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A laser beam of wavelength \(600.0 \mathrm{nm}\) is incident normally on a transmission grating having 400.0 lines \(/ \mathrm{mm} .\) Find the angles of deviation in the first, second, and third orders of bright spots.

Short Answer

Expert verified
Angles are approximately \(13.9^\circ\), \(28.7^\circ\), and \(46.4^\circ\) for first, second, third orders.

Step by step solution

01

Identify Key Parameters

First, identify the key parameters of the problem: the wavelength of the laser beam \( \lambda = 600.0\, \text{nm} \), and the transmission grating with \( 400.0 \) lines\/mm. We must convert the wavelength to meters by noting that \( 1\, \text{nm} = 1 \times 10^{-9} \text{m} \), so \( \lambda = 600.0 \times 10^{-9} \text{m} \).
02

Determine Grating Spacing

The grating has \( 400.0 \) lines per millimeter, which means the spacing \( d \) between the lines is the reciprocal: \( d = \frac{1}{400.0\, \text{lines/mm}} = \frac{1}{400.0\times 10^3\, \text{lines/m}} = 2.5 \times 10^{-6} \text{m} \).
03

Use Grating Equation

The grating equation is \( d \sin \theta = n \lambda \), where \( n \) is the order number. We need to find \( \theta \) for the first, second, and third orders (\( n = 1, 2, 3 \)).
04

Calculate First Order Deviation

For \( n = 1 \), the equation is \( 2.5 \times 10^{-6} \sin \theta = 1 \times 600.0 \times 10^{-9} \). Solving for \( \sin \theta \), we get \( \sin \theta = \frac{600.0 \times 10^{-9}}{2.5 \times 10^{-6}} = 0.24 \). Therefore, \( \theta_1 = \arcsin(0.24) \approx 13.9^\circ \).
05

Calculate Second Order Deviation

For \( n = 2 \), the equation is \( 2.5 \times 10^{-6} \sin \theta = 2 \times 600.0 \times 10^{-9} \). Solving for \( \sin \theta \), we get \( \sin \theta = \frac{1200.0 \times 10^{-9}}{2.5 \times 10^{-6}} = 0.48 \). Therefore, \( \theta_2 = \arcsin(0.48) \approx 28.7^\circ \).
06

Calculate Third Order Deviation

For \( n = 3 \), the equation is \( 2.5 \times 10^{-6} \sin \theta = 3 \times 600.0 \times 10^{-9} \). Solving for \( \sin \theta \), we get \( \sin \theta = \frac{1800.0 \times 10^{-9}}{2.5 \times 10^{-6}} = 0.72 \). Therefore, \( \theta_3 = \arcsin(0.72) \approx 46.4^\circ \).
07

Conclusion: Summary of Results

The angles of deviation for the first three orders of bright spots are approximately \( 13.9^\circ \), \( 28.7^\circ \), and \( 46.4^\circ \) respectively.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Wavelength
Wavelength is a crucial concept in the study of waves. It's the distance between two successive points that are in phase, which means they have the same pattern of motion.
In this context, wavelength is often denoted by the Greek letter lambda (\(\lambda\)). For our laser beam, the wavelength is given as \(600.0\, \text{nm}\), which is a unit called nanometers. To convert to meters, which is more useful in calculations, we remember that \(1\, \text{nm} = 1 \times 10^{-9} \text{m}\). Thus, our wavelength is \(600.0 \times 10^{-9}\, \text{m}\).
Understanding wavelength impacts how we analyze patterns produced by diffracting lights, such as the colors seen when light passes through a prism or a grating.
Characteristics of a Laser Beam
A laser beam is a stream of coherent light where the waves are in phase and have a constant amplitude. Lasers are prized for their precision and intensity, mainly due to this coherence.
In diffraction experiments, such as those involving a grating, the laser's consistent wavelength leads to clear patterns, making lasers an excellent choice for investigating wave properties.
The properties of the laser are essential to predict how it will interact with a diffraction grating, and what kind of diffraction pattern will emerge.
Angles of Deviation in Diffraction
When light passes through a diffraction grating, it bends, and this bending is termed as 'deviation.' The angles at which the light is bent are the angles of deviation.
In our problem, these angles determine where bright spots appear on the screen in various orders (first, second, third, etc.). Each order corresponds to a specific angle, which can be calculated using known formulas.
These angles are critical in applications such as spectrometers, where light needs to be split into its component colors. The distinct deviation angles help researchers and scientists identify substances based on their spectral lines.
The Grating Equation
The grating equation is essential for calculating the angles of deviation. It is given by \(d \sin \theta = n \lambda\), where:
  • \(d\) is the spacing between lines on the grating
  • \(\theta\) is the angle of deviation
  • \(n\) is the order of the bright fringe
  • \(\lambda\) is the wavelength of the light
By rearranging this equation, you can solve for \(\theta\) for any given \(n\).
This equation encapsulates how coherent light of a specific wavelength will divide into patterns when encountering a structured grating. Spacing (\(d\)) and the wavelength are fundamental in determining different harmonic orders, making the calculation straightforward to understand.

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Most popular questions from this chapter

A laser beam of wavelength \(\lambda=632.8 \mathrm{nm}\) shines at normal incidence on the reflective side of a compact disk. (a) The tracks of tiny pits in which information is coded onto the \(\mathrm{CD}\) are \(1.60 \mu \mathrm{m}\) apart. For what angles of reflection (measured from the normal) will the intensity of light be maximum? (b) On a DVD, the tracks are only \(0.740 \mu \mathrm{m}\) apart. Repeat the calculation of part (a) for the DVD.

A wildlife photographer uses a moderate telephoto lens of focal length \(135 \mathrm{~mm}\) and maximum aperture \(f / 4.00\) to photograph a bear that is \(11.5 \mathrm{~m}\) away. Assume the wavelength is \(550 \mathrm{nm}\). (a) What is the width of the smallest feature on the bear that this lens can resolve if it is opened to its maximum aperture? (b) If, to gain depth of field, the photographer stops the lens down to \(f / 22.0,\) what would be the width of the smallest resolvable feature on the bear?

Suppose you illuminate two thin slits by monochromatic coherent light in air and find that they produce their first interference minima at \(\pm 35.20^{\circ}\) on either side of the central bright spot. You then immerse these slits in a transparent liquid and illuminate them with the same light. Now you find that the first minima occur at \(\pm 19.46^{\circ}\) instead. What is the index of refraction of this liquid?

Due to blurring caused by atmospheric distortion, the best resolution that can be obtained by a normal, earth-based, visible-light telescope is about 0.3 arcsecond (there are 60 arcminutes in a degree and 60 arcseconds in an arcminute). (a) Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with \(550 \mathrm{nm}\) light. (b) Increasing the telescope diameter beyond the value found in part (a) will increase the light-gathering power of the telescope, allowing more distant and dimmer astronomical objects to be studied, but it will not improve the resolution. In what ways are the Keck telescopes (each of \(10 \mathrm{~m}\) diameter) atop Mauna Kea in Hawaii superior to the Hale Telescope ( 5 m diameter) on Palomar Mountain in California? In what ways are they not superior? Explain.

Eyeglass lenses can be coated on the inner surfaces to reduce the reflection of stray light to the eye. If the lenses are medium flint glass of refractive index 1.62 and the coating is fluorite of refractive index \(1.432,\) (a) what minimum thickness of film is needed on the lenses to cancel light of wavelength \(550 \mathrm{nm}\) reflected toward the eye at normal incidence, and (b) will any other wavelengths of visible light be canceled or enhanced in the reflected light?

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