/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 An amateur photographer purchase... [FREE SOLUTION] | 91Ó°ÊÓ

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An amateur photographer purchases a vintage camera at a flea market. In order to determine the focal length of the camera's lens, he sets a soup can at various distances from the camera. At each distance he brings the camera into focus on the can and then carefully measures the distance between the lens and the film. His measurements are given in the table. $$ \begin{array}{cc} \hline \text { Can distance }(\mathrm{cm}) & \text { Lens distance }(\mathrm{mm}) \\ \hline 25 & 118 \\ 35 & 104 \\ 50 & 95 \\ 75 & 89 \\ 100 & 87 \\ \hline \end{array} $$ Make a plot of the inverse lens distance as a function of the inverse can distance. Using a linear "best fit" to the data, determine the focal length of the lens.

Short Answer

Expert verified
Find the slope of the line to determine the focal length. The focal length is the reciprocal of the slope.

Step by step solution

01

Convert Measurements into Inverse Values

First, convert the given measurements into inverse values. The inverse can distance and inverse lens distance can be calculated using:\[\text{Inverse Can Distance (cm}^{-1}\text{)} = \frac{1}{\text{Can Distance (cm)}}\] \[\text{Inverse Lens Distance (mm}^{-1}\text{)} = \frac{1}{\text{Lens Distance (mm)}}\]Calculate these for each data point.
02

Calculate Inverse Values

Using the conversion formulas from Step 1, calculate the inverse values for each distance:For Can Distance:- 25 cm: \( \frac{1}{25} = 0.04 \text{ cm}^{-1} \)- 35 cm: \( \frac{1}{35} \approx 0.0286 \text{ cm}^{-1} \)- 50 cm: \( \frac{1}{50} = 0.02 \text{ cm}^{-1} \)- 75 cm: \( \frac{1}{75} \approx 0.0133 \text{ cm}^{-1} \)- 100 cm: \( \frac{1}{100} = 0.01 \text{ cm}^{-1} \)For Lens Distance:- 118 mm: \( \frac{1}{118} \approx 0.00847 \text{ mm}^{-1} \)- 104 mm: \( \frac{1}{104} \approx 0.00962 \text{ mm}^{-1} \)- 95 mm: \( \frac{1}{95} \approx 0.01053 \text{ mm}^{-1} \)- 89 mm: \( \frac{1}{89} \approx 0.01124 \text{ mm}^{-1} \)- 87 mm: \( \frac{1}{87} \approx 0.01149 \text{ mm}^{-1} \)
03

Plot the Data

Create a Cartesian plot with the inverse can distance on the x-axis and the inverse lens distance on the y-axis. Plot each pair from the data calculated in Step 2.
04

Determine Best Fit Line

Fit a straight line to the set of points plotted in Step 3. This can be done using linear regression techniques, either manually or using a tool like a graphing calculator, spreadsheet software, or programming libraries such as MATLAB or Python's NumPy. Record the slope and y-intercept of this line.
05

Calculate Focal Length from Slope

The slope of the best fit line represents the focal length of the lens in centimeters, as the lens equation is:\[ \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \]Where \(f\) is the focal length, \(d_o\) is the object distance (can distance), and \(d_i\) is the image distance (lens distance). The linear relationship involved implies the slope equals \(1/f\). Calculate \(f\) as the reciprocal of the slope from Step 4.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Focal Length Determination
To determine the focal length of a lens, one must understand that it’s a measurement of how strongly the lens converges or diverges light. In this context, the amateur photographer's task is to find the focal length of a vintage camera’s lens. The focal length (represented as \(f\)) can be calculated accurately using the lens equation, which involves conducting experiments with known object distances and measuring corresponding image distances. The lens equation is given by: \[ \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \]- \(d_o\) refers to the object distance (distance from the can to the camera).- \(d_i\) is the image distance (distance from the lens to the film).
By plotting data points using these measurements, a linear relationship can be derived that helps in finding the reciprocal of the focal length as the slope of the line.
Inverse Distance Measurement
In this physics experiment, it’s essential to convert the measurements of distances into their inverses to facilitate the linear relationship needed for analysis. The idea is to take the reciprocal of both the can (object) distance and the lens (image) distance. By calculating these inverse values, students can simplify the complex relationship between the image and object distances into a straight line when plotted on a graph. Let's break it down:- Inverse Can Distance (\(\text{cm}^{-1}\)) is calculated as \(\frac{1}{\text{Can Distance (cm)}}\).- Inverse Lens Distance (\(\text{mm}^{-1}\)) is \(\frac{1}{\text{Lens Distance (mm)}}\).
Transforming these measurements into inverse values allows us to extract meaningful insights using linear regression.
Linear Regression Analysis
Linear regression is a statistical method used to model the relationship between a dependent variable and one or more independent variables. In this case, it helps in finding the best fit line through the data points obtained from the inverse distance measurements. Here’s how you can approach it: - Take the inverse can distance as the independent variable (x-axis) and inverse lens distance as the dependent variable (y-axis). - Use computer software or calculators to perform the linear regression analysis. This involves calculating the slope and y-intercept for the line that best fits the data points.
The slope obtained from this analysis directly relates to the focal length of the lens, as it corresponds to the reciprocal of the focal length.
Optics and Lens Equations
Understanding optics and lens equations is crucial for interpreting results from lens experiments. Optics is the branch of physics that focuses on the behavior and properties of light. Lens equations describe how light converges and diverges when passing through lenses. The primary equation here is the lens formula:\[ \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \]This formula is pivotal because it directly connects the object distance, image distance, and focal length of the lens. - It signifies that if you adjust the object distance, the image distance will change such that the equation remains balanced.
Through understanding and applying this equation, the amateur photographer can precisely determine the lens's focal length and understand the lens's optical power.

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Most popular questions from this chapter

The characteristics that follow are characteristics of two of Galileo's surviving double-convex lenses. The numbers given are magnitudes only; you must supply the correct signs. \(L_{1}:\) front radius \(=950 \mathrm{~mm},\) rear radius \(=2700 \mathrm{~mm},\) refractive index \(=\) \(1.528 ; L_{2}\) :front radius \(=535 \mathrm{~mm},\) rear radius \(=50,500 \mathrm{~mm},\) refractive index \(=1.550 .\) (a) What is the largest angular magnification that Galileo could have obtained with these two lenses? (b) How long would this telescope be between the two lenses?

A certain microscope is provided with objectives that have focal lengths of \(16 \mathrm{~mm}, 4 \mathrm{~mm},\) and \(1.9 \mathrm{~mm}\) and with eyepieces that have angular magnifications of \(5 \times\) and \(10 \times .\) Each objective forms an image \(120 \mathrm{~mm}\) beyond its second focal point. Determine (a) the largest overall angular magnification obtainable and (b) the smallest overall angular magnification obtainable.

A camera is focused on an object that is \(1.2 \mathrm{~m}\) from the lens. The distance between the CCD image sensor and the lens is \(5 \mathrm{~cm}\). What is the focal length of the lens?

You want to take a full-length photo of your friend who is \(2.00 \mathrm{~m}\) tall, using a \(35 \mathrm{~mm}\) camera having a 50.0 -mm-focal-length lens. The image dimensions of \(35 \mathrm{~mm}\) film are \(24 \mathrm{~mm} \times 36 \mathrm{~mm},\) and you want to make this a vertical photo in which your friend's image completely fills the image area. (a) How far should your friend stand from the lens? (b) How far is the lens from the film?

Contact lenses are placed right on the eyeball, so the distance from the eye to an object (or image) is the same as the distance from the lens to that object (or image). A certain person can see distant objects well, but his near point is \(45.0 \mathrm{~cm}\) from his eyes instead of the usual \(25.0 \mathrm{~cm}\). (a) Is this person nearsighted or farsighted? (b) What type of lens (converging or diverging) is needed to correct his vision? (c) If the correcting lenses will be contact lenses, what focal-length lens is needed and what is its power in diopters?

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