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(a) The pilot of a jet fighter will black out at an acceleration greater than approximately \(5 g\) if it lasts more than a few seconds. Express this acceleration in \(\mathrm{m} / \mathrm{s}^{2}\) and \(\mathrm{ft} / \mathrm{s}^{2} .\) (b) The acceleration of the passenger during a car crash with an air bag is about \(60 g\) for a very short time. What is this acceleration in \(\mathrm{m} / \mathrm{s}^{2}\) and \(\mathrm{ft} / \mathrm{s}^{2} ?\) (c) The acceleration of a falling body on our moon is \(1.62 \mathrm{~m} / \mathrm{s}^{2}\). How many \(g^{\prime} \mathrm{s}\) is this? (d) If the acceleration of a test plane is \(24.3 \mathrm{~m} / \mathrm{s}^{2},\) how many \(g\) 's is it?

Short Answer

Expert verified
(a) 49.05 m/s虏, 160.95 ft/s虏; (b) 588.6 m/s虏, 1930.97 ft/s虏; (c) 0.165 g's; (d) 2.48 g's.

Step by step solution

01

Convert acceleration from g to m/s虏 for jet fighter pilot

We know 1g is equivalent to the acceleration due to Earth's gravity, which is approximately 9.81 m/s虏. Therefore, if the pilot will black out at an acceleration of about 5g, we calculate this as: \[5 \times 9.81 = 49.05 \text{ m/s}^2\]
02

Convert acceleration from g to ft/s虏 for jet fighter pilot

To convert the acceleration from m/s虏 to ft/s虏, we use the conversion factor where 1 m/s虏 is approximately 3.281 ft/s虏:\[49.05 \times 3.281 = 160.95 \text{ ft/s}^2\]
03

Convert acceleration from g to m/s虏 for car crash with air bag

1g is 9.81 m/s虏. Therefore, for an acceleration of 60g, the calculation is:\[60 \times 9.81 = 588.6 \text{ m/s}^2\]
04

Convert acceleration from g to ft/s虏 for car crash with air bag

To convert the acceleration from m/s虏 to ft/s虏, use the conversion factor of 3.281 ft/s虏 per m/s虏:\[588.6 \times 3.281 = 1930.97 \text{ ft/s}^2\]
05

Determine g's for the moon's gravity

Given the acceleration due to gravity on the moon as 1.62 m/s虏 and knowing that 1g is 9.81 m/s虏, we calculate the equivalent in g's:\[\frac{1.62}{9.81} \approx 0.165 \text{ g's}\]
06

Determine g's for test plane acceleration

Given an acceleration of 24.3 m/s虏 and 1g as 9.81 m/s虏, calculate the number of g's:\[\frac{24.3}{9.81} \approx 2.48 \text{ g's}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravity
Gravity is a fundamental force that pulls objects towards the center of a massive body, like a planet or the moon. This force gives weight to physical objects and is crucial in our daily lives. On Earth, the acceleration due to gravity is approximately 9.81 meters per second squared (m/s虏). This means that an object鈥檚 velocity increases by about 9.81 m/s every second as it falls.

Understanding gravity's role is essential in various fields, including physics, astronomy, and engineering. For instance, when astronauts travel to the moon, they experience a change in gravitational pull because the moon's gravity is weaker than Earth's.
Bullet Points:
  • Gravity pulls objects towards the center of mass.
  • On Earth, gravity causes a force of about 9.81 m/s虏.
  • The moon's gravity is weaker than Earth's.
Unit Conversion
Unit conversion is one of the most important skills in science and engineering. It involves changing a measurement from one unit to another to facilitate calculations and comparisons. Today, units are standardized by international agreements, which aids global communication and consistency.

In physics problems like those involving acceleration, converting between units like meters per second squared (m/s虏) and feet per second squared (ft/s虏) is common. For example, knowing 1 m/s虏 is approximately equal to 3.281 ft/s虏 helps convert metrics depending on the project's needs or regional standards.
Practical Tips:
  • Always know your conversion factors.
  • Double-check your unit conversions to avoid errors.
  • Use dimensional analysis as a method to confirm conversions are correct.
Physics Problems
Physics problems often challenge us to apply mathematical concepts to understand physical phenomena. These problems can range from analyzing motion and forces to exploring energy and momentum. To solve them, it鈥檚 crucial to have a systematic approach.

Start by identifying what you know and need to find. Apply the correct physics principles and formulas, solve using algebra, and don鈥檛 forget the units! Solving such problems enhances problem-solving skills, logical thinking, and the ability to connect different concepts.
Steps for Success:
  • Identify knowns and unknowns.
  • Choose the correct formula based on physical concepts.
  • Solve algebraically and check units.
Jet Fighter Pilot
A jet fighter pilot experiences extreme conditions and needs to be aware of accelerations that could affect their health. At accelerations above approximately 5g, a pilot can blackout. This is due to the blood flow being unable to keep up with the high gravitational forces, affecting brain function.

Pilots undergo rigorous training to handle high "g" forces. Jet fighters are also designed to manage these intense conditions. Understanding how to convert these forces into different units helps in mechanical engineering and health safety assessments.
Key Points:
  • Pilots face extreme forces that can affect consciousness.
  • Understanding acceleration helps in fighter jet design.
  • Training is essential to endure high g-forces safely.
Car Crash Safety
Car crash safety is a critical field where understanding acceleration and "g" forces plays a significant role, especially during collisions. In a crash, passengers can experience extremely high accelerations, sometimes exceeding 60g. Car safety features, like airbags and seatbelts, are designed to mitigate these forces.

Engineers must calculate these forces in m/s虏 and ft/s虏 to design effective safety systems. Reducing the force experienced by passengers increases their chances of surviving severe crashes without injuries.
Safety Features:
  • Airbags help reduce impact force.
  • Seatbelts prevent ejection from the vehicle.
  • Crush zones absorb collision energy.
Moon Gravity
Moon gravity is significantly weaker than Earth's gravity, at about 1.62 m/s虏. This difference is crucial for astronauts and scientists studying lunar conditions. Understanding moon gravity is essential for navigation, construction, and even for movements of astronauts in space missions.

In terms of 鈥済's,鈥 the moon鈥檚 gravity is only about 0.165 times that of Earth's. This lessened gravity affects everything from launching a spacecraft to how an astronaut walks and performs tasks on the lunar surface.
Important Aspects:
  • Moon gravity is about 1/6th of Earth's.
  • Affects how we plan space missions.
  • Influences the physical activities of astronauts.
Test Plane Acceleration
Test planes are used to push the limits of speed and maneuverability. Understanding acceleration is vital for pilots and engineers. A test plane may accelerate at high rates, for example, 24.3 m/s虏. When considering safety and design, it鈥檚 necessary to convert this into "g" forces, as it equates to about 2.48g.

This conversion helps in understanding what pilots will physically experience and ensures that the planes are engineered to withstand these forces. Monitoring these conditions is essential for pilot safety and for pushing the boundaries of aviation technology.
Notable Points:
  • High acceleration helps test aircraft capabilities.
  • Conversion to g's aids in understanding human impact.
  • Engineering must accommodate high g-forces

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Most popular questions from this chapter

An electric drag racer is much like its piston engine counterpart, but instead it is powered by an electric motor running off of onboard batteries. These vehicles are capable of covering a \(\frac{1}{4}\) mile straight-line track in \(10 \mathrm{~s}\). (a) Determine the acceleration of the drag racer in units of \(\mathrm{m} / \mathrm{s}\). (Assume that the acceleration is constant throughout the race.) (b) How does the value you get compare with the acceleration of gravity? (c) Calculate the final speed of the drag racer in \(\mathrm{mi} / \mathrm{h}\).

The Beretta Model \(92 \mathrm{~S}\) (the standard-issue U.S. army pistol) has a barrel \(127 \mathrm{~mm}\) long. The bullets leave this barrel with a muzzle velocity of \(335 \mathrm{~m} / \mathrm{s}\). (a) What is the acceleration of the bullet while it is in the barrel, assuming it to be constant? Express your answer in \(\mathrm{m} / \mathrm{s}^{2}\) and in \(g^{\prime}\) s. (b) For how long is the bullet in the barrel?

Two bicyclists start a sprint from rest, each riding with a constant acceleration. Bicyclist \(A\) has twice the acceleration of bicyclist \(B ;\) however, bicyclist \(B\) rides for twice as long as bicyclist \(A\). What is the ratio of the distance traveled by bicyclist \(A\) to that traveled by bicyclist \(B\) ? What is the ratio of the speed of bicyclist \(A\) to that of bicyclist \(B\) at the end of their sprint?

A tennis ball on Mars, where the acceleration due to gravity is \(0.379 g\) and air resistance is negligible, is hit directly upward and returns to the same level \(8.5 \mathrm{~s}\) later. (a) How high above its original point did the ball go? (b) How fast was it moving just after being hit? (c) Sketch clear graphs of the ball's vertical position, vertical velocity, and vertical acceleration as functions of time while it's in the Martian air.

An elite human sprinter reaches his top speed of \(11.8 \mathrm{~m} / \mathrm{s}\) at a time of \(7.02 \mathrm{~s}\) after the starting gun. In the first \(1.40 \mathrm{~s},\) however, he reaches a speed of \(8.00 \mathrm{~m} / \mathrm{s}\) with a nearly constant acceleration. Calculate (a) his maximum acceleration during the starting phase and (b) his average acceleration to top speed. (c) Assuming constant acceleration for the first \(1.40 \mathrm{~s}\), how far does he travel during that time?

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