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PRK surgery. Photorefractive keratectomy (PRK) is a laserbased surgery process that corrects near- and farsightedness by removing part of the lens of the eye to change its curvature and hence focal length. This procedure can remove layers \(0.25 \mu \mathrm{m}\) thick in pulses lasting \(12.0 \mathrm{~ns}\) with a laser beam of wavelength \(193 \mathrm{nm} .\) Low-intensity beams can be used because each individual photon has enough energy to break the covalent bonds of the tissue. (a) In what part of the electromagnetic spectrum does this light lie? (b) What is the energy of a single photon? (c) If a \(1.50 \mathrm{~mW}\) beam is used, how many photons are delivered to the lens in each pulse?

Short Answer

Expert verified
(a) Ultraviolet region; (b) 1.03 x 10^{-18} J; (c) 1.75 x 10^7 photons per pulse.

Step by step solution

01

Identify the Wavelength Region

The given wavelength of the laser beam used in PRK surgery is 193 nm. To identify which part of the electromagnetic spectrum this falls under, recognize that the ultraviolet (UV) spectrum ranges from about 10 nm to 400 nm. Since 193 nm is within this range, the light lies in the ultraviolet (UV) region of the electromagnetic spectrum.
02

Calculate the Energy of a Single Photon

The energy of a photon is calculated using the equation \( E = \frac{hc}{\lambda} \), where \( h \) is Planck's constant \( (6.63 \times 10^{-34} \text{ J s}) \), \( c \) is the speed of light \( (3.00 \times 10^8 \text{ m/s}) \), and \( \lambda \) is the wavelength \( (193 \times 10^{-9} \text{ m}) \).Substituting these values, the energy \( E \) becomes:\[ E = \frac{6.63 \times 10^{-34} \times 3.00 \times 10^8}{193 \times 10^{-9}} = 1.03 \times 10^{-18} \text{ J} \]
03

Calculate the Number of Photons per Pulse

To find how many photons are delivered to the lens in each pulse, first convert the power of the beam into energy per pulse. The power of the beam is given as 1.50 mW, which is 0.00150 J/s. The duration of a single pulse is 12.0 ns, which is \( 12.0 \times 10^{-9} \) seconds.The energy for one pulse is: \( E_{\text{pulse}} = 0.00150 \times 12.0 \times 10^{-9} = 1.80 \times 10^{-11} \text{ J} \).Now, use the energy of a single photon calculated in Step 2 to find the number of photons \( n \):\[ n = \frac{E_{\text{pulse}}}{E_{\text{photon}}} = \frac{1.80 \times 10^{-11}}{1.03 \times 10^{-18}} = 1.75 \times 10^{7} \text{ photons} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ultraviolet Spectrum
The ultraviolet (UV) spectrum is a segment of the electromagnetic spectrum. It ranges from about 10 nanometers (nm) to 400 nm.
It sits right between the violet end of visible light and X-rays. In simpler terms, UV light is just beyond the violet we can see with our eyes. This makes it invisible to us.
However, despite being invisible, it has significant energy and impacts our daily lives. When we talk about UV light, it's often associated with the sun. But in the medical world, it finds a special place.
  • UV light can be used for sterilizing medical equipment.
  • It's also used in various laser surgeries like PRK, due to its precision capabilities.
In PRK surgery, the UV light helps in reshaping the eye lens by precisely removing thin layers of tissue.
Photon Energy Calculation
Photon energy is crucial when considering light's interaction with matter, especially in medical applications like the PRK surgery. Here, each photon must have the right amount of energy to perform the desired action on tissues.
The energy of a photon is fundamentally determined by its wavelength. We use the formula:\[ E = \frac{hc}{\lambda} \]where:
  • \( h \) is Planck's constant \((6.63 \times 10^{-34} \, \text{J s})\),
  • \( c \) is the speed of light \((3.00 \times 10^8 \, \text{m/s})\), and
  • \( \lambda \) is the wavelength of light.
By plugging the values specific to the laser used in PRK (193 nm), you can see how energy is calculated. Each photon has enough energy to disrupt tissue bonds, allowing the precision necessary for surgical applications.
Electromagnetic Spectrum
The electromagnetic spectrum encompasses all types of electromagnetic radiation. These radiations are waves of energy that travel through space at the speed of light.
The spectrum is divided based on wavelength and frequency. It ranges from long radio waves to shorter gamma rays. Here’s the classification in order:
  • Radio waves - Longest wavelengths.
  • Microwaves
  • Infrared
  • Visible light - Our eyes can see this range.
  • Ultraviolet (UV) - Higher energy than visible light.
  • X-rays
  • Gamma rays - Shortest wavelengths with highest energy.
Understanding the electromagnetic spectrum helps us understand the applications of different types of waves.
In PRK, knowing the exact place where UV light falls on the spectrum frames the basis for why this light is used for optical surgeries.
Laser Technology in Medicine
Laser technology has revolutionized the medical field. It provides precise control over light energy, enabling innovative treatments for various conditions.
In photorefractive keratectomy (PRK) surgery, lasers are used to improve vision by reshaping the cornea. Key aspects of how laser technology is applied in medicine include:
  • Precision: Lasers provide unparalleled accuracy, essential in eye surgeries.
  • Minimally invasive procedures: Many laser surgeries require small or no incisions.
  • Reduced recovery time: Patients often heal faster with laser surgeries compared to traditional ones.
  • Versatility: From correcting vision issues to removing tattoos, lasers have varied uses.
In PRK, the laser precisely removes the microscopic layer of the cornea to correct vision.
This process is facilitated by understanding both the optical properties of tissue and the energy delivered by the laser.

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Most popular questions from this chapter

Removing vascular lesions. A pulsed dye laser emits light of wavelength \(585 \mathrm{nm}\) in \(450 \mu \mathrm{s}\) pulses. Because this wavelength is strongly absorbed by the hemoglobin in the blood, the method is especially effective for removing various types of blemishes due to blood, such as port- wine-colored birthmarks. To get a reasonable estimate of the power required for such laser surgery, we can model the blood as having the same specific heat and heat of vaporization as water \(\left(4190 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, 2.256 \times 10^{6} \mathrm{~J} / \mathrm{kg}\right) .\) Suppose that each pulse must remove \(2.0 \mu \mathrm{g}\) of blood by evaporating it, starting at \(33^{\circ} \mathrm{C}\). (a) How much energy must each pulse deliver to the blemish? (b) What must be the power output of this laser? (c) How many photons does each pulse deliver to the blemish?

Removing birthmarks. Pulsed dye lasers emit light of wavelength \(585 \mathrm{nm}\) in \(0.45 \mathrm{~ms}\) pulses to remove skin blemishes such as birthmarks. The beam is usually focused onto a circular spot \(5.0 \mathrm{~mm}\) in diameter. Suppose that the output of one such laser is \(20.0 \mathrm{~W}\). (a) What is the energy of each photon, in eV? (b) How many photons per square millimeter are delivered to the blemish during each pulse?

Why is it easier to use helium ions rather than neutral helium atoms in an atomic microscope? A. Helium atoms are not electrically charged, and only electrically charged particles have wave properties. B. Helium atoms form molecules, which are too large to have wave properties. C. Neutral helium atoms are more difficult to focus with electric and magnetic fields. D. The much larger mass of a helium atom compared to a helium ion makes it more difficult to accelerate.

A triply ionized beryllium ion, \(\mathrm{Be}^{3+}\) (a beryllium atom with three electrons removed), behaves very much like a hydrogen atom, except that the nuclear charge is four times as great. (a) What is the ground-level energy of \(\mathrm{Be}^{3+}\) ? How does this compare with the ground-level energy of the hydrogen atom? (b) What is the ionization energy of \(\mathrm{Be}^{3+}\) ? How does this compare with the ionization energy of the hydrogen atom? (c) For the hydrogen atom, the wavelength of the photon emitted in the transition \(n=2\) to \(n=1\) is \(122 \mathrm{nm} .\) (See Example \(28.6 .)\) What is the wavelength of the photon emitted when a \(\mathrm{Be}^{3+}\) ion undergoes this transition? (d) For a given value of \(n\), how does the radius of an orbit in \(\mathrm{Be}^{3+}\) compare with that for hydrogen?

An electron in an excited state of hydrogen makes a transition from the \(n=5\) level to the \(n=2\) level. (a) Does the atom emit or absorb a photon during this process? How do you know? (b) Calculate the wavelength of the photon involved in the transition.

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