/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 How long does it take an automob... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 3: Problem 45

How long does it take an automobile traveling in the left lane of a highway at \(60.0 \mathrm{~km} / \mathrm{h}\) to overtake (become even with) another car that is traveling in the right lane at \(40.0 \mathrm{~km} / \mathrm{h}\) when the cars' front bumpers are initially \(100 \mathrm{~m}\) apart?

Short Answer

Expert verified
It will take approximately 18 seconds for the car travelling at 60 km/h to overtake the car travelling at 40 km/h when they are initially 100 m apart.

Step by step solution

01

Conversion of Units

Firstly, convert the speed of both cars into m/s because they are provided in km/hr and the distance is provided in meters. This can be done using the conversion factor that 1 km/h = \(\frac{5}{18}\) m/s. Thus: Speed of first car = \(60 \times \frac{5}{18}\) m/s = 16.67 m/s. Speed of second car = \(40 \times \frac{5}{18}\) m/s = 11.11 m/s.
02

Calculation of Relative Speed

Find the relative speed by subtracting the speed of the slower car from the speed of the faster car. Thus, relative speed = 16.67 m/s - 11.11 m/s = 5.56 m/s.
03

Calculation of Time Taken

Using the formula time = distance / speed, calculate the time taken by the faster car to cover the distance of 100 meters with respect to the slower car. Thus, time = 100 m / 5.56 m/s = 18 seconds.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A quarterback throws a football toward a receiver with an initial speed of \(20 \mathrm{~m} / \mathrm{s}\) at an angle of \(30^{\circ}\) above the horizontal. At that instant the receiver is \(20 \mathrm{~m}\) from the quarterback. In (a) what direction and (b) with what constant speed should the receiver run in order to catch the football at the level at which it was thrown?

One of the fastest recorded pitches in major-league baseball, thrown by Tim Lincecum in 2009 , was clocked at \(101.0 \mathrm{mi} / \mathrm{h}\) (Fig. P3.22). If a pitch were thrown horizontally with this velocity, how far would the ball fall vertically by the time it reached home plate, \(60.5 \mathrm{ft}\) away?

A novice golfer on the green takes three strokes to sink the ball. The succes- sive displacements of the ball are \(4.00 \mathrm{~m}\) to the north, \(2.00 \mathrm{~m}\) northeast, and \(1.00 \mathrm{~m}\) at \(30.0^{\circ}\) west of south (Fig. P3.21). Starting at the same initial point, an expert golfer could make the hole in what single displacement?

A car is parked on a cliff overlooking the ocean on an incline that makes an angle of \(24.0^{\circ}\) below the horizontal. The negligent driver leaves the car in neutral, and the emergency brakes are defective. The car rolls from rest down the incline with a constant acceleration of \(4.00 \mathrm{~m} / \mathrm{s}^{2}\) for a distance of \(50.0 \mathrm{~m}\) to the edge of the cliff, which is \(30.0 \mathrm{~m}\) above the ocean. Find (a) the car's position relative to the base of the cliff when the car lands in the ocean and (b) the length of time the car is in the air.

A bomber is flying horizontally over level terrain at a speed of \(275 \mathrm{~m} / \mathrm{s}\) relative to the ground and at an altitude of \(3.00 \mathrm{~km}\). (a) The bombardier releases one bomb. How far does the bomb travel horizontally between its release and its impact on the ground? Ignore the effects of air resistance. (b) Firing from the people on the ground suddenly incapacitates the bombardier before he can call, "Bombs away!" Consequently, the pilot maintains the plane's original course, altitude, and speed through a storm of flak. Where is the plane relative to the bomb's point of impact when the bomb hits the ground? (c) The plane has a telescopic bombsight set so that the bomb hits the target seen in the sight at the moment of release. At what angle from the vertical was the bombsight set?
See all solutions

Recommended explanations on Physics Textbooks

Electric Charge Field and Potential

Read Explanation

Mechanics and Materials

Read Explanation

Famous Physicists

Read Explanation

Modern Physics

Read Explanation

Further Mechanics and Thermal Physics

Read Explanation

Classical Mechanics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.