/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 A race car moves such that its p... [FREE SOLUTION] | 91Ó°ÊÓ

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A race car moves such that its position fits the relationship $$ x=(5.0 \mathrm{~m} / \mathrm{s}) t+\left(0.75 \mathrm{~m} / \mathrm{s}^{3}\right) t^{3} $$ where \(x\) is measured in meters and \(t\) in seconds. (a) Plot a graph of the car's position versus time. (b) Determine the instantaneous velocity of the car at \(t=4.0 \mathrm{~s}\), using time intervals of \(0.40 \mathrm{~s}, 0.20 \mathrm{~s}\), and \(0.10 \mathrm{~s}\). (c) Compare the average velocity during the first \(4.0 \mathrm{~s}\) with the results of part (b).

Short Answer

Expert verified
Instantaneous velocity at \(t=4.0s\) using \(v=5+3(0.75)(4.0s)^{2}\) is \(26\ m/s\). The total displacement during the first 4.0s using \(x=(5.0 \mathrm{~m} / \mathrm{s}) t+\left(0.75 \mathrm{~m} / \mathrm{s}^{3}\right) t^{3}\) yields \(x=64m\). Hence, the average velocity during the first 4.0s is \(64m/4.0s=16\ m/s\). The instantaneous velocity is greater than the average velocity indicating speeding up of the car.

Step by step solution

01

Plot the Position-Time Graph

Using the position-time relation given by the equation \(x=(5.0 \mathrm{~m} / \mathrm{s}) t+\left(0.75 \mathrm{~m} / \mathrm{s}^{3}\right) t^{3}\), plot the graph by substituting different values of \(t\) (time in secs) and note corresponding \(x\) (position in meters). The graph can be plotted using any graph plotting software or by hand.
02

Calculate Instantaneous Velocity

Instantaneous velocity can be calculated as the derivative of the position with respect to time or \(v=\dfrac{dx}{dt}\). Differentiating the given equation, yields the velocity-time relationship \(v=5+3(0.75)t^{2}\). Instantaneous velocity can then be calculated by plugging \(t=4.0s\) into this equation.
03

Calculate the Average Velocity

Average velocity is calculated as total displacement over total time. Displacement is calculated by substituting \(t=4.0s\) into the position-time equation, and then divide by the total time which is 4.0s.
04

Comparison

Compare the calculated average velocity and instantaneous velocity at \(t=4.0s\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Position-Time Relationship
To understand motion, one of the first relationships we examine is how position changes over time. This relationship helps us describe an object's trajectory - the path it takes as it moves. It's important to grasp that the position-time graph is a visual representation of an object's journey.

Understanding the Curve

  • If the graph is a straight line, this means the object is moving at a constant speed.
  • If the graph curves, the speed is changing - it's either accelerating or decelerating.
In our exercise, the car's motion is described by a mathematical model, specifically an equation that takes into account basic speed and acceleration: \(x = (5.0 \, \text{m/s})t + (0.75 \, \text{m/s}^3)t^3\). As such, a position-time graph for this would start with a gentle slope that gets steeper over time due to the cubic term in the equation, indicative of an increasing acceleration.
Instantaneous Velocity Calculation
Instantaneous velocity is essentially the speed of an object at a specific moment in time - think of it as the speedometer reading in that instant. To find this, we use calculus, taking the derivative of the position with respect to time.

Calculating Velocity from Position

When we differentiate our car's position-time equation, \(x=(5.0 \, \text{m/s}) t + (0.75 \, \text{m/s}^3)t^3\), we're left with its velocity-time relationship: \(v = 5 + 3(0.75)t^2\). Substituting any value of \(t\), we can then solve for \(v\), finding the speed at that particular second.

For the given exercise, finding the instantaneous velocity at \(t=4.0s\) is just a matter of plugging the number into our velocity equation, resulting in the car's speed at that exact moment.
Average Velocity
The term 'average velocity' figures heavily in introductory physics. It's defined as the total displacement (how far from its starting point an object has moved, regardless of the journey it took) divided by the total time taken to move that distance.

To calculate this, we often use the formula: \( \text{Average Velocity} = \frac{\text{Total Displacement}}{\text{Total Time}} \). In our exercise, by inserting \(t=4.0s\) into the position equation, we get the displacement after 4 seconds, and then dividing by 4 seconds yields the average velocity.

Nuances of Average Velocity

A critical point here is that average velocity can be the same for different types of motion—constant speed, acceleration, or deceleration—as long as the start and endpoints are the same. It does not inform us about what happened in between, which is why instantaneous velocity is also valuable.
Velocity-Time Relationship
Looking at how velocity changes with time tells us a lot about an object's state of motion. The velocity-time graph is particularly insightful as it can show constant velocity (horizontal line), constant acceleration (straight inclined line), or changing acceleration (curved line).

In the context of our race car example, we found the velocity-time relationship to be non-linear, due to the \(t^2\) term in the equation: \(v = 5 + 3(0.75)t^2\). This equation tells us that the car's acceleration isn't constant; it's increasing over time.

Implications for Motion

Such a relationship implies that the car is not simply speeding up at a steady rate; rather, the rate at which it's speeding up is itself increasing. If plotted, the velocity-time graph would curve upwards, getting steeper as time progresses, indicating a gain in acceleration, culminating in a higher final velocity for the car.

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Most popular questions from this chapter

Two cars travel in the same direction along a straight highway, one at a constant speed of \(55 \mathrm{mi} / \mathrm{h}\) and the other at \(70 \mathrm{mi} / \mathrm{h}\). (a) Assuming they start at the same point, how much sooner does the faster car arrive at a destination \(10 \mathrm{mi}\) away? (b) How far must the faster car travel before it has a 15 -min lead on the slower car?

A speedboat moving at \(30.0 \mathrm{~m} / \mathrm{s}\) approaches a no-wake buoy marker \(100 \mathrm{~m}\) ahead. The pilot slows the boat with a constant acceleration of \(-3.50 \mathrm{~m} / \mathrm{s}^{2}\) by reducing the throttle. (a) How long does it take the boat to reach the buoy? (b) What is the velocity of the boat when it reaches the buoy?

A car starts from rest and travels for \(t_{1}\) seconds with a uniform acceleration \(a_{1} .\) The driver then applies the brakes, causing a uniform acceleration \(a_{2}\). If the brakes are applied for \(t_{2}\) seconds, (a) how fast is the cas going just before the beginning of the braking period: (b) How far does the car go before the driver begins to brake? (c) Using the answers to parts (a) and (b) as the initial velocity and position for the motion of the ca during braking, what total distance does the car travel Answers are in terms of the variables \(a_{1}, a_{2}, t_{1}\), and \(t_{2}\).

BIO Colonel John P. Stapp, USAF, participated in studying whether a jet pilot could survive emergency ejection. On March 19,1954 , he rode a rocketpropelled sled that moved down a track at a speed of \(632 \mathrm{mi} / \mathrm{h}\) (see Fig. P2.56). He and the sled were safely brought to rest in \(1.40 \mathrm{~s}\). Determine in SI units (a) the negative acceleration he experienced and (b) the distance he traveled during this negative acceleration.

S An athlete swims the length \(L\) of a pool in a time \(t_{1}\) and makes the return trip to the starting position in a time \(t_{2}\). If she is swimming initially in the positive \(x\)-direction, determine her average velocities symbolically in (a) the first half of the swim, (b) the second half of the swim, and (c) the round trip. (d) What is her average speed for the round trip?

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