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The elastic limit of a piece of steel wire is \(2.70 \times 10^{9} \mathrm{~Pa}\). What is the maximum speed at which transverse wave pulses can propagate along the wire without exceeding its elastic limit? (The density of steel is \(7.86 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\).)

Short Answer

Expert verified
Maximum transverse wave speed in the steel wire without exceeding the elastic limit is approximately 1862.6 m/s.

Step by step solution

01

Identify given quantities

We are given the elastic limit of steel, \( \sigma = 2.7 \times 10^{9} \, \mathrm{Pa} \), and the density of steel, \( \rho = 7.86 \times 10^{3} \, \mathrm{kg/m^3} \). These values act as stress and density in the wave speed formula.
02

Substitute for \( v \) in wave speed formula

Now, we need to substitute these values into the wave speed formula \( v = \sqrt{\frac{\sigma}{\rho}} \). This gives us \( v = \sqrt{\frac{2.7 \times 10^{9} \, \mathrm{Pa}}{7.86 \times 10^{3} \, \mathrm{kg/m^3}}} \).
03

Calculate the wave speed

By solving this calculation, we obtain the wave speed \( v \). This is the maximum speed at which transverse wave pulses can propagate along the wire without exceeding its elastic limit.

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