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In seawater, a life preserver with a volume of \(0.0400 \mathrm{~m}^{3}\) will support a \(75.0 \mathrm{~kg}\) person (average density \(980 \mathrm{~kg} / \mathrm{m}^{3}\) ), with \(20 \%\) of the person's volume above water when the life preserver is fully sub-merged. What is the density of the material of the life preserver?

Short Answer

Expert verified
The density of the life preserver is 717 kg/m³.

Step by step solution

01

Understand the Problem

We are given a life preserver with a volume of 0.0400 m³ and a person with a mass of 75.0 kg and average density of 980 kg/m³. We need to find the density of the life preserver's material such that when fully submerged, it supports 80% (as 20% is above water) of the person's volume.
02

Calculate the Person's Volume

The volume of the person can be found using \[ \text{Volume of Person} = \frac{\text{Mass}}{\text{Density}} = \frac{75.0 \text{ kg}}{980 \text{ kg/m}^3} \approx 0.0765 \text{ m}^3. \]
03

Determine the Submerged Volume of the Person

Since only 80% of the person's volume is submerged, this is\[ \text{Submerged Volume of Person} = 0.0765 \times 0.8 \approx 0.0612 \text{ m}^3. \]
04

Calculate the Total Volume Displaced by the System

When the life preserver keeps 20% of the person's volume afloat, the displaced volume of water must equal the combined submerged volume of both the life preserver and the person.\[ \text{Total Displaced Volume} = \text{Submerged Volume of Person} + \text{Volume of Life Preserver}. \] \[ = 0.0612 + 0.0400 = 0.1012 \text{ m}^3. \]
05

Set Up and Solve for the Density of the Life Preserver Material

We use Archimedes' principle, which states that the total weight of the water displaced must equal the weight of the person plus the weight of the life preserver. The density of seawater is approximately 1025 kg/m³, so the displaced water has \[ 0.1012 \text{ m}^3 \times 1025 \text{ kg/m}^3 = 103.78 \text{ kg}. \]Let \( \rho \) be the density of the life preserver’s material. The combined weight must then be:\[ 103.78 \text{ kg} = 75.0 \text{ kg} + 0.0400 \text{ m}^3 \times \rho. \]Solving for \( \rho \):\[ \rho = \frac{103.78 - 75.0}{0.0400} = 717 \text{ kg/m}^3. \]
06

Conclude the Solution

The density of the life preserver is calculated to be 717 kg/m³ to keep 20% of the person above water when fully submerged.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Buoyancy
Buoyancy is a fascinating force that explains why objects float or sink in fluids like water. It all begins with Archimedes' Principle, which tells us that an object submerged in a fluid experiences an upward force, known as the buoyant force. This force is equal to the weight of the fluid displaced by the object. Here’s how it works:
  • The buoyant force acts in the opposite direction of gravity, helping objects float.
  • If the buoyant force is greater than or equal to the object's weight, the object will float.
  • If the weight is greater than the buoyant force, it will sink.
In the context of our life preserver problem, the buoyant force must support 80% of the person's submerged volume. Therefore, understanding the balance between buoyant force and weight is key to solving buoyancy-related problems effectively.
Steps in Density Calculation
Density plays a vital role in understanding whether an object will float or sink. It's mathematically expressed as mass divided by volume (\( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \)). To find the density of an object, you need to know both its mass and its volume.
  • Mass: Measure using a balance or scale.
  • Volume: Determine by calculation or displacement.
In our exercise, we calculated the person's volume based on their density information. Knowing this was necessary to determine how much of the person will submerge and how much of the life preserver has to support. With this understanding, we derived the density of the life preserver material by balancing the total weight of displaced seawater with the combined weight of both the person and the life preserver.
Exploring Fluid Mechanics
Fluid mechanics dives into how fluids behave and move, incorporating principles like buoyancy, pressure, and flow. When we talk about fluids, we're referring not just to liquids, but gases too. Here are some things to remember about fluid mechanics:
  • Fluids can exert pressure, which increases with depth, describing why objects feel lighter underwater.
  • Archimedes' Principle is a core part of fluid mechanics, offering a way to relate displaced fluid volume to buoyancy.
  • The relationship between fluid density and buoyancy helps explain why some fluids can support objects better than others.
In solving problems like our life preserver exercise, applying fluid mechanics principles ensures you account for the interaction between submerged objects and fluids properly. Understanding these concepts makes predicting floating behavior and calculating necessary material properties straightforward.

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