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A circular saw blade \(0.200 \mathrm{~m}\) in diameter starts from rest. In 6.00 s, it reaches an angular velocity of \(140 \mathrm{rad} / \mathrm{s}\) with constant angular acceleration. Find the angular acceleration and the angle through which the blade has turned in this time.

Short Answer

Expert verified
The angular acceleration is approximately \( 23.33\, \text{rad/s}^2 \) and the angular displacement is approximately \( 419.94\, \text{rad} \).

Step by step solution

01

Identify known values

We are given: the initial angular velocity \( \omega_0 = 0\, \text{rad/s} \), the final angular velocity \( \omega = 140\, \text{rad/s} \), the time \( t = 6.00\, \text{s} \), and the diameter of the blade, which isn't needed directly for these calculations. We need to find the angular acceleration \( \alpha \) and the angle \( \theta \) through which the blade has turned.
02

Write the formula for angular acceleration

The formula for angular acceleration \( \alpha \) when the initial and final angular velocities are known is: \( \alpha = \frac{\omega - \omega_0}{t} \).
03

Calculate angular acceleration

Substitute the given values into the formula: \( \alpha = \frac{140\, \text{rad/s} - 0}{6.00\, \text{s}} = \frac{140}{6}\, \text{rad/s}^2 \). Performing the division gives: \( \alpha \approx 23.33\, \text{rad/s}^2 \).
04

Write the formula for angular displacement

The formula for angular displacement \( \theta \) when starting from rest with constant angular acceleration is: \( \theta = \omega_0 t + \frac{1}{2} \alpha t^2 \). Since the initial angular velocity is zero, the equation simplifies to \( \theta = \frac{1}{2} \alpha t^2 \).
05

Calculate angular displacement

Substitute \( \alpha \approx 23.33\, \text{rad/s}^2 \) and \( t = 6.00\, \text{s} \) into the formula: \( \theta = \frac{1}{2} \times 23.33 \times (6.00)^2 \). Calculating this gives: \( \theta = \frac{1}{2} \times 23.33 \times 36 \approx 419.94\, \text{rad} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Acceleration
Angular acceleration (\( \alpha \)) is a measure of how quickly the angular velocity of an object changes with time. Think of it as how fast something is spinning up or slowing down. Angular acceleration is particularly important when something starts moving from a state of rest or when its speed changes over time like our circular saw blade example.

In the given exercise, the concept of angular acceleration is used to determine how quickly the saw blade reaches its designated speed. This can be calculated using the formula:
  • \( \alpha = \frac{\omega - \omega_0}{t} \)
Where:
  • \( \omega \): Final angular velocity
  • \( \omega_0 \): Initial angular velocity
  • \( t \): Time taken to reach the final angular velocity
For the circular saw, we substituted the given values into the formula and calculated that the angular acceleration is approximately \( 23.33 \, \text{rad/s}^2 \). This tells us that the blade's spinning speed increases rapidly until it reaches 140 rad/s in just 6 seconds.
Angular Velocity
Angular velocity (\( \omega \)) describes how quickly something is rotating. It's like the speedometer for rotational motion. If you could see how fast a clock's hands move, that would be its angular velocity.

In the problem about the saw blade, the angular velocity is what we measure to understand how quickly it reaches its top speed. It is measured in radians per second (rad/s). Initially, the saw blade starts at rest, which means its initial angular velocity (\( \omega_0 \)) is 0 rad/s.

The final angular velocity is given as 140 rad/s. Angular velocity evolves with time under the effect of angular acceleration, and in continuous movement like this, the velocity is what decides how much the blade will turn in a given time frame. Angular velocity, therefore, acts as a crucial middle step between just having a stationary blade and it moving through a specific angle.
Angular Displacement
Angular displacement (\( \theta \)) refers to the angle through which an object has rotated in a specific time period. Imagine the path traced by the blade's edge as it spins—angular displacement is essentially the angle of that arc over time.

In the example, we calculate the angular displacement to find out how much the blade has turned during the time it's accelerating. The formula used is:
  • \( \theta = \omega_0 t + \frac{1}{2} \alpha t^2 \)
Since the saw blade started from rest, the formula simplifies to:
  • \( \theta = \frac{1}{2} \alpha t^2 \)
By plugging in the angular acceleration (\( \alpha \approx 23.33 \, \text{rad/s}^2 \)) and time (\( t = 6.00 \, \text{s} \)), we find the angular displacement to be approximately 419.94 radians. This reflects the total angle covered by the blade in 6 seconds while it speeds up.

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Most popular questions from this chapter

If a wheel \(212 \mathrm{~cm}\) in diameter takes \(2.25 \mathrm{~s}\) for each revolution, find its (a) period and (b) angular speed in rad/s.

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