/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 Two tuning forks are producing s... [FREE SOLUTION] | 91Ó°ÊÓ

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Two tuning forks are producing sounds of wavelength \(34.40 \mathrm{~cm}\) and \(33.94 \mathrm{~cm}\) simultaneously. How many beats do you hear each second?

Short Answer

Expert verified
Approximately 13 beats per second are heard.

Step by step solution

01

Understand the concept of beats

When two sound waves of slightly different frequencies interfere with each other, they produce a perceptible variation or "pulsations" in loudness called beats. The beat frequency is the absolute difference between the two frequencies.
02

Calculate the frequencies of the tuning forks

The frequency of a wave is given by the formula \( f = \frac{v}{\lambda} \), where \( v \) is the speed of sound in air (approximately \(343 \, \text{m/s}\) at room temperature), and \( \lambda \) is the wavelength.For the first tuning fork with \( \lambda_1 = 34.40 \, \text{cm} = 0.3440 \, \text{m} \), the frequency is\[f_1 = \frac{343}{0.3440} \approx 997.1 \, \text{Hz}\]For the second tuning fork with \( \lambda_2 = 33.94 \, \text{cm} = 0.3394 \, \text{m} \), the frequency is\[f_2 = \frac{343}{0.3394} \approx 1010.0 \, \text{Hz}\]
03

Calculate the beat frequency

The beat frequency \( f_b \) is determined by the absolute difference between the two frequencies:\[f_b = |f_1 - f_2|\]Substituting the frequencies we calculated:\[f_b = |997.1 - 1010.0| = 12.9 \, \text{Hz}\]
04

Conclude the solution

Since the beat frequency represents the number of beats heard per second, hearing 12.9 beats per second means you hear roughly 13 beats per second (since beat counts must be whole numbers).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tuning Fork
A tuning fork is a simple yet powerful device used to produce a pure musical note. It consists of a metal, usually steel, shaped like a pair of prongs connected to a handle. When struck against a surface, it vibrates at a specific frequency, generating sound waves that travel through the air. These prongs flex inward and outward, creating a series of compressions and rarefactions in the air molecules. Consequently, this sets off waves in the surrounding medium, which we perceive as sound.
When used in acoustics, tuning forks serve as frequency standards, since their sounds are stable and predictable. The accuracy of a tuning fork largely depends on its construction material and the temperature of the environment, as small changes can affect its vibration rate. Therefore, tuning forks are valuable tools in teaching and tuning musical instruments. They provide a clear example of harmonic motion, helping explain fundamental principles of wave behavior.
Wavelength and Frequency Relationship
Sound waves, as with all waves, exhibit an intrinsic relationship between their wavelength and frequency. This is expressed in the equation: \[ f = \frac{v}{\lambda} \] where:
  • \( f \) is the frequency of the wave, noted in Hertz (Hz), which counts the number of wave cycles that pass a point per second.
  • \( v \) is the speed of the wave through a medium, such as air.
  • \( \lambda \) is the wavelength, the physical distance over which the wave's shape repeats.
In particular, the speed of sound in air is approximately 343 m/s.
When dealing with sound waves, a shorter wavelength signifies a higher frequency, meaning the waves occur more rapidly, resulting in a higher pitched sound. Conversely, a longer wavelength correlates with a lower frequency and a lower pitch. Understanding this relationship is crucial for solving problems involving sound interference and beat frequencies.
Interference of Sound Waves
Interference occurs when two or more sound waves meet while traveling through the same medium. One key type of interference involves beats, which result from combining waves of slightly different frequencies.
When these waves intersect, they produce a pattern of alternating loud and soft sounds. These alternations, known as beats, arise from the constructive and destructive interference of the waves. Constructive interference occurs when the waves align such that their amplitudes combine, creating a louder sound. Conversely, destructive interference happens when the waves are out of phase, reducing the overall sound.
This characteristic pulsation or variation in sound intensity is measured as the beat frequency. By finding the absolute difference between the frequencies of the two waves, as calculated in the original solution, students can determine the number of beats heard each second. The concept of sound wave interference is fundamental in fields such as acoustics, music, and sound engineering.
Speed of Sound in Air
The speed of sound is a dynamic quantity influenced by several factors, including air temperature, humidity, and atmospheric pressure. At room temperature (about 20°C or 68°F), sound travels at about 343 meters per second (m/s) in air.
The speed of sound can vary slightly under different conditions:
  • It increases with higher temperatures. Warmer air means the air molecules have more energy, moving faster and facilitating faster travel of the sound wave.
  • Humidity also affects speed—sound travels faster in humid air because water vapor makes the air less dense.
  • The speed does not readily change with atmospheric pressure because pressure and density changes often cancel each other out.
Understanding the speed of sound is important for solving wave-related problems like the calculation of frequency and wavelength. This knowledge serves as a foundation in various applications, from music to meteorology.

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Most popular questions from this chapter

For cranial ultrasound, why is it advantageous to use frequencies in the kHZ range rather than in the MHz range? A. The antinodes of the standing waves will be closer together at the lower frequencies than at the higher frequencies. B. There will be no standing waves at the lower frequencies. C. Cranial bones will attenuate the ultrasound more at the lower frequencies than at the higher frequencies. D. Cranial bones will attenuate the ultrasound less at the lower frequencies than at the higher frequencies.

A very noisy chain saw operated by a tree surgeon emits a total acoustic power of \(20.0 \mathrm{~W}\) uniformly in all directions. At what distance from the source is the sound level equal to (a) \(100 \mathrm{~dB}\), (b) \(60 \mathrm{~dB} ?\)

A young person with normal hearing can hear sounds ranging from \(20 \mathrm{~Hz}\) to \(20 \mathrm{kHz}\). How many octaves can such a person hear? (Recall that if two tones differ by an octave, the higher frequency is twice the lower frequency.)

A trumpet player is tuning his instrument by playing an A note simultaneously with the first-chair trumpeter, who has perfect pitch. The first-chair player's note is exactly \(440 \mathrm{~Hz}\), and 2.8 beats per second are heard. What are the two possible frequencies of the other player's note?

(a) What is the sound intensity level in a car when the sound intensity is \(0.500 \mu \mathrm{W} / \mathrm{m}^{2} ?\) (b) What is the sound intensity in the air near a jackhammer when the sound intensity level is \(103 \mathrm{~dB}\) ?

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