/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 A daring swimmer dives off a cli... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A daring swimmer dives off a cliff with a running horizontal leap, as shown in Figure \(3.35 .\) What must her minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom, which is \(1.75 \mathrm{~m}\) wide and \(9.00 \mathrm{~m}\) below the top of the cliff?

Short Answer

Expert verified
Minimum speed is approximately 1.30 m/s.

Step by step solution

01

Understanding the Problem

The swimmer dives off a cliff horizontally and must avoid hitting a ledge that is 1.75 meters wide and 9.00 meters below the top.
02

Determine Time of Fall

First, find the time it takes for the swimmer to fall 9.00 meters vertically. We use the equation for free fall: \[ y = \frac{1}{2} g t^2 \] where \( y = 9.00 \) meters is the vertical distance and \( g = 9.81 \) m/s² is the acceleration due to gravity. Solving for \( t \), we have: \[ t^2 = \frac{2 \times 9.00}{9.81} \] \[ t = \sqrt{\frac{18.00}{9.81}} \approx 1.35 \text{ seconds} \]
03

Calculate Horizontal Distance

Determine the horizontal speed needed to clear the ledge. The swimmer must travel 1.75 meters horizontally in 1.35 seconds. We use the equation for horizontal motion: \[ d = v t \] Setting \( d = 1.75 \) meters and \( t = 1.35 \) seconds: \[ v = \frac{1.75}{1.35} \approx 1.30 \text{ m/s} \]
04

Conclusion

The minimum horizontal speed required for the swimmer to safely clear the ledge is approximately 1.30 m/s.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Horizontal Velocity
In projectile motion, horizontal velocity is crucial in determining where an object lands. When the swimmer dives off the cliff, she does so with a horizontal leap. Horizontal velocity, in this context, refers to the constant speed at which she travels parallel to the ground.

Unlike vertical motion, which is affected by gravity, horizontal velocity remains steady because there are no forces like air resistance acting on it in an ideal scenario. To calculate it, we use the formula:
  • \( d = vt \)
where \(d\) is the distance to clear (1.75 meters), \(v\) is the horizontal velocity, and \(t\) is the time spent in the air.

By knowing the time it takes to fall vertically, the swimmer's horizontal velocity can be calculated, allowing her to ensure she clears the ledge safely.
Free Fall
Free fall describes the motion of the swimmer as she descends from the cliff. This movement is under the sole influence of gravity, which means that the swimmer accelerates downwards at a constant rate. The acceleration due to gravity on Earth is \(9.81\, \text{m/s}^2\).

To find how long it takes for the swimmer to reach the ledge, we utilize the equation for free fall:
  • \( y = \frac{1}{2} g t^2 \)
Here, \(y\) is the vertical displacement (9 meters in this case) and \(t\) is the time. Solving for \(t\) provides the time of fall, which is approximately 1.35 seconds.

This timing not only tells us when she will reach the ledge vertically but also plays a key role in calculating how far she travels horizontally during the same period.
Kinematics
Kinematics is the branch of physics that deals with the motion of objects. It provides the framework for analyzing this projectile motion problem. By breaking down the swimmer's dive into horizontal and vertical components, kinematics enables the separation of variables affecting each motion.

The key kinematic equations used here account for both aspects of her dive: the uniform horizontal motion and the accelerated vertical motion due to gravity.

Velocity in horizontal motion and displacement in free fall are connected through time. This makes kinematics essential for discovering the conditions under which the swimmer will land safely beyond the ledge.

Understanding kinematics helps in drawing clear relationships between the variables, such as distance, time, and velocity, thereby solving motion-related problems like this cliff dive example.
Gravity
Gravity is the natural phenomenon that causes the swimmer to accelerate towards the Earth. It acts exclusively in the vertical direction in this scenario, leaving her horizontal motion unaffected.

The constant acceleration due to gravity is \(9.81\, \text{m/s}^2\). This value does not change and is what pulls the swimmer down as she leaps off the cliff.

In projectile motion, gravity is responsible for increasing the velocity of an object as it falls. The longer the object is in the air, the faster it travels downwards.

By understanding gravity, one can predict how fast and in what manner the swimmer descends. This not only assists in finding the time of fall but also helps in planning the necessary horizontal speed needed to ensure she doesn’t hit the ledge.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A bottle rocket can shoot its projectile vertically to a height of \(25.0 \mathrm{~m}\). At what angle should the bottle rocket be fired to reach its maximum horizontal range, and what is that range? (You can ignore air resistance.)

A batted baseball leaves the bat at an angle of \(30.0^{\circ}\) above the horizontal and is caught by an outfielder \(375 \mathrm{ft}\) from home plate at the same height from which it left the bat. (a) What was the initial speed of the ball? (b) How high does the ball rise above the point where it struck the bat?

Crossing the river, I. A river flows due south with a speed of \(2.0 \mathrm{~m} / \mathrm{s} .\) A man steers a motorboat across the river; his velocity relative to the water is \(4.2 \mathrm{~m} / \mathrm{s}\) due east. The river is \(800 \mathrm{~m}\) wide. (a) What is his velocity (magnitude and direction) relative to the earth? (b) How much time is required for the man to cross the river? (c) How far south of his starting point will he reach the opposite bank?

Canada geese migrate essentially along a north-south direction for well over a thousand kilometers in some cases, traveling at speeds up to about \(100 \mathrm{~km} / \mathrm{h}\). If one such bird is flying at \(100 \mathrm{~km} / \mathrm{h}\) relative to the air, but there is a \(40 \mathrm{~km} / \mathrm{h}\) wind blowing from west to east, (a) at what angle relative to the northsouth direction should this bird head so that it will be traveling directly southward relative to the ground? (b) How long will it take the bird to cover a ground distance of \(500 \mathrm{~km}\) from north to south? (Note: Even on cloudy nights, many birds can navigate using the earth's magnetic field to fix the north-south direction.)

Show that a projectile achieves its maximum range when it is fired at \(45^{\circ}\) above the horizontal if \(y=y_{0}\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.