/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 57 A passenger bus in Zurich, Switz... [FREE SOLUTION] | 91Ó°ÊÓ

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A passenger bus in Zurich, Switzerland, derived its motive power from the energy stored in a large flywheel. Whenever the bus was stopped at a station, the wheel was brought up to speed with the use of an electric motor that could then be attached to the electric power lines. The flywheel was a solid cylinder with a mass of \(1000 \mathrm{~kg}\) and a diameter of \(1.80 \mathrm{~m} ;\) its top angular speed was \(3000 \mathrm{rev} / \mathrm{min} .\) At this angular speed, what was the kinetic energy of the flywheel?

Short Answer

Expert verified
The kinetic energy of the flywheel is 20,000,000 J (20 MJ).

Step by step solution

01

Calculate the Moment of Inertia

The moment of inertia for a solid cylinder is given by \( I = \frac{1}{2} M R^2 \), where \( M \) is the mass and \( R \) is the radius. The radius \( R \) is half of the diameter, so \( R = 0.90 \text{ m} \). Thus, the moment of inertia is \( I = \frac{1}{2} \times 1000 \text{ kg} \times (0.90 \text{ m})^2 = 405 \text{ kg} \cdot \text{m}^2 \).
02

Convert Angular Speed to Radians per Second

The angular speed is given in revolutions per minute (\( \mathrm{rev} / \min \)) and must be converted to radians per second (\( \mathrm{rad} / \sec \)). Using the conversion factors \( 1 \mathrm{rev} = 2\pi \mathrm{rad} \) and \( 1 \min = 60 \seconds \), we have: \( \omega = 3000 \mathrm{rev} / \mathrm{min} \times \frac{2\pi \mathrm{rad}}{1\mathrm{rev}} \times \frac{1 \mathrm{min}}{60 \mathrm{sec}} = 314.16 \mathrm{rad} / \mathrm{sec} \).
03

Calculate the Kinetic Energy

The kinetic energy of a rotating object is given by \( KE = \frac{1}{2} I \omega^2 \), where \( \omega \) is the angular speed in radians per second. Substitute in the values: \( KE = \frac{1}{2} \times 405 \text{ kg} \cdot \text{m}^2 \times (314.16 \mathrm{rad} / \mathrm{sec})^2 = 20,000,000 \text{ J} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Flywheel Energy Storage
Flywheel energy storage is a clever method for storing and retrieving energy. Imagine the flywheel as a heavy spinning disk that can store kinetic energy through its rotation. This energy can be released when needed to power systems, like the Zurich bus. The key advantage of using flywheels is their ability to quickly release energy, which makes them highly useful in applications requiring frequent start and stop cycles. Some benefits of flywheel energy storage include:
  • High power output: They rapidly deliver stored energy.
  • Long lifecycle: They can withstand countless cycles without performance degradation.
  • No toxic chemicals: Unlike batteries, flywheels do not involve harmful materials.
In the context of the bus in Zurich, the flywheel stored energy when the bus was charged at stations. By doing so, it allowed the bus to travel between stations without using any direct power from electrical lines. This is not only environmentally friendly but also efficient in reducing the need for constant energy input from external sources.
Moment of Inertia
The moment of inertia is a fundamental concept in understanding the rotational dynamics of objects. It describes how the mass of an object is distributed relative to the axis of rotation. Think of it as a rotational equivalent of mass in linear motion. For the flywheel, which is a solid cylinder, the moment of inertia (I) helps determine how much torque is needed to change its angular speed.The formula for the moment of inertia of a solid cylinder is:\[ I = \frac{1}{2} M R^2 \]where \( M \) is the mass and \( R \) is the radius. In our case, the mass is 1000 kg and the radius is 0.90 meters (half of the diameter). Thus, the calculation of \( I \) becomes straightforward:\[ I = \frac{1}{2} \times 1000 \times (0.90)^2 = 405 \text{ kg} \cdot \text{m}^2 \] Understanding this concept is crucial because it influences how the flywheel behaves under different forces. A larger moment of inertia means the flywheel is harder to accelerate or decelerate, impacting how effectively the energy is stored or released.
Angular Speed Calculation
Angular speed describes how quickly an object rotates. In this context, it's crucial to convert angular speed into the correct units to calculate kinetic energy correctly. The given angular speed was 3000 revolutions per minute, but to use it in equations effectively, we need it in radians per second.Radians are used because they provide a direct measure of an angle in relation to the radius of a circle, making calculations involving circles very straightforward. The conversion process involves:
  • 1 revolution = \(2\pi\) radians
  • 1 minute = 60 seconds
To get the angular speed in radians per second, the conversion goes as follows:\[ \omega = 3000 \times \frac{2\pi}{1} \times \frac{1}{60} = 314.16 \text{ rad/s} \]This conversion is crucial as the kinetic energy formula requires angular speed in radians per second for accurate results. A proper understanding here ensures that calculations regarding the flywheel's stored energy are both correct and efficient.

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Most popular questions from this chapter

A uniform marble rolls down a symmetric bowl, starting from rest at the top of the left side. The top of each side is a distance \(h\) above the bottom of the bowl. (a) How far up the right side of the bowl will the marble go if the interior surface of the bowl is rough so that the marble rolls without slipping? (b) How high would the marble go if the bowl's surface were frictionless? (c) For which case is the marble moving faster when it reaches the bottom of the bowl?

The spin cycles of a washing machine have two angular speeds, 423 rev \(/ \mathrm{min}\) and \(640 \mathrm{rev} / \mathrm{min} .\) The internal diameter of the drum is \(0.470 \mathrm{~m}\). (a) What is the ratio of the maximum radial force on the laundry for the higher angular speed to that for the lower speed? (b) What is the ratio of the maximum tangential speed of the laundry for the higher angular speed to that for the lower speed? (c) Find the laundry's maximum tangential speed and the maximum radial acceleration, in terms of \(g\).

A curve ball is a type of pitch in which the baseball spins on its axis as it heads for home plate. If a curve ball is thrown at \(35.8 \mathrm{~m} / \mathrm{s}\) (80 mph) with a spin rate of 30 rev \(/\) s, how many revolutions does it complete before reaching home plate? Assume that home plate is \(18.3 \mathrm{~m}(60 \mathrm{ft})\) from the pitching mound and that the baseball travels at a constant velocity.

A car is traveling at a speed of \(101 \mathrm{~km} / \mathrm{h}\) on the highway and has a small stone stuck between the treads of one of its tires. The tires have diameter \(61.0 \mathrm{~cm}\) and are rolling without sliding or slipping. What are (a) the maximum and (b) the minimum speeds of the stone as observed by a pedestrian standing on the side of the highway?

The flywheel of a gasoline engine is required to give up 500 \(\mathrm{J}\) of kinetic energy while its angular velocity decreases from 650 rev \(/\) min to 520 rev \(/\) min. What moment of inertia is required?

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