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A wheel rotates with a constant angular velocity of \(6.00 \mathrm{rad} / \mathrm{s}\) (a) Compute the radial acceleration of a point \(0.500 \mathrm{~m}\) from the axis, using the relation \(a_{\mathrm{rad}}=\omega^{2} r .(\mathrm{b})\) Find the tangential speed of the point, and compute its radial acceleration from the relation \(a_{\mathrm{rad}}=v^{2} / r\)

Short Answer

Expert verified
The radial acceleration is \( 18.0 \, \text{m/s}^2 \) and the tangential speed is \( 3.00 \, \text{m/s} \).

Step by step solution

01

Identify the Given Values

We start by identifying the values provided in the problem. The angular velocity \( \omega \) is given as \( 6.00 \, \text{rad/s} \) and the radial distance \( r \) is \( 0.500 \, \text{m} \).
02

Calculate the Radial Acceleration with Angular Velocity

To find the radial acceleration using the given relation \( a_{\text{rad}} = \omega^2 r \), substitute \( \omega = 6.00 \, \text{rad/s} \) and \( r = 0.500 \, \text{m} \):\[ a_{\text{rad}} = (6.00)^2 \times 0.500 \]\[ a_{\text{rad}} = 36 \times 0.500 \]\[ a_{\text{rad}} = 18.0 \, \text{m/s}^2 \]
03

Compute the Tangential Speed

The tangential speed \( v \) can be found using the formula \( v = \omega r \). Substitute the values of \( \omega \) and \( r \):\[ v = 6.00 \times 0.500 \]\[ v = 3.00 \, \text{m/s} \]
04

Calculate the Radial Acceleration with Tangential Speed

Using the tangential speed, compute the radial acceleration with the formula \( a_{\text{rad}} = \frac{v^2}{r} \):\[ a_{\text{rad}} = \frac{3.00^2}{0.500} \]\[ a_{\text{rad}} = \frac{9.00}{0.500} \]\[ a_{\text{rad}} = 18.0 \, \text{m/s}^2 \]
05

Verify Consistency

Both methods for calculating radial acceleration produced the same result: \( 18.0 \, \text{m/s}^2 \). This confirms that the calculations are consistent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radial Acceleration
Radial acceleration is a key component in understanding the motion of objects in a circular path. It is also known as centripetal acceleration because it points towards the center of the circle around which the object moves. The formula to calculate radial acceleration is given by \( a_{\text{rad}} = \omega^2 r \), where \( \omega \) represents the angular velocity and \( r \) is the radial distance from the axis of rotation. In a real-world scenario, if you're spinning a wheel, any point on the rim would have a radial acceleration directed towards the center of the wheel. This acceleration is responsible for keeping the object moving in a circle. Without it, the object would move off in a straight line due to inertia.To calculate this in the exercise, we substitute the values provided: \( \omega = 6.00 \; \text{rad/s} \) and \( r = 0.500 \; \text{m} \). The calculation ensures that the radial acceleration, \( a_{\text{rad}} \), is 18.0 m/s², confirming the consistent force towards the center as the wheel rotates.
Tangential Speed
Tangential speed refers to the linear speed of a point located at a certain distance from the axis of rotation. It is different from angular velocity, which describes how fast something rotates. Tangential speed is given by the formula \( v = \omega r \), linking the rotation speed (\( \omega \)) with the radius (\( r \)).For instance, on a rotating wheel, the point on the rim that is 0.500m from the center has a tangential speed determined by its radial position multiplied by the angular velocity of the wheel. In the exercise, substituting the given values, \( v \) is calculated as 3.00 m/s, indicating how fast a point on the rim of the wheel moves along its circular path. This speed is important for understanding motions such as rolling wheels or rotating fans.
Constant Angular Velocity
Constant angular velocity means an object maintains the same rate of rotation over time. It’s measured in radians per second (rad/s), symbolized by \( \omega \). When angular velocity is constant, each point on a rotating object moves at a constant speed along its circular path, but for such a point, the direction changes continuously.In practical terms, let's consider a ceiling fan spinning at a constant speed. Each blade moves with constant angular velocity, maintaining uniform rotations per minute. This ensures consistent airflow in a room.In the context of the exercise, the wheel spins with a constant angular velocity of 6.00 rad/s. This constancy gives us a stable measure to compute both the tangential speed and radial acceleration, showing that all necessary forces and motions remain consistent.
Physics Problems
Physics problems involving angular motion often require understanding concepts like radial acceleration, tangential speed, and constant angular velocity. These topics are essential for solving real-world scenarios involving circular motion, such as those concerning car tires, amusement park rides, or planetary orbits.To tackle such problems efficiently:
  • Identify and write down all given values clearly.
  • Know the right formulas, such as \( a_{\text{rad}} = \omega^2 r \) or \( v = \omega r \), which link angular motion concepts.
  • Ensure unit consistency across all data and answers.
  • Be methodical, solving step by step to avoid errors and confirm calculations as done in the exercise.
With patience and practice, physics problems can turn into intuitive solutions, making complex systems easier to handle.

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Most popular questions from this chapter

A wagon wheel is constructed as shown in Figure \(9.31 .\) The radius of the wheel is \(0.300 \mathrm{~m}\), and the rim has a mass of \(1.40 \mathrm{~kg}\). Each of the wheel's eight spokes, which come out from the center and are 0.300 m long, has a mass of \(0.280 \mathrm{~kg}\). What is the moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel?

The spin cycles of a washing machine have two angular speeds, 423 rev \(/ \mathrm{min}\) and \(640 \mathrm{rev} / \mathrm{min} .\) The internal diameter of the drum is \(0.470 \mathrm{~m}\). (a) What is the ratio of the maximum radial force on the laundry for the higher angular speed to that for the lower speed? (b) What is the ratio of the maximum tangential speed of the laundry for the higher angular speed to that for the lower speed? (c) Find the laundry's maximum tangential speed and the maximum radial acceleration, in terms of \(g\).

The once-popular LP (long-play) records were 12 in. in diameter and turned at a constant \(33 \frac{1}{3} \mathrm{rpm} .\) Find (a) the angular speed of the LP in rad \(/ \mathrm{s}\) and \((\mathrm{b})\) its period in seconds.

A curve ball is a type of pitch in which the baseball spins on its axis as it heads for home plate. If a curve ball is thrown at \(35.8 \mathrm{~m} / \mathrm{s}\) (80 mph) with a spin rate of 30 rev \(/\) s, how many revolutions does it complete before reaching home plate? Assume that home plate is \(18.3 \mathrm{~m}(60 \mathrm{ft})\) from the pitching mound and that the baseball travels at a constant velocity.

A turntable that spins at a constant 78.0 rpm takes \(3.50 \mathrm{~s}\) to reach this angular speed after it is turned on. Find (a) its angular acceleration (in rad \(/ \mathrm{s}^{2}\) ), assuming it to be constant, and (b) the number of degrees it turns through while speeding up.

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