/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 | From a height of \(35.0 \mathr... [FREE SOLUTION] | 91Ó°ÊÓ

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| From a height of \(35.0 \mathrm{~m}\), a \(1.25 \mathrm{~kg}\) bird dives (from rest) into a small fish tank containing \(50.0 \mathrm{~kg}\) of water. What is the maximum rise in temperature of the water if the bird gives it all of its mechanical energy?

Short Answer

Expert verified
The maximum rise in temperature of the water is approximately 0.00205°C.

Step by step solution

01

Determine Initial Gravitational Potential Energy

We start by calculating the gravitational potential energy (GPE) the bird has at the height of 35.0 m using the formula: \( \text{GPE} = m \cdot g \cdot h \), where \( m = 1.25 \text{ kg} \), \( g = 9.81 \text{ m/s}^2 \), and \( h = 35.0 \text{ m} \). This gives us: \[ \text{GPE} = 1.25 \times 9.81 \times 35.0 = 428.4375 \text{ J} \]
02

Convert Mechanical Energy to Heat Energy

According to the problem, the bird transfers all its mechanical energy to the water as heat energy. Therefore, the entire gravitational potential energy of 428.4375 J is used to heat the water.
03

Calculate the Mass of the Water

We have the mass of the water as given: \( m_{\text{water}} = 50.0 \text{ kg} \).
04

Calculate Temperature Change Using Heat Transfer Formula

The energy transferred in the form of heat can be calculated by the equation: \( Q = m_{\text{water}} \cdot c \cdot \Delta T \), where:- \( Q = 428.4375 \text{ J} \) (the energy transferred)- \( m_{\text{water}} = 50 \text{ kg} \)- \( c = 4184 \text{ J/kg}^\circ \text{C} \) (specific heat capacity of water)Rearranging the equation to solve for \( \Delta T \), we have:\[ \Delta T = \frac{Q}{m_{\text{water}} \cdot c} = \frac{428.4375}{50 \times 4184} \approx 0.00205^\circ \text{C} \]
05

Final Result and Interpretation

The maximum rise in temperature of the water is therefore approximately \( 0.00205^\circ \text{C} \). This extremely small temperature change is due to the large specific heat capacity of water compared to the relatively small amount of energy transferred.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Potential Energy
Gravitational Potential Energy (GPE) is the energy stored in an object due to its position relative to the Earth or another massive body. When an object is held at a certain height, it has potential energy because of the gravitational force acting on it. The formula for GPE is \[ \text{GPE} = m \cdot g \cdot h \]where
  • \( m \) is the mass of the object in kilograms (kg),
  • \( g \) is the acceleration due to gravity (approximately \( 9.81 \text{ m/s}^2 \) on Earth's surface),
  • \( h \) is the height in meters (m) above the reference point, usually the ground.
In our example, the bird has a mass of \( 1.25 \text{ kg} \) and is at a height of \( 35.0 \text{ m} \). This setup allows us to calculate its GPE before it begins its dive. Understanding GPE is crucial as it helps us appreciate how energy conservation applies when an object transitions from a high point to a lower one.
Heat Transfer
Heat transfer occurs when energy moves from one place or material to another because of a temperature difference. In this context, the bird’s mechanical energy as it dives is converted into heat energy upon impact with the water. This process demonstrates the principles of energy conservation, where the lost potential energy is transformed into another type of energy. Upon entering the water, the energy conversion results in a rise in temperature of the water molecules, albeit by a small amount. This conversion is an example of energy transferring through conduction, where kinetic energy from the bird is shared with water molecules that are in direct contact.
Specific Heat Capacity
The specific heat capacity of a material is defined as the amount of heat required to change the temperature of one kilogram of the substance by one degree Celsius. It is an important property that varies from material to material. For water, the specific heat capacity is \( c = 4184 \text{ J/kg}^\circ \text{C} \).This high value means that water can absorb or release a large amount of heat with only a slight change in temperature. It explains why in our scenario, the temperature of the water increases by a mere \( 0.00205^\circ \text{C} \) despite the conversion of the bird's entire mechanical energy. When a substance has a high specific heat capacity, as water does, it can absorb more energy without a significant increase in temperature, showcasing its role as a temperature stabilizer in nature and technology.
Mechanical Energy
Mechanical energy encompasses both kinetic and potential energy in a system. In our exercise, the bird initially possesses only gravitational potential energy when at rest at a height, which then converts into kinetic energy as it dives. This transformation is part of the energy conservation principle in a closed system. As soon as the bird enters the water, the kinetic energy gets transferred into the water's thermal energy, thus warming the water slightly. This entire process from potential energy to kinetic energy, and finally to heat, exemplifies energy conversion in mechanical systems. It highlights how different forms of mechanical energy can seamlessly convert, playing critical roles in various phenomena and applications.

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Most popular questions from this chapter

The energy output of an animal engaged in an activity is called the basal metabolic rate (BMR) and is a measure of the conversion of food energy into other forms of energy. A simple calorimeter to measure the BMR consists of an insulated box with a thermometer to measure the temperature of the air. The air has a density of \(1.29 \mathrm{~kg} / \mathrm{m}^{3}\) and a specific heat of \(1020 \mathrm{~J} /(\mathrm{kg} \cdot \mathrm{K}) . \mathrm{A} 50.0 \mathrm{~g}\) hamster is placed in a calorimeter that contains \(0.0500 \mathrm{~m}^{3}\) of air at room temperature. (a) When the hamster is running in a wheel, the temperature of the air in the calorimeter rises \(1.8 \mathrm{C}^{\circ}\) per hour. How much heat does the running hamster generate in an hour? (Assume that all this heat goes into the air in the calorimeter. Ignore the heat that goes into the walls of the box and into the thermometer, and assume that no heat is lost to the surroundings.) (b) Assuming that the hamster converts seed into heat with an efficiency of \(10 \%\) and that hamster seed has a food energy value of \(24 \mathrm{~J} / \mathrm{g},\) how many grams of seed must the hamster eat per hour to supply the energy found in part (a)?

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One experimental method of measuring an insulating material's thermal conductivity is to construct a box of the material and measure the power input to an electric heater inside the box that maintains the interior at a measured temperature above the outside surface. Suppose that in such an apparatus a power input of \(180 \mathrm{~W}\) is required to keep the interior surface of the box \(65.0 \mathrm{C}^{\circ}\) (about \(120 \mathrm{~F}^{\circ}\) ) above the temperature of the outer surface. The total area of the box is \(2.18 \mathrm{~m}^{2}\), and the wall thickness is \(3.90 \mathrm{~cm}\). Find the thermal conductivity of the material in SI units.

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