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A \(65-\mathrm{g}\) ice cube is initially at \(0.0^{\circ} \mathrm{C}\). (a) Find the change in entropy of the cube after it melts completely at \(0.0^{\circ} \mathrm{C}\). (b) What is the change in entropy of the environment in this process? Hint: The latent heat of fusion for water is \(3.33 \times 10^{5} \mathrm{~J} / \mathrm{kg}\).

Short Answer

Expert verified
The change in entropy of the ice cube after it melts completely at 0.0°C is 79.2 J/K. The change in entropy of the environment in this process is -79.2 J/K.

Step by step solution

01

Calculate the heat transferred

First, we need to calculate the heat transferred in the process of melting. Because this process occurs at a constant temperature, we can use the latent heat of fusion (L) to calculate this. The formula to use is: \( Q = mL \), where m is the mass of the ice cube and L is the latent heat of fusion. So, for our exercise: \( Q = 0.065\,\mathrm{kg} \times 3.33 \times 10^{5} \,\mathrm{J/kg} = 21645 \,\mathrm{J} \).
02

Calculate the change in entropy for the ice cube

Next, we will calculate the change in entropy for the ice cube. As mentioned above, we use the formula \(\Delta S = \frac{Q}{T}\), where T is the absolute temperature. Beware that temperature must always be in Kelvin when calculating entropy. In our case, the given temperature is 0.0° C = 273.15K. So, the change in entropy for the ice cube is: \( \Delta S = \frac{21645\,\mathrm{J}}{273.15\,\mathrm{K}} = 79.2\,\mathrm{J/K} \).
03

Calculate the change in entropy for the environment

Lastly, we need to calculate the change in entropy of the surroundings. The heat transferred to the ice cube from the environment is exactly the amount the environment loses. Therefore, the heat transferred from the environment is negative. Hence: \( \Delta S = \frac{-Q}{T} = \frac{-21645\,\mathrm{J}}{273.15\,\mathrm{K}} = -79.2\,\mathrm{J/K} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Latent Heat of Fusion
The latent heat of fusion is a crucial concept in understanding phase change, particularly the transformation from a solid state to a liquid state. It refers to the amount of energy needed to change the state of a substance, like ice, into a liquid, like water, without altering its temperature. For water, the latent heat of fusion is approximately 333,000 joules per kilogram (J/kg).

In our textbook exercise, the latent heat of fusion enables us to calculate the energy absorbed by a melting ice cube. To convert the 65-gram ice cube into water at the same temperature, we multiply its mass by the latent heat of fusion given for water. This energy is not lost; it is stored as potential energy, enabling the molecules in the ice to overcome the forces holding them together in a solid form. Understanding this concept helps clarify the energy transfer involved during phase changes.
Thermodynamics
Thermodynamics is the branch of physics that deals with the relationships between heat and other forms of energy. In our problem, thermodynamics principles are applied to calculate the entropy change, which is a measure of the disorder or randomness within a system. Entropy is a core idea in thermodynamics and can be tricky to grasp because it's not as tangible as other thermal properties like temperature or pressure.

When the ice cube melts, its entropy increases because the molecules move from a well-ordered solid structure to a more disordered liquid state. The increase in entropy is quantified using the formula \(\Delta S = \frac{Q}{T}\), where \(\Delta S\) is the entropy change, \(Q\) is the heat transfer, and \(T\) is the absolute temperature in Kelvin. Thermodynamic principles assert that in an isolated system, the entropy remains constant or increases over time, which corresponds to the Second Law of Thermodynamics.
Heat Transfer
The concept of heat transfer is central to the exercise when discussing the entropy change of the ice cube and its surroundings. Heat transfer refers to the movement of thermal energy from one thing to another due to a temperature difference. It's essential to note that heat moves spontaneously from hotter to colder objects until thermal equilibrium is achieved.

During the ice cube's melting process, the surrounding environment transfers heat to the ice, which is why the cube melts. The environment's temperature drops slightly as the ice cube's temperature remains constant at 0.0°C, that it, until it melts completely. This interaction is also a great example of how the concepts of thermodynamics and heat transfer interplay with one another to describe physical processes in our everyday lives.

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