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Newton's law of universal gravitation is represented by $$ F=G \frac{M m}{r^{2}} $$ where \(F\) is the gravitational force, \(M\) and \(m\) are masses, and \(r\) is a length. Force has the SI units \(\mathrm{kg} \cdot \mathrm{m} / \mathrm{s}^{2}\). What are the SI units of the proportionality constant \(G\) ?

Short Answer

Expert verified
The SI units of the proportionality constant (G) are \(m^3/(kg.s^2)\).

Step by step solution

01

Understand the given equation

Firstly, recognizing and affirming the components of the given equation is crucial. The law of universal gravitation as presented by Sir Isaac Newton is, \(F = G\frac{Mm}{r^2}\) where F signifies the gravitational force, M and m refer to masses, and r is a length. The SI units of force, mass, and distance are kilogram meter per second squared \((kg.m/s^2)\), kilogram \((kg)\), and meter \((m)\), respectively.
02

Rearrange the equation and isolate G

The next task is to get G isolated. This will help us easily find the SI unit of G. By rearranging the equation, we obtain \(G = \frac{F.r^2}{M.m}\).
03

Substitute known units into the rearranged equation

Replace all the known units into the rearranged equation. That gives us, \(G = \frac{(kg.m/s^2).(m^2)}{kg.kg}\).
04

Simplify the units

After substitution, simplifying the units, would provide the SI unit for the gravitational constant G. Thus simplifying, we get G as \(m^3/(kg.s^2)\).
05

Document the SI units of G

Finally, denote G's SI units as found in Step 4. The SI units of the proportionality constant G are \(m^3/(kg.s^2)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's law of universal gravitation
Newton's law of universal gravitation is a cornerstone of physics. It's a fundamental principle to understand how masses interact through the force of gravity. Newton proposed that every particle of matter in the universe attracts every other particle with a force. This force is proportional to the product of their masses and inversely proportional to the square of the distance between their centers. This idea is mathematically captured through the equation:
\[ F = G \frac{M m}{r^2} \]
Here, \(F\) is the gravitational force between the masses \(M\) and \(m\), separated by a distance \(r\), while \(G\) is the gravitational constant, a unique value that orders the scale of the force. By understanding this equation, one can predict and measure the gravitational attraction between objects, whether they be as immense as planets or as minuscule as atoms.
SI units
SI units, also known as the International System of Units, provide a standard for measurements worldwide. This system ensures that scientific and engineering work remains consistent across various fields and regions. When dealing with Newton's law, key SI units come into play:
  • Force (\(F\)): measured in newtons (N), which is equivalent to \(kg \cdot m/s^2\).
  • Mass (\(M\) and \(m\)): measured in kilograms (kg).
  • Distance (\(r\)): measured in meters (m).
By using these standardized measurements, one can apply the principles of gravitational force consistently, ensuring accurate scientific communication and calculations globally. Ensuring familiarity with these units helps in easily converting, comparing, and solving problems in physics.
Gravitational force
Gravitational force is the attractive force acting between any two masses due to their mass. It's one of the four fundamental forces of nature. While it is the weakest of the fundamental forces, its range is infinite, and it plays a crucial role at astronomical scales, governing the motion of planets, stars, and galaxies.
The strength of the gravitational force follows the inverse square law, where it diminishes with the square of the distance between the masses. This nature is critical for understanding phenomena ranging from why things fall to the ground, to the orbits of planets in our solar system. In the equation \(F = G\frac{Mm}{r^2}\), \(F\) denotes the gravitational force, a central focus when studying gravity and motion. Understanding its calculations helps in predicting how objects influence one another through gravity.
Proportionality constant
The proportionality constant in Newton's gravitational equation is the gravitational constant \(G\). This constant ensures that the equation correctly scales the gravitational forces to real-world values. The value of \(G\) is approximately \(6.674 \times 10^{-11} \text{ m}^3 \text{ kg}^{-1} \text{ s}^{-2}\).
The SI units for \(G\) can be derived by rearranging Newton's equation and solving for \(G\). Upon doing so, we find:
\[ G = \frac{F \cdot r^2}{M \cdot m} \]
Substituting the known SI units, \(F = \text{kg} \cdot \text{m/s}^2\), \(r = \text{m}\), and \(M\) and \(m\) in kg, leads us to:
\[ G = \frac{\text{kg} \cdot \text{m/s}^2 \cdot \text{m}^2}{\text{kg} \cdot \text{kg}} = \text{m}^3/ (\text{kg} \cdot \text{s}^2) \]
This unit ensures that no matter the masses or distance, using \(G\) maintains consistency in the gravitational force calculations, an essential factor in physics and our understanding of celestial and earthly movements.

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Most popular questions from this chapter

A woman measures the angle of elevation of a mountaintop as \(12.0^{\circ}\). After walking \(1.00 \mathrm{~km}\) closer to the mountain on level ground, she finds the angle to be \(14.0^{\circ}\). (a) Draw a picture of the problem, neglecting the height of the woman's eyes above the ground. Hint: Use two triangles. (b) Select variable names for the mountain height (suggestion: \(y\) ) and the woman's original distance from the mountain (suggestion: \(x\) ) and label the picture. (c) Using the labeled picture and the tangent function, write two trigonometric equations relating the two selected variables. (d) Find the height \(y\) of the mountain by first solving one equation for \(x\) and substituting the result into the other equation.

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