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With what tension must a rope with length \(2.50 \mathrm{~m}\) and mass \(0.120 \mathrm{~kg}\) be stretched for transverse waves of frequency \(40.0 \mathrm{~Hz}\) to have a wavelength of \(0.750 \mathrm{~m} ?\)

Short Answer

Expert verified
The tension in the rope should be 43.2 N.

Step by step solution

01

Identify Known Values

First, list down all the known values from the problem:- Length of the rope, \( L = 2.50 \text{ m} \)- Mass of the rope, \( m = 0.120 \text{ kg} \)- Frequency of the wave, \( f = 40.0 \text{ Hz} \)- Wavelength of the wave, \( \lambda = 0.750 \text{ m} \).
02

Calculate Linear Density

Calculate the linear density, \( \mu \), of the rope, which is the mass per unit length:\[ \mu = \frac{m}{L} = \frac{0.120 \text{ kg}}{2.50 \text{ m}} = 0.048 \text{ kg/m} \]
03

Use Wave Equation

Use the wave speed equation for a stretched rope: \( v = \sqrt{\frac{T}{\mu}} \)Since the wave speed, \( v \), is also given by \( v = f \lambda \), we can equate the two expressions for velocity:\[ f \lambda = \sqrt{\frac{T}{\mu}} \]
04

Solve for Tension

Solve the equation for tension, \( T \):1. Substitute known values into the equation: \[ v = f \lambda = 40.0 \text{ Hz} \times 0.750 \text{ m} = 30.0 \text{ m/s} \]2. Rearrange the equation: \[ 30.0 = \sqrt{\frac{T}{0.048}} \]3. Square both sides to remove the square root: \[ 30.0^2 = \frac{T}{0.048} \]4. Solve for \( T \): \[ 900 = \frac{T}{0.048} \] \[ T = 900 \times 0.048 = 43.2 \text{ N} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tension in a Rope
When dealing with transverse waves traveling through a rope, understanding the concept of tension is crucial. Tension is the force applied along the length of the rope to stretch it tightly. This tension ensures that the rope is taut enough for waves to propagate effectively.
An easy way to visualize tension is to think of a tug-of-war game, where the rope is stretched between the two teams. The force needed to hold the rope tight is the tension.
In calculations, tension is represented by the symbol \( T \), and it impacts the speed at which waves can travel through the rope. The higher the tension, the faster the wave can move. To find the tension needed to achieve a specific wave speed, like in the given exercise, you can use the wave speed equation, which relates tension with linear density of the rope.
Linear Density
Linear density is a key factor in determining how waves behave on a rope. It describes the mass of the rope per unit of length, essentially how heavy the rope is per meter.
The formula to compute linear density \( \mu \) is:
  • \( \mu = \frac{m}{L} \)

where \( m \) is the mass and \( L \) is the length of the rope.
This calculation provides valuable insights into how the mass distribution of the rope affects wave propagation. Generally, a rope with higher linear density will require more tension for waves to travel at the same speed, compared to a rope with lower linear density.
Wave Speed Equation
The wave speed equation is pivotal to understanding how fast transverse waves travel along a rope. This equation links tension, linear density, and wave speed.
The fundamental equation to determine wave speed \( v \) is:
  • \( v = \sqrt{\frac{T}{\mu}} \)
This means the speed of the wave is determined by the tension \( T \) over the linear density \( \mu \).
A convenient aspect of wave problems is that wave speed can also be determined by the product of frequency \( f \) and wavelength \( \lambda \) as:
  • \( v = f \lambda \)
By equating these two expressions for wave speed, you can solve for the tension required in any given problem, which is a common approach in physics exercises.
Wavelength and Frequency
Wavelength and frequency are intrinsic properties of waves, describing their physical structure and the rate at which they occur. Wavelength, denoted by \( \lambda \), is the distance between two successive crests or troughs in a wave.
Frequency, signified by \( f \), is the number of wavelengths that pass a point per second, measured in Hertz (Hz).
These two elements are interrelated through the wave speed equation, \( v = f \lambda \), which essentially states that the speed of a wave is the product of its wavelength and frequency.
Understanding these concepts helps in solving many wave problems and is essential in applications like music, telecommunication, and even understanding the behavior of ocean waves.

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Most popular questions from this chapter

A police siren of frequency \(f_{\text {siren }}\) is attached to a vibrating platform. The platform and siren oscillate up and down in simple harmonic motion with amplitude \(A_{\mathrm{p}}\) and frequency \(f_{\mathrm{p}}\). (a) Find the maximum and minimum sound frequencies that you would hear at a position directly above the siren. (b) At what point in the motion of the platform is the maximum frequency heard? The minimum frequency? Explain.

Electromagnetic waves, which include light, consist of vibrations of electric and magnetic fields, and they all travel at the speed of light. (a) FM radio. Find the wavelength of an FM radio station signal broadcasting at a frequency of \(104.5 \mathrm{MHz}\). (b) X-rays. X-rays have a wavelength of about 0.10 nm. What is their frequency? (c) The Big Bang. Microwaves with a wavelength of \(1.1 \mathrm{~mm}\), left over from soon after the Big Bang. have been detected. What is their frequency? (d) Sunburn. Sunburn (and skin cancer) is caused by ultraviolet light waves having a frequency of around \(10^{16} \mathrm{~Hz}\). What is their wavelength? (e) SETI. It has been suggested that extraterrestrial civilizations (if they exist) might try to communicate by using electromagnetic waves having the same frequency as that given off by the spin flip of the electron in hydrogen, which is \(1.43 \mathrm{GHz}\). To what wavelength should we tune our telescopes in order to search for such signals? (f) Microwave ovens. Microwave ovens cook food with electromagnetic waves of frequency around \(2.45 \mathrm{GHz}\). What wavelength do these waves have?

In some applications of ultrasound, such as its use on cranial tissues, large reflections from the surrounding bones can produce standing waves. This is of concem because the large pressure amplitude in an antinode can damage tissues. For a frequency of \(1.0 \mathrm{MHz},\) what is the distance between antinodes in tissue? A. \(0.38 \mathrm{~mm}\) B. \(0.75 \mathrm{~mm}\) C. \(1.5 \mathrm{~mm}\) D. \(3.0 \mathrm{~mm}\)

Standing sound waves are produced in a pipe that is \(1.20 \mathrm{~m}\) long. For the fundamental frequency and the first two overtones, determine the locations along the pipe (measured from the left end) of the displacement nodes if (a) the pipe is open at both ends; (b) the pipe is closed at the left end and open at the right end.

A wire with mass \(40.0 \mathrm{~g}\) is stretched so that its ends are tied down at points \(80.0 \mathrm{~cm}\) apart. The wire vibrates in its fundamental mode with frequency \(60.0 \mathrm{~Hz}\) and with an amplitude of \(0.300 \mathrm{~cm}\) at the antinodes. (a) What is the speed of propagation of transverse waves in the wire? (b) Compute the tension in the wire.

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