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A \(1.50-\mathrm{m}\) -long rope is stretched between two supports with a tension that makes the speed of transverse waves \(48.0 \mathrm{~m} / \mathrm{s}\). What are the wavelength and frequency of (a) the fundamental tone? (b) the second overtone? (c) the fourth harmonic?

Short Answer

Expert verified
(a) Fundamental: 3.00 m, 16.0 Hz; (b) Second overtone: 1.00 m, 48.0 Hz; (c) Fourth harmonic: 0.75 m, 64.0 Hz.

Step by step solution

01

Understanding the Problem

When a rope is stretched between two supports, it can have standing waves. The fundamental frequency corresponds to the lowest frequency at which a standing wave can form. The overtones and harmonics refer to higher frequencies of the standing wave.
02

Identify Given Data

We are given the length of the rope as \( L = 1.50 \) meters and the speed of transverse waves on the rope as \( v = 48.0 \) m/s.
03

Calculate the Fundamental Frequency

For the fundamental tone (first harmonic), the wavelength \( \lambda_1 \) is twice the length of the rope: \[ \lambda_1 = 2L = 2 \times 1.50 = 3.00 \text{ meters} \] The frequency \( f_1 \) is given by \[ f_1 = \frac{v}{\lambda_1} = \frac{48.0}{3.00} = 16.0 \text{ Hz} \].
04

Determine the Wavelength and Frequency of the Second Overtone

The second overtone is the third harmonic. Its wavelength \( \lambda_3 \) is \[ \lambda_3 = \frac{2L}{3} = \frac{3.00}{3} = 1.00 \text{ meters} \] The frequency \( f_3 \) for the third harmonic is \[ f_3 = \frac{v}{\lambda_3} = \frac{48.0}{1.00} = 48.0 \text{ Hz} \].
05

Calculate the Wavelength and Frequency of the Fourth Harmonic

The fourth harmonic has a wavelength \( \lambda_4 \) of \[ \lambda_4 = \frac{2L}{4} = \frac{3.00}{4} = 0.75 \text{ meters} \] The frequency \( f_4 \) for the fourth harmonic is \[ f_4 = \frac{v}{\lambda_4} = \frac{48.0}{0.75} = 64.0 \text{ Hz} \].
06

Summary of Results

For the fundamental tone, the wavelength is \( 3.00 \) meters and the frequency is \( 16.0 \) Hz. The second overtone has a wavelength of \( 1.00 \) meters and a frequency of \( 48.0 \) Hz. The fourth harmonic has a wavelength of \( 0.75 \) meters and a frequency of \( 64.0 \) Hz.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fundamental Frequency
When a rope or string is fixed at both ends, it can produce standing waves. The lowest frequency at which a standing wave can form is known as the fundamental frequency. This is also referred to as the first harmonic. For a string of length \( L \), the wavelength of the fundamental frequency is twice the length of the string. Hence, \( \lambda_1 = 2L \).
In the given example, the string is 1.50 meters long, giving us a fundamental wavelength of 3.00 meters. To find the fundamental frequency, you divide the wave speed \( v \) by the wavelength \( \lambda_1 \):
- \( f_1 = \frac{v}{\lambda_1} = \frac{48.0}{3.00} = 16.0 \) Hz.
By understanding the fundamental frequency, you grasp the basic mode of vibration for the string. This mode produces the simplest standing wave pattern, featuring a single antinode.
Harmonics
Harmonics are the higher frequencies at which the string can naturally vibrate. Each harmonic corresponds to a multiple of the fundamental frequency.
- **Second Overtone:** The second overtone is equivalent to the third harmonic in a standing wave system. It consists of three loops or antinodes along the length of the string. For this harmonic, the wavelength is \( \lambda_3 = \frac{2L}{3} \), resulting in 1.00 meter for our example.
- The frequency is then \( f_3 = \frac{v}{\lambda_3} = 48.0 \) Hz.
- **Fourth Harmonic:** Similarly, the fourth harmonic has a wavelength \( \lambda_4 = \frac{2L}{4} \), simplifying to 0.75 meters. The frequency can be calculated by \( f_4 = \frac{v}{\lambda_4} = 64.0 \) Hz.
Understanding harmonics is crucial for identifying complex sound patterns and vibrations, giving insight into how musical instruments create rich tones and sounds.
Transverse Waves
Transverse waves are waves where the motion of the medium is perpendicular to the direction of the wave itself. This means if the wave is moving horizontally, the displacement of the medium (like a rope or string) will be vertical.
In the context of waves on a rope, transverse waves create the characteristic peaks and troughs seen in standing waves. These motions, when perfectly timed with the reflections from the rope's fixed ends, lead to the formation of standing waves.
Transverse waves are important for understanding not only vibrations of strings but also electromagnetic waves, like light, where the electric and magnetic fields oscillate perpendicular to the direction of wave travel.
Wave Speed
Wave speed is a crucial factor in determining both the frequency and wavelength of standing waves. It describes how quickly waves travel through a medium. The formula relating wave speed to frequency and wavelength is\( v = f \cdot \lambda \), where \( v \) is the wave speed, \( f \) is the frequency, and \( \lambda \) is the wavelength.
In the example, the wave speed is given as 48.0 meters per second. This remains constant for the medium provided no other changes. Understanding wave speed allows you to calculate either frequency or wavelength, provided you have one of these and the wave speed.
Knowing the wave speed and the mechanics behind the equations allows one to design instruments and understand phenomena where precise wave manipulation is essential. From musical instrument tuning to engineering applications, wave speed plays an integral role.

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