/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 A particle is moving with a spee... [FREE SOLUTION] | 91Ó°ÊÓ

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A particle is moving with a speed of \(0.80 c\). Calculate the ratio of its kinetic energy to its rest energy.

Short Answer

Expert verified
The ratio of kinetic energy to rest energy is \( \frac{2}{3} \).

Step by step solution

01

Understanding Key Concepts

The problem involves concepts of modern physics, specifically involving relativistic speeds. Given that the speed of the particle is a fraction of the speed of light, we will use relativistic formulas for energy. We need to find the ratio of the kinetic energy (KE) to the rest energy (E_0) of the particle.
02

Using Relativistic Energy Formulas

The rest energy of the particle is given by:\[ E_0 = mc^2 \]The total energy (E) when moving at a speed \(v\) is:\[ E = \frac{mc^2}{\sqrt{1 - \left(\frac{v}{c}\right)^2}} \]The kinetic energy is therefore:\[ KE = E - E_0 \]
03

Calculating Total Energy

Substitute \(v = 0.80c\) into the formula for total energy:\[ E = \frac{mc^2}{\sqrt{1 - (0.80)^2}} = \frac{mc^2}{\sqrt{1 - 0.64}} = \frac{mc^2}{\sqrt{0.36}} = \frac{mc^2}{0.6} \]
04

Finding Kinetic Energy

Using the expression for kinetic energy:\[ KE = E - E_0 = \frac{mc^2}{0.6} - mc^2 = mc^2\left(\frac{1}{0.6} - 1\right) = mc^2\left(\frac{1 - 0.6}{0.6}\right) = mc^2\left(\frac{0.4}{0.6}\right) = mc^2 \left(\frac{2}{3}\right) \]
05

Calculating the Ratio of Kinetic Energy to Rest Energy

The ratio of kinetic energy to rest energy is given by:\[ \text{Ratio} = \frac{KE}{E_0} = \frac{\left(\frac{2}{3}mc^2\right)}{mc^2} = \frac{2}{3} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rest Energy
Rest energy is a concept in physics referring to the intrinsic energy of an object at rest. According to Einstein's famous equation, rest energy is expressed using the formula \( E_0 = mc^2 \). Here, \( m \) represents the object's rest mass, and \( c \) is the speed of light.
Understanding rest energy is crucial since it represents the minimum energy a particle possesses simply by its existence. It lays the foundation for deeper studies in physics, particularly when dealing with advanced concepts like relativity.
Rest energy highlights how mass is a pure form of energy, showing that even a stationary object inherently holds vast amounts of energy simply due to its mass.
In relativistic physics, recognizing that an object's rest energy can be significant, especially at high speeds, is essential. This energy contributes to determining how much energy is needed to accelerate a particle from rest to a higher velocity.
Speed of Light
The speed of light, denoted by \( c \), is a fundamental constant in physics and plays a pivotal role in modern physics theories. It is approximately \( 3 \, \times \, 10^8 \) meters per second in a vacuum. This constant is vital in relativity because it represents the maximum speed at which information or matter can travel.
The speed of light is not just a measure but also defines the relationship between time and space. It acts as a boundary for the speed of all particles and signals, influencing how energy, like kinetic or rest energy, transforms with speed.
In the context of physics problems, the speed of light underlines the constraints and allows us to use relativity to calculate dynamic properties of particles, such as kinetic energy when they move at relativistic speeds (a significant portion of the speed of light).
Relativistic Energy Formulas
Relativistic energy formulas are adjustments of classical physics formulas to account for objects moving at speeds close to the speed of light. In classical physics, kinetic energy is defined by \( KE = \frac{1}{2}mv^2 \), but this does not hold at high velocities.
For relativistic speeds, energy is described as:
  • Total energy \( E \) is calculated with \[ E = \frac{mc^2}{\sqrt{1- \left(\frac{v}{c}\right)^2}} \].
  • Kinetic energy \( KE \) can then be derived from \( E - E_0 \), where \( E_0 = mc^2 \), showing that beyond rest energy, kinetic energy is required to account for the increase in velocity.
These formulas are crucial for accurately describing the behavior of particles in high-speed scenarios, illustrating how their energy requirements grow drastically as they approach the speed of light.
Kinetic Energy Ratio
The kinetic energy ratio involves comparing the kinetic energy of an object to its rest energy, providing insights into how energy evolves with speed. For particles moving close to the speed of light, this ratio becomes a tool to understand relativistic effects.
Using the relationship derived from relativistic energies, we calculate:
  • Ratio \( = \frac{KE}{E_0} \).
  • For a particle moving at \( 0.80c \), the ratio is \( \frac{2}{3} \), indicating that its kinetic energy is two-thirds of its rest energy.
This ratio helps underline how at high speeds, even significant kinetic energy is required to increase velocity further due to relativistic effects.
Through this understanding, one can appreciate how energy distribution in fast-moving particles is dominated by the relativistic framework.
Modern Physics Concepts
Modern physics concepts frequently explore how classical mechanics break down at high velocities, close to the speed of light, necessitating the use of relativity and quantum mechanics.
Relativity, introduced by Einstein, revolutionized our understanding of motion at extreme speeds, distinct from Newtonian mechanics. It shows us how time and space are intertwined, impacting objects' energy and motion in space.
Modern physics helps us solve complex problems, like how to handle particles moving at speeds comparable to light, requiring precise calculations using relativistic energy formulas.
It enhances our comprehension of the universe, pushing the boundaries of our knowledge and leading to advancements in technology, such as GPS systems and understanding cosmic phenomena.
These concepts are fundamental in developing technologies and theories that continue to shape our world and extend the horizons of human knowledge.

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Most popular questions from this chapter

A particle of mass \(m\) is moving at a speed \(v .\) (a) At what fraction of the speed of light is the momentum of the particle twice the nonrelativistic Newtonian momentum \(p=m v ?\) (b) Can the magnitude of the relativistic momentum ever be less than that of the Newtonian momentum?

Electrons are accelerated through a potential difference of \(750 \mathrm{kV}\), so that their kinetic energy is \(7.50 \times 10^{5} \mathrm{eV}\). (a) What is the ratio of the speed \(v\) of an electron having this energy to the speed of light, \(c ?\) (b) What would the speed be if it were computed from the principles of classical mechanics?

A meterstick moves past you at great speed. Its motion relative to you is parallel to its long axis. If you measure the length of the moving meterstick to be \(1.00 \mathrm{ft}(1 \mathrm{ft}=0.3048 \mathrm{~m})-\) for example, by comparing it with a 1-ft ruler that is at rest relative to you-at what speed is the meterstick moving relative to you?

The negative pion \(\left(\pi^{-}\right)\) is an unstable particle with an average lifetime of \(2.60 \times 10^{-8} \mathrm{~s}\) (measured in the rest frame of the pion). (a) If the pion is made to travel at very high speed relative to a laboratory, its average lifetime is measured in the laboratory to be \(4.20 \times 10^{-7} \mathrm{~s} .\) Calculate the speed of the pion expressed as a fraction of \(c .\) (b) What distance, as measured in the laboratory, does the pion travel during its average lifetime?

A cube of metal with sides of length \(a\) sits at rest in the laboratory with one edge parallel to the \(x\) axis. Therefore, in the laboratory frame, its volume is \(a^{3}\). A rocket ship flies past the laboratory parallel to the \(x\) axis with a velocity \(v .\) As measured by an observer in the rocket, determine (a) the length of the edges of the cube that are perpendicular to the \(x\) axis, (b) the length of the cube edges that are parallel to the \(x\) axis, and (c) the volume of the metal cube.

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