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Suppose that you drop a marble from the top of the Burj Khalifa building in Dubai, which is about \(830 \mathrm{~m}\) tall. If you ignore air resistance, (a) how long will it take for the marble to hit the ground? (b) How fast will it be moving just before it hits?

Short Answer

Expert verified
(a) 13 seconds, (b) 127.4 m/s.

Step by step solution

01

Identifying the Known Values

We know the height from which the marble is dropped, which is \( h = 830 \) m. The initial velocity \( u = 0 \) m/s since it is dropped. The acceleration due to gravity \( g = 9.8 \) m/s² (assuming no air resistance).
02

Calculating the Time to Hit the Ground

We will use the kinematic equation \( h = ut + \frac{1}{2}gt^2 \) where \( u = 0 \) m/s. This simplifies to \( h = \frac{1}{2}gt^2 \). Substituting the known values: \( 830 = \frac{1}{2} \times 9.8 \times t^2 \). Solving for \( t \), we get \[ t^2 = \frac{830 \times 2}{9.8} \ \approx 169.39 \]. Thus, \( t \approx 13 \) seconds.
03

Calculating the Final Velocity

Use the kinematic equation \( v = u + gt \). Since the initial velocity \( u = 0 \), the equation simplifies to \( v = gt \). Substituting the known values: \( v = 9.8 \times 13 \ \approx 127.4 \) m/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration Due to Gravity
The acceleration due to gravity, often represented by the symbol \( g \), is the rate at which an object accelerates when it is falling freely toward Earth. On our planet, this value is approximately \( 9.8 \text{ m/s}^2 \). This means that every second, the velocity of a freely falling object increases by \( 9.8 \text{ m/s} \).
When calculating problems involving objects under free fall, we generally assume that air resistance is negligible. This simplifies our calculations and allows us to rely on the constant value of gravity. This concept is crucial in understanding the motion of objects not only on Earth but also helps in studying celestial bodies. Many physics problems start by identifying this constant to predict how objects move under the influence of gravity.
Free Fall
Free fall is a special kind of motion that occurs when only gravity is acting on an object. When an object is in free fall, it does not encounter air resistance or external forces.
Imagine dropping a marble from a tall building like the Burj Khalifa. At the moment it leaves your hand, it's in free fall if air resistance is ignored. In this condition:
  • The only force acting on it is the gravitational pull.
  • Its initial velocity is zero if you simply let go of it.
  • It accelerates continuously at the rate of gravity \( g \), which is \( 9.8 \text{ m/s}^2 \) on Earth.
Understanding the principles of free fall is essential in physics because it provides a basis for analyzing more complex motions when other forces come into play.
Motion Equations
To analyze the motion of objects, such as a marble being dropped from a great height, we utilize motion equations, specifically the kinematic equations. These help us describe motion mathematically without needing to delve into the reasons behind it.
One key equation is used to determine the time it takes an object to reach the ground, and another is used to find its final velocity just before impact. Here's how they both look:
  • To find time \( t \), we use \( h = \frac{1}{2}gt^2 \). Solving for \( t \) gives us the time it takes for a free-falling object to hit the ground from a known height \( h \).
  • To find the final velocity \( v \) just before it hits the ground, we use \( v = gt \).
The simplicity of these equations allows us to solve complex motion problems with minimal input data. By measuring the height and using the constant acceleration due to gravity, predicting the outcome of a free fall experiment becomes straightforward.

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Most popular questions from this chapter

According to recent typical test data, a Ford Focus travels \(0.250 \mathrm{mi}\) in \(19.9 \mathrm{~s},\) starting from rest. The same car, when braking from \(60.0 \mathrm{mi} / \mathrm{h}\) on dry pavement, stops in \(146 \mathrm{ft}\). Assume constant acceleration in each part of its motion, but not necessarily the same acceleration when slowing down as when speeding up. (a) Find this car's acceleration while braking and while speeding up. (b) If its acceleration is constant while speeding up, how fast (in \(\mathrm{mi} / \mathrm{h}\) ) will the car be traveling after \(0.250 \mathrm{mi}\) of acceleration? (c) How long does it take the car to stop while braking from \(60.0 \mathrm{mi} / \mathrm{h} ?\)

Two rockets having the same acceleration start from rest, but rocket \(A\) travels for twice as much time as rocket \(B\). (a) If rocket \(A\) goes a distance of \(250 \mathrm{~km}\), how far will rocket \(B\) go? (b) If rocket \(A\) reaches a speed of \(350 \mathrm{~m} / \mathrm{s},\) what speed will rocket \(B\) reach?

A jet fighter pilot wishes to accelerate from rest at \(5 g\) to reach Mach 3 (three times the speed of sound) as quickly as possible. Experimental tests reveal that he will black out if this acceleration lasts more than 5.0 s. Use \(331 \mathrm{~m} / \mathrm{s}\) for the speed of sound. (a) Will the period of acceleration last long enough to cause him to black out? (b) What is the greatest speed he can reach with an acceleration of \(5 g\) before blacking out?

You and your family take a trip to see your aunt who lives 100 miles away along a straight highway. The first 60 miles of the trip are driven at \(55 \mathrm{mi} / \mathrm{h}\) but then you get stuck in a standstill traffic jam for 20 minutes. In order to make up time, you then proceed at \(75 \mathrm{mi} / \mathrm{h}\) for the rest of the trip. What is the magnitude of your average velocity for the whole trip?

Starting from rest, a boulder rolls down a hill with constant acceleration and travels \(2.00 \mathrm{~m}\) during the first second. (a) How far does it travel during the second second? (b) How fast is it moving at the end of the first second? at the end of the second second?

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