/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 II A 1.55-m-tall fisherman stand... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

II A 1.55-m-tall fisherman stands at the edge of a lake, being watched by a suspicious trout that is \(3.50 \mathrm{~m}\) from the fisherman in the horizontal direction and \(45.0 \mathrm{~cm}\) below the surface of the water. At what angle from the vertical does the fish see the top of the fisherman's head?

Short Answer

Expert verified
The angle from the vertical is approximately \(29.74^\circ\).

Step by step solution

01

Understanding the Scenario

First, visualize the scenario. The fisherman is standing vertically at the edge of the lake. The fish is located 3.50 meters horizontally from the fisherman and 0.45 meters below the water surface. We need to find the angle from the vertical at which the fish sees the top of the fisherman's head.
02

Establish Coordinates

Assign coordinates to the key points. Let the point directly below the fisherman's feet on the water's surface be the origin (0, 0). The fish is at (3.50 m, -0.45 m) and the top of the fisherman's head is at (0 m, 1.55 m).
03

Determine the Line of Sight

The line of sight from the fish to the top of the fisherman's head is a straight line joining the fish's position to the top of the fisherman's head. This line will form the hypotenuse of a right triangle with the vertical direction.
04

Calculate Vertical and Horizontal Distances

Calculate the difference in vertical distances. The vertical distance from the fish to the top of the fisherman's head is the difference in their y-coordinates: Vertical distance = Height of fisherman's head - Depth of fish = 1.55 m - (-0.45 m) = 2.00 m.
05

Use Trigonometry to Find the Angle

To find the angle from the vertical (\( \theta \)) at which the fish sees the top of the fisherman's head, use the tangent function. \[ \tan(\theta) = \frac{\text{Horizontal distance}}{\text{Vertical distance}} = \frac{3.50}{2.00} = 1.75 \]Now, calculate \( \theta \): \[ \theta = \tan^{-1}(1.75) \approx 60.26^\circ \].
06

Find the Complementary Angle

Since we need the angle from the vertical, find the complementary angle: \( \text{Angle from vertical} = 90^\circ - \theta = 90^\circ - 60.26^\circ = 29.74^\circ \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometry in Physics
In physics, trigonometry helps us calculate angles and distances that aren't directly measurable. Imagine a fisherman and a fish in a lake. The fish wants to know the angle at which it sees the top of the fisherman's head. Here, trigonometry can simplify the hardness of the task.
Knowing the distances horizontally and vertically, we can use functions like tangent, sine, or cosine. Specifically, the tangent function relates the angle to the ratio of the opposite side over the adjacent side in a right triangle.
For this exercise, we utilized the tangent to find the angle formed between the fish's line of sight and the vertical. Consequently, knowing trigonometry allows us to compute quantities that govern how we interpret different real-world physics problems.
Right Triangle Geometry
When confronted with problems involving height and distance, right triangle geometry is a gateway to finding solutions. Think of the fish, the fisherman’s head, and the lake's surface creating a right triangle. This configuration allows easy calculation of unknown angles or distances.
The vertical difference between the fish and the fisherman's head became one side of our triangle, and the horizontal distance makes up the other. The fish’s line of sight, acting as the hypotenuse, connects these two points. Within this configuration, the theorem of Pythagoras or trigonometric identities can reveal much-needed answers about the system's geometry.
Understanding right triangle geometry not only applies to simple scenarios like this one but becomes a versatile tool across various physics applications.
Visualizing Physics Scenarios
Visualizing scenarios in physics involves breaking down complex situations into simpler, understandable components. We began with our fisherman and fish by creating a coordinate system, setting clear reference points.
The fish beneath the water's surface and the top of the fisherman's head established two key points. By imagining these points on a 2D coordinate plane, a vivid picture forms, laying the groundwork for our understanding.
Visualization assists in conceptualizing the problem before delving into the numbers and equations. It relieves confusion, helping students better connect the mathematics to the tangible world. Visualizing is an essential step, enriching comprehension when solving physics problems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

At the floor of a room, the intensity of light from bright overhead lights is \(8.00 \mathrm{~W} / \mathrm{m}^{2} .\) Find the radiation pressure on a totally absorbing section of the floor.

The polarizing angle for light in air incident on a glass plate is \(57.6^{\circ} .\) What is the index of refraction of the glass?

A plane sinusoidal electromagnetic wave in air has a wavelength of \(3.84 \mathrm{~cm}\) and an \(\vec{E}\) -field amplitude of \(1.35 \mathrm{~V} / \mathrm{m}\). (a) What is the frequency of the wave? (b) What is the \(\vec{B}\) -field amplitude? (c) What is the intensity? (d) What average force does this radiation exert perpendicular to its direction of propagation on a totally absorbing surface with area \(0.240 \mathrm{~m}^{2} ?\)

I Two plane mirrors \(A\) and \(B\) intersect at a \(45^{\circ}\) angle. Three rays of light leave point \(P\) (see Figure 23.48 ) and strike one of the mirrors. What is the subsequent path of each of the following rays until they no longer strike either of the mirrors? (a) Ray \(1,\) which strikes \(A\) at \(45^{\circ}\) with respect to the normal (b) Ray \(2,\) which strikes \(B\) traveling perpendicular to mirror \(A\) (c) Ray \(3,\) which strikes \(B\) perpendicular to its surface

A geostationary communications satellite orbits the earth directly above the equator at an altitude of \(35,800 \mathrm{~km}\). Calculate the time it would take a cell phone signal to travel from a point on the equator to the satellite and back. Would this delay be noticeable in a conversation?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.