/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 A diver observes a bubble of air... [FREE SOLUTION] | 91Ó°ÊÓ

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A diver observes a bubble of air rising from the bottom of a lake (where the absolute pressure is 3.50 atm) to the surface (where the pressure is \(1.00 \mathrm{~atm}\) ). The temperature at the bottom is \(4.0^{\circ} \mathrm{C}\) and the temperature at the surface is \(23.0^{\circ} \mathrm{C}\). (a) What is the ratio of the volume of the bubble as it reaches the surface to its volume at the bottom? (b) Would it be safe for the diver to hold his breath while ascending from the bottom of the lake to the surface? Why or why not?

Short Answer

Expert verified
The volume ratio is approximately 3.74. It is unsafe to hold breath while ascending due to risk of lung expansion.

Step by step solution

01

Understand the Problem

We need to calculate the ratio of the volume of an air bubble when it reaches the surface of a lake to its volume at the bottom. This problem involves understanding changes in pressure and temperature. We will use the Ideal Gas Law in a comparative form to determine this ratio.
02

Recall the Ideal Gas Law

The Ideal Gas Law is given by \( PV = nRT \). In this problem, the number of moles \( n \) and the universal gas constant \( R \) are constant, so we can consider the relation \( \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \).
03

Set Initial Conditions

Let \( P_1 = 3.50 \) atm, \( V_1 \) be the initial volume (at the bottom), and \( T_1 = 4.0^\circ \text{C} = 277 \) K after converting Celsius to Kelvin by adding 273. Similarly, \( P_2 = 1.00 \) atm and \( T_2 = 23.0^\circ \text{C} = 296 \) K.
04

Apply the Comparative Gas Law

Using the relation \( \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \), we can solve for \( \frac{V_2}{V_1} \): \[ \frac{3.50 \, V_1}{277} = \frac{1.00 \, V_2}{296} \]Rearrange this to find:\[ \frac{V_2}{V_1} = \frac{3.50 \times 296}{1.00 \times 277} \]
05

Calculate the Volume Ratio

Substitute the values and compute the ratio:\[ \frac{V_2}{V_1} = \frac{3.50 \times 296}{277} \approx \frac{1036}{277} \approx 3.74 \]
06

Answer Part (b) of the Question

It would not be safe for the diver to hold their breath while ascending. As the bubble expands due to decreasing pressure and increasing temperature, the air in the diver's lungs would also expand, potentially causing lung damage.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Boyle's Law
Boyle's Law is a key principle in understanding how gases behave under changes of pressure. It tells us that the pressure and volume of a gas have an inverse relationship when temperature is kept constant. If you increase the pressure on a gas, its volume gets smaller, provided the temperature doesn’t change. Conversely, if you reduce the pressure, the volume increases. For instance, a balloon will shrink when pressure on it increases and will expand when the pressure decreases. This is represented by the equation: \[ P_1V_1 = P_2V_2 \] where \( P \) is pressure and \( V \) is volume of the gas at initial (1) and final (2) states. This relationship helps us understand the movement of the diver's bubble, as it ascends and experiences decreasing pressure.
Charles's Law
Charles's Law describes how gases expand when heated. It states that when the pressure is kept constant, the volume of a gas is directly proportional to its temperature, measured in Kelvin. As the temperature of a gas increases, so does its volume, and vice versa. This is because increasing temperature adds more energy to the gas molecules, causing them to move faster and push each other apart. The law can be expressed by: \[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \] This equation shows us that if you know the initial and final temperatures and the initial volume, you can find the final volume of the gas. In the context of the diver's air bubble, as it rises and the water temperature increases, Charles's Law shows why the bubble expands.
Pressure and Volume Relationship
The relationship between pressure and volume is crucial when analyzing gas behavior in enclosed spaces or variable environments, like underwater. According to the ideal gas law and Boyle's Law, as pressure on a gas rises, its volume must decrease if temperature stays constant. Conversely, as pressure decreases, volume increases. In the dive scenario, as the bubble rises to the lake's surface, it experiences less water pressure and thus increases in volume. This is vital to remember for divers, as a sudden reduction in pressure can cause gas in a diver's lungs to expand rapidly. - Increasing pressure = Decreasing volume - Decreasing pressure = Increasing volume Understanding this relationship helps in predicting how gas volumes change when moving between different pressure zones.
Temperature Effects on Gases
Temperature significantly affects gases, influencing their volume and the pressure they exert. The Ideal Gas Law effectively combines the principles of both Boyle's and Charles's Laws: \[ PV = nRT \] Here, \( P \) is pressure, \( V \) is volume, \( n \) is the number of moles, \( R \) is the universal gas constant, and \( T \) is temperature in Kelvin. Increasing temperature usually causes a gas to expand if the pressure remains unchanged because molecules move more vigorously, occupying more space. In our example, as the bubble rises, it goes from colder to warmer temperatures, increasing the volume even as the external pressure decreases. This dual effect can cause a significant expansion, illustrating why adjusting breathing technique for divers is crucial to prevent lung over-expansion as they ascend.

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