/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 A curving freeway exit has a rad... [FREE SOLUTION] | 91Ó°ÊÓ

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A curving freeway exit has a radius of \(50.0 \mathrm{~m}\) and a posted speed limit of \(35 \mathrm{mi} / \mathrm{h}\). What is your radial acceleration (in \(\mathrm{m} / \mathrm{s}^{2}\) ) if you take this exit at the posted speed? What if you take the exit at a speed of \(50 \mathrm{mi} / \mathrm{h} ?\)

Short Answer

Expert verified
At 35 mi/h, the radial acceleration is 4.89 m/s²; at 50 mi/h, it is 9.99 m/s².

Step by step solution

01

Convert Speed Limit to Meters per Second

First, convert the speed from miles per hour to meters per second. The posted speed limit is \(35 \text{ mi/h}\). To convert to \(\text{m/s}\), use the conversion factor: 1 mile per hour is approximately \(0.44704 \text{ m/s}\). Therefore, \(35 \text{ mi/h} \times 0.44704 = 15.6464 \text{ m/s}\).
02

Calculate Radial Acceleration at Posted Speed

Radial acceleration can be calculated using the formula \( a_r = \frac{v^2}{r} \), where \(v\) is the speed in meters per second and \(r\) is the radius in meters. Using the posted speed: \( a_r = \frac{(15.6464)^2}{50.0} = 4.89 \text{ m/s}^2 \).
03

Convert Second Speed to Meters per Second

Convert the second speed of \(50 \text{ mi/h}\) to meters per second. Using the conversion factor: \(50 \text{ mi/h} \times 0.44704 = 22.352 \text{ m/s}\).
04

Calculate Radial Acceleration at Second Speed

Use the same radial acceleration formula for the second speed: \( a_r = \frac{(22.352)^2}{50.0} = 9.99 \text{ m/s}^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Circular Motion
Imagine driving on a circular track. This is a typical example of circular motion. When a car moves along a curve, it is constantly changing direction. Even though the speed might remain the same, the vehicle experiences an acceleration due to this change in direction. This is known as radial or centripetal acceleration. Radial acceleration is always directed towards the center of the circle that the object is moving around.
  • It keeps the vehicle or object following its curved path.
  • The formula for radial acceleration is given by \( a_r = \frac{v^2}{r} \), where \(v\) is speed and \(r\) is the radius of the curve.
Understanding this is crucial because it helps explain why vehicles have a maximum safe speed to navigate curves without skidding off the road. If the speed exceeds this limit, the radial force can become too weak to keep the vehicle on its path, leading to accidents.
Mastering Speed Conversion
When dealing with speed in physics problems, different units can often complicate calculations. In many cases, speed is measured in miles per hour (mi/h) but needs to be converted into meters per second (m/s) for physical calculations in science and engineering.
This is important because:
  • All the SI unit calculations, like those for radial acceleration, require speed in meters per second.
  • Unit conversion ensures consistency and accuracy in problem-solving.
To convert speeds from mi/h to m/s, use the conversion factor where 1 mi/h equals about 0.44704 m/s. For example, to convert 35 mi/h: \(35 \times 0.44704 = 15.6464 \) m/s.
This process might seem simple, but it is critical in ensuring the accuracy of subsequent calculations, particularly when safety and precision are at stake.
Approaching Physics Problem Solving
Tackling physics problems, like the calculation of radial acceleration, requires a clear strategy. First, understand the terms and variables involved. Identify what you know and what you need to find.
In the context of radial acceleration problems:
  • Recognize the formula needed: in this case, \( a_r = \frac{v^2}{r} \).
  • Translate given information into necessary units (e.g., convert speeds to m/s).
From there, plug the values into your formula.
It is critical to double-check each step:
  • Verify calculations for unit conversions.
  • Ensure clarity in your mathematical operations.
Following a structured approach in physics not only helps solve the problem but also builds confidence in handling more complex problems in future studies.
Exploring the Basics of Kinematics
Kinematics is the branch of physics that deals with the motion of objects without considering the causes of that motion. Within kinematics, understanding different kinds of motion, such as circular motion, is fundamental.
Key aspects of kinematics include:
  • Defining different types of motion (linear, circular, etc.).
  • Analyzing velocity and acceleration in any motion type.
Circular motion, like in our problem, requires thinking about how acceleration works when speed and direction constantly change.
This aspect of kinematics allows us to predict object behavior in complex motion, such as vehicles turning on curved paths. The predictive power of kinematics is vital in everything from road safety to designing thrill rides at amusement parks.

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Most popular questions from this chapter

The froghopper, Philaenus spumarius, holds the world record for insect jumps. When leaping at an angle of \(58.0^{\circ}\) above the horizontal, some of the tiny critters have reached a maximum height of \(58.7 \mathrm{~cm}\) above the level ground. (See Nature, Vol. 424,31 July \(2003,\) p. \(509 .\) ) (a) What was the takeoff speed for such a leap? (b) What horizontal distance did the froghopper cover for this world-record leap?

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