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In a series \(R-L-C\) circuit, \(R=400 \Omega, L=0.350 \mathrm{H},\) and \(C=0.0120 \mu \mathrm{F}\). (a) What is the resonance angular frequency of the circuit? (b) The capacitor can withstand a peak voltage of \(550 \mathrm{~V}\). If the voltage source operates at the resonance frequency, what maximum voltage amplitude can it have if the maximum capacitor voltage is not exceeded?

Short Answer

Expert verified
(a) Resonance angular frequency is \(8,529 \, \mathrm{rad/s}\). (b) Maximum voltage amplitude is \(22.72 \, \mathrm{V}\).

Step by step solution

01

Identify Resonance Condition

In a series \(R-L-C\) circuit, resonance occurs when the inductive reactance \(X_L\) is equal to the capacitive reactance \(X_C\). This happens at the resonance angular frequency given by \(\omega_0 = \frac{1}{\sqrt{LC}}\).
02

Calculate Resonance Angular Frequency

Given \(L = 0.350 \, \mathrm{H}\) and \(C = 0.0120 \, \mu\mathrm{F} = 0.0120 \times 10^{-6} \, \mathrm{F}\), the resonance angular frequency is: \[ \omega_0 = \frac{1}{\sqrt{0.350 \times 0.0120 \times 10^{-6}}} \approx 8,529 \, \mathrm{rad/s}. \]
03

Understand Maximum Voltage Condition

At resonance, the current is limited only by the resistance \(R\), and the voltage across the capacitor can be much higher than the source voltage. The maximum voltage across the capacitor \(V_C\) is related to the maximum current \(I\) and angular frequency by \(V_C = I \cdot X_C\), where \(X_C = \frac{1}{\omega C}\).
04

Calculate Capacitive Reactance

The capacitive reactance at resonance is \(X_C = \frac{1}{\omega_0 C}\). Substituting the values, \[ X_C = \frac{1}{8,529 \times 0.0120 \times 10^{-6}} \approx 9,689 \, \Omega. \]
05

Calculate Maximum Current

The maximum current \(I\) at peak capacitor voltage (\(550 \, \mathrm{V}\)) is given by \(I = \frac{V_C}{X_C}\). So, \[ I = \frac{550}{9,689} \approx 0.0568 \, \mathrm{A}. \]
06

Calculate Maximum Voltage Amplitude

The source voltage at resonance is \(V_s = I \times R\). Thus, \[ V_s = 0.0568 \times 400 \approx 22.72 \, \mathrm{V}. \] This is the maximum amplitude for the source voltage without exceeding the capacitor's peak voltage.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

RLC Circuit
An RLC circuit is an electrical circuit composed of a resistor (R), an inductor (L), and a capacitor (C), connected in series or parallel. The "RLC" stands for Resistor, Inductor, and Capacitor, which are these circuit's three main components. In the case of a series RLC circuit, the components are connected end to end, forming a complete closed loop. This setup allows currents to flow through in a series manner.

The main characteristic of an RLC circuit is the ability to resonate at a specific frequency, known as the resonance frequency. At this frequency, the inductive and capacitive reactances cancel each other out, minimizing the circuit's overall impedance to just the resistance component. This behavior makes RLC circuits critical in applications like radio transmissions, filters, and frequency tuning.
  • At resonance, energy is optimally transferred through the components.
  • Used in devices needing precise frequency selection.
  • Combines the properties of all three components to control current and voltage in the circuit.
Angular Frequency
Angular frequency, often denoted by the symbol \(\omega\), represents how quickly an object rotates or oscillates, measuring in radians per second. It is a crucial concept when dealing with oscillating systems such as RLC circuits, as it defines the speed at which the circuit oscillates at any given time.

In the context of an RLC circuit, the resonance angular frequency is particularly important. It is the frequency at which the inductive reactance and capacitive reactance are equal, leading to resonance. The formula for calculating this frequency in a series RLC circuit is given by:\[ \omega_0 = \frac{1}{\sqrt{LC}} \]
  • Measured in radians per second.
  • Critical for understanding oscillatory behavior in circuits.
  • Indicates the natural frequency of oscillation for a system.
Inductive Reactance
Inductive reactance is a measure of the opposition that an inductor gives to the flow of alternating current (AC), due to its inherent property of self-induction. Inductance (the ability to store energy in a magnetic field) causes the current to lag the voltage in an AC circuit. This reactance increases with the frequency of the current because the opposition to the change in current flow builds up more strongly. It is represented by \(X_L\) and is given by:\[ X_L = \omega L \]

Where \(\omega\) is the angular frequency, and \(L\) is the inductance in henrys (H). In RLC circuits:
  • Inductive reactance is directly proportional to frequency.
  • Presents a positive reactance in the circuit.
  • Affects how current and voltage interact over time.
Capacitive Reactance
Capacitive reactance acts as the opposite of inductive reactance. It measures the opposition that a capacitor presents to AC. Capacitors allow AC to flow more easily as the frequency increases, since the capacitive reactance decreases with increasing frequency. This creates a phase shift where the current leads the voltage in the circuit. It is represented by \(X_C\) and can be calculated by:\[ X_C = \frac{1}{\omega C} \]

Where \(\omega\) is the angular frequency, and \(C\) is the capacitance in farads (F). In resonance conditions:
  • Capacitive reactance decreases as frequency increases.
  • Contributes a negative reactance to the circuit.
  • Balances with inductive reactance at resonance, canceling out the total reactance.

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Most popular questions from this chapter

A \(2.20 \mu \mathrm{F}\) capacitor is connected across an ac source whose voltage amplitude is kept constant at \(60.0 \mathrm{~V}\), but whose frequency can be varied. Find the current amplitude when the angular frequency is (a) \(100 \mathrm{rad} / \mathrm{s} ;\) (b) \(1000 \mathrm{rad} / \mathrm{s} ;\) (c) \(10,000 \mathrm{rad} / \mathrm{s}\).

A series \(R-L-C\) circuit is connected to a \(120 \mathrm{~Hz}\) ac source that has \(V_{\mathrm{rms}}=80.0 \mathrm{~V}\). The circuit has a resistance of \(75.0 \Omega\) and an impedance of \(105 \Omega\) at this frequency. What average power is delivered to the circuit by the source?

An electrical engineer is designing an \(R-L-C\) circuit for use in a ham radio receiver. He is unsure of the value of the inductance in the circuit, so he measures the resonant frequency of his circuit using a few different values of capacitance. The data he obtains are shown in the table. $$ \begin{array}{cc} \hline \text { Capacitance (nF) } & \text { Frequency (kHz) } \\ \hline 0.2 & 560 \\ 0.4 & 395 \\ 0.7 & 300 \\ 1.0 & 250 \\ \hline \end{array} $$ Make a linearized graph of the data by plotting the square of the resonance frequency as a function of the inverse of the capacitance. Using a linear "best fit" to the data, determine the inductance of his circuit.

In a series \(R-L-C\) circuit, \(L=0.200 \mathrm{H}, C=80.0 \mu \mathrm{F},\) and the voltage amplitude of the source is \(240 \mathrm{~V}\). (a) What is the resonance angular frequency of the circuit? (b) When the source operates at the resonance angular frequency, the current amplitude in the circuit is 0.600 A. What is the resistance \(R\) of the resistor? (c) At the resonance frequency, what are the peak voltages across the inductor, the capacitor, and the resistor?

A \(100.0 \Omega\) resistor, a \(0.100 \mu \mathrm{F}\) capacitor, and a \(300.0 \mathrm{mH}\) inductor are connected in series to a voltage source with amplitude \(240 \mathrm{~V}\). (a) What is the resonance angular frequency? (b) What is the maximum current in the resistor at resonance? (c) What is the maximum voltage across the capacitor at resonance? (d) What is the maximum voltage across the inductor at resonance? (e) What is the maximum energy stored in the capacitor at resonance? In the inductor?

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