/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 In the air we breathe at \(72^{\... [FREE SOLUTION] | 91Ó°ÊÓ

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In the air we breathe at \(72^{\circ} \mathrm{F}\) and 1.0 atm pressure, how many molecules does a typical cubic centimeter contain, assuming that the air is all \(\mathrm{N}_{2} ?\)

Short Answer

Expert verified
A cubic centimeter of air at 72°F and 1 atm contains approximately 2.48 x 10^19 molecules.

Step by step solution

01

Understand the Ideal Gas Law

We use the ideal gas law to find the number of molecules in a given volume. The ideal gas law is given by the formula \( PV = nRT \), where \( P \) is the pressure, \( V \) is the volume, \( n \) is the number of moles, \( R \) is the ideal gas constant, and \( T \) is the temperature in Kelvin.
02

Convert Temperature to Kelvin

The temperature provided is in Fahrenheit, so we need to convert it to Kelvin. The conversion formula from Fahrenheit to Celsius is: \( °C = (°F - 32) \times \frac{5}{9} \). Thus, \( 72°F = (72-32) \times \frac{5}{9} = 22.22°C \). Now convert Celsius to Kelvin using \( K = °C + 273.15 \), which gives \( 22.22°C + 273.15 = 295.37 \text{ K} \).
03

Understand the Variables

We know the pressure \( P = 1.0 \text{ atm} \), volume \( V = 1.0 \text{ cm}^3 = 1.0 \times 10^{-3} \text{ L} \) (since there are 1000 cm³ in a liter), \( T = 295.37 \text{ K} \) from previous conversion, and \( R \) can be used as \( 0.0821 \text{ atm·L/mol·K} \).
04

Solve for Number of Moles (n)

Using the ideal gas law, \( n = \frac{PV}{RT} \). Substitute the known values: \( n = \frac{1.0 \times 1.0 \times 10^{-3}}{0.0821 \times 295.37} = \frac{1.0 \times 10^{-3}}{24.252237} \approx 4.123 \times 10^{-5} \text{ moles} \).
05

Calculate Number of Molecules

Using Avogadro's number, which is \( 6.022 \times 10^{23} \text{ molecules/mol} \), multiply by the moles of nitrogen to find the number of molecules: \( 4.123 \times 10^{-5} \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mol} \approx 2.48 \times 10^{19} \text{ molecules} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Avogadro's Number
Avogadro's Number is a crucial concept in chemistry and physics when dealing with gases, as it represents the number of constituent particles (usually atoms or molecules) in one mole of a substance. This constant is approximately \( 6.022 \times 10^{23} \), meaning that one mole of any substance contains exactly this number of molecules or atoms.
It's named after Amedeo Avogadro, who introduced this concept to distinguish atoms and molecules in gaseous substances. When using the Ideal Gas Law to calculate things like the number of molecules in a gas, Avogadro's Number allows us to convert from moles of a substance to number of particles.
This conversion is vital when you want real-world numbers of molecules, as seen in our exercise where understanding the count of nitrogen molecules in a cubic centimeter of air is achieved by multiplying the moles by Avogadro's number.
Temperature Conversion
Temperature Conversion is an important step in many scientific calculations since different scales of temperature can impact the outcomes. The key to the Ideal Gas Law is that temperature must be in Kelvin, as this scale starts at absolute zero, providing a natural baseline for thermodynamic calculations.
Converting from Fahrenheit to Celsius involves subtracting 32 and then multiplying by \( \frac{5}{9} \). After that, converting from Celsius to Kelvin requires adding 273.15. These conversions ensure that temperature is compatible with units used in gas law formulas.
For example, in the exercise, we convert \( 72^{\circ} \mathrm{F} \) to \( 295.37 \mathrm{K} \), allowing us to correctly use the Ideal Gas Law to find the number of moles of nitrogen gas in the given volume.
Number of Molecules
To find the Number of Molecules in a gas sample, we first need to determine the number of moles of the gas using the Ideal Gas Law. This involves using the formula \( n = \frac{PV}{RT} \) where \( n \) is the number of moles. Once we have the number of moles, Avogadro's Number is used to calculate the actual number of molecules.
This calculation is significant because it moves from a macroscopic scale (moles) to a microscopic one (molecules), helping us understand how many actual particles are present. In the provided exercise, we found approximately \( 2.48 \times 10^{19} \) molecules of nitrogen in a cubic centimeter of air, showcasing how small yet numerous these gas molecules are.
Understanding these conversions and calculations is essential in fields ranging from chemistry to environmental science, where precise molecule counts can be crucial.
Pressure and Volume in Gases
Pressure and Volume in Gases are key variables in the Ideal Gas Law, which allows us to understand the behavior of gases under different conditions. Pressure (\( P \)) is the force exerted by the gas molecules against the walls of its container, often measured in atmospheres (atm). Volume (\( V \)) is the space that the gas occupies, usually measured in liters.
The Ideal Gas Law formula \( PV = nRT \) shows the relationship between these variables. It tells us that for a given mass of gas at constant temperature, the product of its pressure and volume is constant.
This principle helps explain why gases expand to fill their containers and why pressure increases when gases are compressed. In our exercise, the calculation uses \( 1.0 \text{ atm} \) and \( 1.0 \times 10^{-3} \text{ L} \) (since we're converting from cubic centimeters to liters), which illustrates how these concepts apply in real-world calculations.

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Most popular questions from this chapter

Suppose you do \(457 \mathrm{~J}\) of work on 1.18 moles of ideal He gas in a perfectly insulated container. By how much does the internal energy of this gas change? Does it increase or decrease?

Starting with \(2.50 \mathrm{~mol}\) of \(\mathrm{N}_{2}\) gas (assumed to be ideal) in a cylinder at 1.00 atm and \(20.0^{\circ} \mathrm{C}\), a chemist first heats the gas at constant volume, adding \(1.52 \times 10^{4} \mathrm{~J}\) of heat, then continues heating and allows the gas to expand at constant pressure to twice its original volume. (a) Calculate the final temperature of the gas. (b) Calculate the amount of work done by the gas. (c) Calculate the amount of heat added to the gas while it was expanding. (d) Calculate the change in internal energy of the gas for the whole process.

In a certain chemical process, a lab technician supplies \(254 \mathrm{~J}\) of heat to a system. At the same time, \(73 \mathrm{~J}\) of work are done on the system by its surroundings. What is the increase in the internal energy of the system?

A \(20.0 \mathrm{~L}\) tank contains \(0.225 \mathrm{~kg}\) of helium at \(18.0^{\circ} \mathrm{C}\). The molar mass of helium is \(4.00 \mathrm{~g} / \mathrm{mol}\). (a) How many moles of helium are in the tank? (b) What is the pressure in the tank, in pascals and in atmospheres?

The gas inside a balloon will always have a pressure nearly equal to atmospheric pressure, since that is the pressure applied to the outside of the balloon. You fill a balloon with helium (a nearly ideal gas) to a volume of \(0.600 \mathrm{~L}\) at a temperature of \(19.0^{\circ} \mathrm{C}\). What is the volume of the balloon if you cool it to the boiling point of liquid nitrogen \((77.3 \mathrm{~K}) ?\)

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