/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 What is the average kinetic ener... [FREE SOLUTION] | 91Ó°ÊÓ

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What is the average kinetic energy of a molecule of oxygen at a temperature of \(300 \mathrm{~K}\) ?

Short Answer

Expert verified
The average kinetic energy of a molecule of oxygen at a temperature of 300 K is \(6.21 \times 10^{-21} J\).

Step by step solution

01

Identify Known Values

In this case, the known values are the Boltzmann constant (\(k = 1.38 \times 10^{-23} J/K\)) and the temperature (\(T = 300 K\)).
02

Insert Values into The Equation

Insert these values into the equation for the average kinetic energy. So we have \(KE = \frac{3}{2} \times 1.38 \times 10^{-23} J/K \times 300 K\).
03

Solve the Equation

Multiply the values together to find the average kinetic energy per molecule. After calculation, the result is \(6.21 \times 10^{-21} J\).

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Most popular questions from this chapter

\(M\) The active element of a certain laser is made of a glass rod \(30.0 \mathrm{~cm}\) long and \(1.50 \mathrm{~cm}\) in diameter. Assume the average coefficient of linear expansion of the glass is \(9.00 \times 10^{-6}\left({ }^{\circ} \mathrm{C}\right)^{-1}\). If the temperature of the rod increases by \(65.0^{\circ} \mathrm{C}\), what is the increase in (a) its length, (b) its diameter, and (c) its volume?

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In a period of \(1.0 \mathrm{~s}, 5.0 \times 10^{23}\) nitrogen molecules strike a wall of area \(8.0 \mathrm{~cm}^{2}\). If the molecules move at \(300 \mathrm{~m} / \mathrm{s}\) and strike the wall head-on in a perfectly elastic collision, find the pressure exerted on the wall. (The mass of one \(\mathrm{N}_{2}\) molecule is \(4.68 \times 10^{-26} \mathrm{~kg}\).)

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