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There are two categories of ultraviolet light. Ultraviolet A (UVA) has a wavelength ranging from \(320 \mathrm{nm}\) to \(400 \mathrm{nm}\). It is not so harmful to the skin and is necessary for the production of vitamin D. UVB, with a wavelength between \(280 \mathrm{nm}\) and \(320 \mathrm{nm},\) is much more dangerous because it causes skin cancer. (a) Find the frequency ranges of UVA and UVB. (b) What are the ranges of the wave numbers for UVA and UVB?

Short Answer

Expert verified
(a) UVA: \(7.5 \times 10^{14} - 9.375 \times 10^{14}\ Hz\), UVB: \(9.375 \times 10^{14} - 10.71 \times 10^{14}\ Hz\). (b) UVA: \(2.5 \times 10^6 - 3.125 \times 10^6\ m^{-1}\), UVB: \(3.125 \times 10^6 - 3.57 \times 10^6\ m^{-1}\).

Step by step solution

01

Understanding the Relationship Between Wavelength and Frequency

To find the frequency of light, we use the formula \( c = \lambda u \), where \( c \) is the speed of light \( 3 \times 10^8 \ m/s \), \( \lambda \) is the wavelength, and \( u \) is the frequency. Frequency is given by \( u = \frac{c}{\lambda} \). We will calculate this for both UVA and UVB ranges.
02

Calculate UVA Frequency Range

The wavelength range for UVA is \(320 \mathrm{nm}\) to \(400 \mathrm{nm}\). Convert these to meters: \(320 \mathrm{nm} = 320 \times 10^{-9} \ m\) and \(400 \mathrm{nm} = 400 \times 10^{-9} \ m\). Calculate the frequency:For \(400 \mathrm{nm}\):\[u = \frac{3 \times 10^8 \ m/s}{400 \times 10^{-9} \ m} = 7.5 \times 10^{14} \ Hz\]For \(320 \mathrm{nm}\):\[u = \frac{3 \times 10^8 \ m/s}{320 \times 10^{-9} \ m} = 9.375 \times 10^{14} \ Hz\]Thus, the frequency range for UVA is from \(7.5 \times 10^{14} \ Hz\) to \(9.375 \times 10^{14} \ Hz\).
03

Calculate UVB Frequency Range

The wavelength range for UVB is \(280 \mathrm{nm}\) to \(320 \mathrm{nm}\). Convert these to meters: \(280 \mathrm{nm} = 280 \times 10^{-9} \ m\) and \(320 \mathrm{nm} = 320 \times 10^{-9} \ m\). Calculate the frequency:For \(320 \mathrm{nm}\):\[u = \frac{3 \times 10^8 \ m/s}{320 \times 10^{-9} \ m} = 9.375 \times 10^{14} \ Hz\]For \(280 \mathrm{nm}\):\[u = \frac{3 \times 10^8 \ m/s}{280 \times 10^{-9} \ m} = 10.71 \times 10^{14} \ Hz\]Thus, the frequency range for UVB is from \(9.375 \times 10^{14} \ Hz\) to \(10.71 \times 10^{14} \ Hz\).
04

Understanding Wave Number Calculation

Wave number \( k \) is the reciprocal of the wavelength in meters, \( k = \frac{1}{\lambda} \). To find the wave number ranges, we will calculate \( k \) for each boundary of the UVA and UVB wavelengths.
05

Calculate UVA Wave Number Range

For UVA, the wavelengths are \(320 \mathrm{nm}\) to \(400 \mathrm{nm}\).For \(400 \mathrm{nm}\):\[k = \frac{1}{400 \times 10^{-9} \ m} = 2.5 \times 10^6 \ m^{-1}\]For \(320 \mathrm{nm}\):\[k = \frac{1}{320 \times 10^{-9} \ m} = 3.125 \times 10^6 \ m^{-1}\]Thus, the wave number range for UVA is from \(2.5 \times 10^6 \ m^{-1}\) to \(3.125 \times 10^6 \ m^{-1}\).
06

Calculate UVB Wave Number Range

For UVB, the wavelengths are \(280 \mathrm{nm}\) to \(320 \mathrm{nm}\).For \(320 \mathrm{nm}\):\[k = \frac{1}{320 \times 10^{-9} \ m} = 3.125 \times 10^6 \ m^{-1}\]For \(280 \mathrm{nm}\):\[k = \frac{1}{280 \times 10^{-9} \ m} = 3.57 \times 10^6 \ m^{-1}\]Thus, the wave number range for UVB is from \(3.125 \times 10^6 \ m^{-1}\) to \(3.57 \times 10^6 \ m^{-1}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength
In physics, a wavelength is a key characteristic of any wave and describes the distance between consecutive peaks of a wave. It's usually measured in nanometers (nm) for light waves. For ultraviolet light, different wavelengths characterize UVA and UVB light. The UVA range is between 320 nm to 400 nm, while UVB is between 280 nm to 320 nm. Understanding these ranges is crucial because the shorter the wavelength, the more energy the wave carries, which accounts for the varying effects these light types have on skin health.

In simpler terms, think of wavelength as the size of the ripples in a pond. Bigger waves take longer to complete a cycle, while smaller ripples represent higher energy waves that can potentially carry more impact, as with UVB.
Frequency Calculation
Frequency refers to the number of waves that pass a given point per second, measured in hertz (Hz). To find it, we use the formula \( u = \frac{c}{\lambda} \), where \( c \) is the speed of light \( (3 \times 10^8 \, m/s) \) and \( \lambda \) is the wavelength. This formula shows the inverse relationship between frequency and wavelength: shorter wavelengths mean higher frequencies.

For UVA and UVB, the frequency calculation allows us to see why UVB rays are potentially more harmful. The ranges are:
  • **UVA:** \(7.5 \times 10^{14} \, Hz\) to \(9.375 \times 10^{14} \, Hz\)
  • **UVB:** \(9.375 \times 10^{14} \, Hz\) to \(10.71 \times 10^{14} \, Hz\)
This illustrates that UVB has a higher frequency, thus more energy per photon, which is why it poses a greater risk to skin health.
Wave Number
The wave number is another way to specify wave properties. It represents the number of waves per unit distance and is calculated as \( k = \frac{1}{\lambda} \), with \( \lambda \) in meters. The unit for wave number is reciprocal meters (m^{-1}).

For UV light, calculating the wave number for UVA and UVB gives us an idea of how dense the wave is in a given space. The denser the waves, the higher the energy density, contributing to UVA and UVB's different effects. The wave number ranges:
  • **UVA:** \(2.5 \times 10^6 \, m^{-1}\) to \(3.125 \times 10^6 \, m^{-1}\)
  • **UVB:** \(3.125 \times 10^6 \, m^{-1}\) to \(3.57 \times 10^6 \, m^{-1}\)
Seeing these numbers, you notice UVB is packed more densely with waves, aligning with its higher energy characteristics.
UVA and UVB
Ultraviolet (UV) light is divided into two primary categories: UVA and UVB, based on differences in wavelength. While both types originate from the sun, their effects on the skin vary because of their different energy levels.

**UVA**:
- Longer wavelengths (320 to 400 nm)
- Less energetic per photon than UVB
- Vital for vitamin D synthesis
- Larger presence in sunlight exposure

**UVB**:
- Shorter wavelengths (280 to 320 nm)
- More energetic, capable of causing skin damage like sunburn and skin cancer

Protecting oneself from UVB is crucial due to its higher energy and potential to cause harm, unlike the beneficial aspects of UVA when exposure is controlled.
Physics Problem Solving
When faced with physics problems involving concepts like wavelengths, frequencies, and wave numbers, breaking down each step can simplify complex ideas:
  • **Understand relationships:** Knowing formulas such as \( u = \frac{c}{\lambda} \) helps relate frequency and wavelength effortlessly.
  • **Unit Conversion:** Often, converting units from nanometers to meters is necessary, as consistency in units is key for accurate calculations.
  • **Logical Steps:** Divide the problem into smaller parts. Calculate one aspect (e.g., frequency) before moving on to another (e.g., wave number).
  • **Cross-Check Results:** Ensuring each step is correct can prevent errors, particularly important in higher-level physics.
Approaching physics with a step-by-step methodology makes even challenging problems more manageable and can strengthen your understanding of key principles.

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Most popular questions from this chapter

Laser surgery. Very short pulses of high-intensity laser beams are used to repair detached portions of the retina of the eye. The brief pulses of energy absorbed by the retina weld the detached portion back into place. In one such procedure, a laser beam has a wavelength of \(810 \mathrm{nm}\) and delivers \(250 \mathrm{~mW}\) of power spread over a circular spot \(510 \mu \mathrm{m}\) in diameter. The vitreous humor (the transparent fluid that fills most of the eye) has an index of refraction of \(1.34 .\) (a) If the laser pulses are each \(1.50 \mathrm{~ms}\) long, how much energy is delivered to the retina with each pulse? (b) What average pressure does the pulse of the laser beam exert on the retina as it is fully absorbed by the circular spot? (c) What are the wavelength and frequency of the laser light inside the vitreous humor of the eye? (d) What are the maximum values of the electric and magnetic fields in the laser beam?

A radio broadcasts at a wavelength of \(3.06 \mathrm{~m}\). Near the broadcast tower the electric-field amplitude is \(2700 \mathrm{~N} / \mathrm{C}\). Calculate (a) the frequency, (b) the wave number, and (c) the magnetic-field amplitude of the electromagnetic wave.

Physicians use high-frequency \((f=1 \mathrm{MHz}\) to \(5 \mathrm{MHz}\) ) sound waves, called ultrasound, to image internal organs. The speed of these ultrasound waves is \(1480 \mathrm{~m} / \mathrm{s}\) in muscle and \(344 \mathrm{~m} / \mathrm{s}\) in air. We define the index of refraction of a material for sound waves to be the ratio of the speed of sound in air to the speed of sound in the material. Snell's law then applies to the refraction of sound waves. (a) At what angle from the normal does an ultrasound beam enter the heart if it leaves the lungs at an angle of \(9.73^{\circ}\) from the normal to the heart wall? (Assume that the speed of sound in the lungs is \(344 \mathrm{~m} / \mathrm{s} .)\) (b) What is the critical angle for sound waves in air incident on muscle?

A powerful searchlight shines on a man. The man's cross-sectional area is \(0.500 \mathrm{~m}^{2}\) perpendicular to the light beam, and the intensity of the light at his location is \(36.0 \mathrm{~kW} / \mathrm{m}^{2}\). He is wearing black clothing, so that the light incident on him is totally absorbed. What is the magnitude of the force the light beam exerts on the man? Do you think he could sense this force?

He-Ne lasers are often used in physics demonstrations. They produce light of wavelength \(633 \mathrm{nm}\) and a power of \(0.500 \mathrm{~mW}\) spread over a cylindrical beam \(1.00 \mathrm{~mm}\) in diameter (although these quantities can vary). (a) What is the intensity of this laser beam? (b) What are the maximum values of the electric and magnetic fields? (c) What is the average energy density in the laser beam?

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