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How big is a million dollars? At the time this text was written, the price of gold was about \(\$ 1400\) per ounce, while that of silver was about \(\$ 20\) an ounce. The "ounce" in this case is the troy ounce, which is equal to \(31.1035 \mathrm{~g}\). (The more familiar avoirdupois ounce is equal to \(28.35 \mathrm{~g} .\) ) The density of gold is \(19.3 \mathrm{~g} / \mathrm{cm}^{3}\) and that of silver is \(10.5 \mathrm{~g} / \mathrm{cm}^{3}\). (a) If you found a spherical gold nugget worth \(\$ 1\) million, what would be its diameter? (b) How much would a silver nugget of that size be worth?

Short Answer

Expert verified
A spherical gold nugget worth $1 million has a diameter of about 12.98 cm. A silver nugget of the same size is worth approximately $7,782.20.

Step by step solution

01

Determine the weight of a million dollars in gold

To find the weight of a million dollars in gold, divide the total value by the price per ounce. \\[ \text{Weight of gold} = \frac{1,000,000 \text{ dollars}}{1,400 \text{ dollars/ounce}} \approx 714.29 \text{ ounces} \]
02

Convert ounces to grams

Convert the weight from troy ounces to grams using the conversion rate. \\[ \text{Weight of gold in grams} = 714.29 \text{ ounces} \times 31.1035 \text{ grams/ounce} \approx 22,231.95 \text{ grams} \]
03

Calculate the volume of the gold nugget

Find the volume by using the density of gold: \\[ \text{Volume of gold} = \frac{\text{Weight in grams}}{\text{Density}} = \frac{22,231.95 \text{ grams}}{19.3 \text{ grams/cm}^3} \approx 1,152.27 \text{ cm}^3 \]
04

Determine the radius of the spherical gold nugget

Use the volume of a sphere formula to find the radius: \\[ V = \frac{4}{3} \pi r^3 \Rightarrow r = \left(\frac{3V}{4\pi}\right)^{1/3} \] \Calculate the radius using the volume found in Step 3: \\[ r = \left(\frac{3 \times 1,152.27}{4 \times \pi}\right)^{1/3} \approx 6.49 \text{ cm} \]
05

Calculate the diameter of the gold nugget

Diameter is twice the radius: \\[ \text{Diameter} = 2 \times 6.49 \approx 12.98 \text{ cm} \]
06

Calculate the volume of the silver nugget with the same diameter

Using the same diameter, calculate the volume for silver: \\[ V = \frac{4}{3} \pi r^3; \quad r = 6.49 \text{ cm} \] \Substitute the radius: \\[ V \approx \frac{4}{3} \pi (6.49)^3 \approx 1,152.27 \text{ cm}^3 \]
07

Calculate the weight of the silver nugget

Using the volume and density of silver, calculate its weight: \\[ \text{Weight in grams} = \text{Volume} \times \text{Density} = 1,152.27 \text{ cm}^3 \times 10.5 \text{ grams/cm}^3 \approx 12,097.84 \text{ grams} \]
08

Convert the weight of the silver nugget to ounces

Convert from grams to ounces using the inverse of the conversion factor: \\[ \text{Weight in ounces} = \frac{12,097.84 \text{ grams}}{31.1035 \text{ grams/ounce}} \approx 389.11 \text{ ounces} \]
09

Calculate the worth of the silver nugget

Multiply the weight in ounces by the price of silver per ounce: \\[ \text{Worth of silver} = 389.11 \text{ ounces} \times 20 \text{ dollars/ounce} \approx 7,782.20 \text{ dollars} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gold and Silver Economics
The economics of gold and silver are fascinating and play a significant role in the global market. These precious metals are not just seen as commodities but are deeply ingrained in history as stores of value. Prices of gold and silver fluctuate based on demand, market sentiment, and geopolitical factors.
- **Gold**: It is often considered a safeguard against economic downturns, and its price can rise during times of uncertainty. Gold is also used in jewelry, electronics, and other industries. - **Silver**: While it shares some uses with gold, silver has a wider industrial application, being used in electronics, solar panels, and various chemical processes. Due to these uses, its price can be more volatile. The exercise highlights the price difference, with $1400 per ounce for gold and $20 per ounce for silver. This large difference illustrates gold's perceived value and its utility as an economic hedge. Understanding these economics helps in appreciating the historical standing and current market values in investments and industrial applications.
Troy and Avoirdupois Ounce
The term 'ounce' may be familiar, but it's essential to know that there are different types of ounces when dealing with precious metals. The exercise refers to the troy ounce, which is specifically used in the metals market. - **Troy Ounce**: Weighs 31.1035 grams and is the standard unit for precious metals like gold and silver. It originates from the Roman monetary system, providing uniformity in trade across different regions. - **Avoirdupois Ounce**: More commonly used in daily life, weighing 28.35 grams. It's the standard measurement unit for everyday goods in the United States and is based on a system used in medieval France. Converting between these ounces is crucial when determining the mass and worth of metals like gold and silver in various contexts. Understanding this distinction helps avoid confusion during calculations, especially in investment or trading scenarios.
Sphere Volume Calculation
Calculating the volume of spherical objects comes in handy in various scientific and practical applications. The formula for the volume of a sphere is based on its radius and is expressed as:- \[ V = \frac{4}{3} \pi r^3 \]This formula is pivotal in the exercise as it allows us to translate weight into volume. When considering a spherical nugget of gold, the volume tells us about the nugget's spatial presence, which is significant when dealing with its physical properties or market value.
Calculating the volume allows us to:- **Estimate Size**: Determining how large or small an object is based on its weight and density. - **Cross-Application**: Use this measurement in other spheres like material science and engineering, where comprehension of physical dimensions is key.
The calculations in the exercise illustrate the application of the volume formula to real-world scenarios, helping to contextualize theoretical math into tangible outcomes.
Density and Mass Relationship
Density is a physical property that links mass and volume in a straightforward relationship. It is defined as the mass per unit volume:- **Density Formula**: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]This relationship is crucial for determining how much space a set amount of mass will occupy. In the context of the exercise, knowing the density of gold (19.3 g/cm³) and silver (10.5 g/cm³) enables accurate volume calculation.
Significance of Density:- **Predicting Weight from Volume**: Once the volume of a gold nugget is known, one can calculate its mass using its density. - **Comparative Analysis**: Different materials have different densities, influencing how much space they occupy given a certain mass. This becomes useful when comparing how substances behave in practical contexts, like construction or manufacturing.
By understanding the relationship between density, mass, and volume, students can make better predictions and calculations related to physical objects, enhancing comprehension of material properties in various scientific disciplines.

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Most popular questions from this chapter

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