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Write the wave equation for the electric field of an electromagnetic wave that is traveling in the \(+x\) direction with a wavelength of \(2.0 \mathrm{~m}\) and an amplitude of \(100 \mathrm{~N} / \mathrm{C}\). Give the wave equation in terms of its angular frequency and wave number.

Short Answer

Expert verified
The wave equation is \(E(x, t) = 100 \cos(\pi x - 3\pi \times 10^8 t)\).

Step by step solution

01

Identify Given Information

We are given an electromagnetic wave traveling in the +x direction with a wavelength \(\lambda = 2.0\, \mathrm{m}\) and an amplitude \(E_0 = 100\, \mathrm{N/C}\). We need to find the wave equation for the electric field in terms of angular frequency and wave number.
02

Calculate the Wave Number

The wave number \(k\) is related to the wavelength by the formula \(k = \frac{2\pi}{\lambda}\). Substitute \(\lambda = 2.0\, \mathrm{m}\) into the equation:\[k = \frac{2\pi}{2.0} = \pi\, \mathrm{m^{-1}}.\]
03

Calculate the Angular Frequency

The angular frequency \(\omega\) is related to the wavelength and the speed of light \(c\) as \(\omega = \frac{2\pi c}{\lambda}\). Since the speed of light \(c = 3.0 \times 10^8\, \mathrm{m/s}\), plug in the values:\[\omega = \frac{2\pi \times 3.0 \times 10^8}{2.0} = 3\pi \times 10^8\, \mathrm{rad/s}.\]
04

Write the Wave Equation

The wave equation for the electric field \(E(x, t)\) is given by:\[E(x, t) = E_0 \cos(kx - \omega t),\]where \(E_0 = 100\, \mathrm{N/C}\), \(k = \pi\, \mathrm{m^{-1}}\), and \(\omega = 3\pi \times 10^8\, \mathrm{rad/s}\). Substitute these values:\[E(x, t) = 100 \cos(\pi x - 3\pi \times 10^8 t).\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Equation
The wave equation describes how electromagnetic waves, such as light, move through space. It mathematically expresses something that varies with both position and time. The general form is written as:
  • For an electric field: \( E(x, t) = E_0 \cos(kx - \omega t) \)
Here, \( E_0 \) is the amplitude of the wave, \( k \) is the wave number, \( \omega \) is the angular frequency, \( x \) is the position, and \( t \) is the time.
A wave traveling in the positive x-direction means it has a negative \( \omega t \) term.
Think of this equation as a pattern that repeats over time and space, telling how strong the electric field is at any point.
Angular Frequency
Angular frequency is a measure of how quickly the wave cycles through its motion. It is denoted by \( \omega \) and is measured in radians per second. The formula for calculating angular frequency is:
  • \( \omega = \frac{2\pi c}{\lambda} \)
Here, \( c \) is the speed of light (approximately \( 3 \times 10^8 \) m/s), and \( \lambda \) is the wavelength of the wave.
Angular frequency relates to how fast the peaks and troughs of the wave pass a given point. The larger the \( \omega \), the more rapidly the wave oscillates. For electromagnetic waves, this speed is extremely fast, making them appear continuous to our senses.
Wave Number
Wave number is another key characteristic of a wave. It tells how many wave cycles are present in a unit distance. Represented by \( k \), it’s calculated using:
  • \( k = \frac{2\pi}{\lambda} \)
Where \( \lambda \) is the wavelength. The wave number unit is \( \mathrm{m^{-1}} \) (inverse meters).
Wave number reflects the spatial frequency. That is, how tight or loose the wave is over distance. A higher wave number means more cycles are packed into a smaller space, implying a shorter wavelength and thus, higher energy.
Electric Field
The electric field component of an electromagnetic wave represents the force that would act on a charged particle placed in the field. It’s a vector quantity with both magnitude and direction.
In our context, the electric field has an amplitude \( E_0 \), based on the initial strength given to the wave; in this problem, it's given as \( 100 \, \mathrm{N/C} \).
It expresses how strong the wave’s electric component is at any point in space and time. This strength decreases and increases as the wave propagates, cycling between -\( E_0 \) and \( E_0 \).
The variability captured by the wave equation shows how this field interacts with other charges and fields around it.
Wavelength
Wavelength, denoted as \( \lambda \), is the distance between successive crests or troughs of a wave. Think of it as the 'length' of just one cycle of the wave. For electromagnetic waves, it's often measured in meters.
Wavelength and frequency are inversely related: longer wavelengths mean lower frequencies and vice versa. In simpler terms, if a wave has a long wavelength, it oscillates less frequently.
  • Relation: \( c = \lambda f \)
Understanding this helps explain how different colors of light and parts of the electromagnetic spectrum have different properties. Wavelength has a direct impact on energy; shorter wavelengths are associated with more energetic waves, like gamma rays, while longer wavelengths are typical of radio waves, which carry less energy.

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Most popular questions from this chapter

The speed of light with a wavelength of \(656 \mathrm{nm}\) in heavy flint glass is \(1.82 \times 10^{8} \mathrm{~m} / \mathrm{s}\). What is the index of refraction of the glass at this wavelength?

A glass plate having parallel faces and a refractive index of 1.58 lies at the bottom of a liquid of refractive index \(1.70 .\) A ray of light in the liquid strikes the top of the glass at an angle of incidence of \(62.0^{\circ} .\) Compute the angle of refraction of this light in the glass.

Some insect eyes have two types of cells that are sensitive to the plane of polarization of light. In a simple model, one cell type (type \(\mathrm{H}\) ) is sensitive to horizontally polarized light only, and the other cell type (type \(\mathrm{V}\) ) is sensitive to vertically polarized light only. To study the responses of these cells, researchers fix the insect in a normal, upright position so that one eye is illuminated by a light source. Then several experiments are carried out. First, light with a plane of polarization at \(45^{\circ}\) to the horizontal shines on the insect. Which statement is true about the two types of cells? A. Both types detect this light. B. Neither type detects this light. C. Only type \(\mathrm{H}\) detects the light. D. Only type \(\mathrm{V}\) detects the light.

The vitreous humor, a transparent, gelatinous fluid that fills most of the eyeball, has an index of refraction of \(1.34 .\) Visible light ranges in wavelength from \(400 \mathrm{nm}\) (violet) to \(700 \mathrm{nm}\) (red), as measured in air. This light travels through the vitreous humor and strikes the rods and cones at the surface of the retina. What are the ranges of (a) the wavelength, (b) the frequency, and (c) the speed of the light just as it approaches the retina within the vitreous humor?

Some insect eyes have two types of cells that are sensitive to the plane of polarization of light. In a simple model, one cell type (type \(\mathrm{H}\) ) is sensitive to horizontally polarized light only, and the other cell type (type \(\mathrm{V}\) ) is sensitive to vertically polarized light only. To study the responses of these cells, researchers fix the insect in a normal, upright position so that one eye is illuminated by a light source. Then several experiments are carried out. Next, unpolarized light is reflected off a smooth horizontal piece of glass, and the reflected light shines on the insect. Which statement is true about the two types of cells? A. When the light is directly above the glass, only type \(\mathrm{V}\) detects the reflected light. B. When the light is directly above the glass, only type \(\mathrm{H}\) detects the reflected light. C. When the light is about \(35^{\circ}\) above the horizontal, type \(\mathrm{V}\) responds much more strongly than type \(\mathrm{H}\) does. D. When the light is about \(35^{\circ}\) above the horizontal, type \(\mathrm{H}\) responds much more strongly than type \(\mathrm{V}\) does.

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