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Vector \(A\) has components \(A_{x}=1.30 \mathrm{~cm}, \quad A_{y}=\) \(2.25 \mathrm{~cm} ; \quad\) vector \(\quad \vec{B} \quad\) has components \(\quad B_{x}=4.10 \mathrm{~cm}\) \(B_{y}=-3.75 \mathrm{~cm} .\) Find (a) the components of the vector sum \(\overrightarrow{\boldsymbol{A}}+\overrightarrow{\boldsymbol{B}} ;(\mathrm{b})\) the magnitude and direction of \(\vec{A}+\vec{B} ;(\mathrm{c})\) the components of the vector difference \(\overrightarrow{\boldsymbol{B}}-\overrightarrow{\boldsymbol{A}} ;\) (d) the magnitude and direction of \(\overrightarrow{\boldsymbol{B}}-\overrightarrow{\boldsymbol{A}}\)

Short Answer

Expert verified
(a) Components of sum: (5.40, -1.50) cm (b) Magnitude: 5.60 cm; Direction: -15.5° (c) Components of difference: (2.80, -6.00) cm (d) Magnitude: 6.62 cm; Direction: -64.0°

Step by step solution

01

Find the Components of Vector Sum

To find the components of the vector sum \( \overrightarrow{A} + \overrightarrow{B} \), we add the respective components of the two vectors. The x-component of the sum is \( A_x + B_x = 1.30 + 4.10 = 5.40 \) cm. The y-component of the sum is \( A_y + B_y = 2.25 - 3.75 = -1.50 \) cm.Thus, the components of \( \overrightarrow{A} + \overrightarrow{B} \) are \( (5.40, -1.50) \) cm.
02

Calculate the Magnitude of Vector Sum

The magnitude of \( \overrightarrow{A} + \overrightarrow{B} \) is calculated using the Pythagorean theorem:\[|\overrightarrow{A} + \overrightarrow{B}| = \sqrt{(5.40)^2 + (-1.50)^2} = \sqrt{29.16 + 2.25} = \sqrt{31.41} \approx 5.60 \text{ cm}\]
03

Determine the Direction of Vector Sum

The direction of \( \overrightarrow{A} + \overrightarrow{B} \) is given by the angle \( \theta \) such that\[\theta = \arctan\left(\frac{-1.50}{5.40}\right)\]Calculating the angle:\[\theta \approx \arctan(-0.2778) \approx -15.5^{\circ}\]The angle \( \theta \) is measured counterclockwise from the positive x-axis.
04

Find Components of Vector Difference

For the vector difference \( \overrightarrow{B} - \overrightarrow{A} \), subtract the components of \( \overrightarrow{A} \) from \( \overrightarrow{B} \). The x-component is \( B_x - A_x = 4.10 - 1.30 = 2.80 \) cm.The y-component is \( B_y - A_y = -3.75 - 2.25 = -6.00 \) cm.Thus, the components of \( \overrightarrow{B} - \overrightarrow{A} \) are \( (2.80, -6.00) \) cm.
05

Calculate the Magnitude of Vector Difference

To find the magnitude of \( \overrightarrow{B} - \overrightarrow{A} \), apply the Pythagorean theorem:\[|\overrightarrow{B} - \overrightarrow{A}| = \sqrt{(2.80)^2 + (-6.00)^2} = \sqrt{7.84 + 36.00} = \sqrt{43.84} \approx 6.62 \text{ cm}\]
06

Determine the Direction of Vector Difference

The direction of \( \overrightarrow{B} - \overrightarrow{A} \) is calculated using the angle \( \theta \):\[\theta = \arctan\left(\frac{-6.00}{2.80}\right)\]Calculating the angle:\[\theta \approx \arctan(-2.1429) \approx -64.0^{\circ}\]This angle is also measured counterclockwise from the positive x-axis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Addition
When combining two vectors, we apply vector addition, which involves adding corresponding components from each vector.
This method maintains the directional qualities of each component, resulting in a new vector sum.

For example:
  • Given vector \( \overrightarrow{A} = (A_x, A_y) \)
  • and \( \overrightarrow{B} = (B_x, B_y) \)

The components of the resulting vector, \( \overrightarrow{A} + \overrightarrow{B} \), are found by:
  • Adding the x-components: \( A_x + B_x \)
  • Adding the y-components: \( A_y + B_y \)

So, for vectors \((1.30 \, \text{cm}, 2.25 \, \text{cm})\) and \((4.10 \, \text{cm}, -3.75 \, \text{cm})\),
we calculate:
  • X-component: \( 1.30 + 4.10 = 5.40 \, \text{cm} \)
  • Y-component: \( 2.25 - 3.75 = -1.50 \, \text{cm} \)
This results in the new vector \((5.40 \, \text{cm}, -1.50 \, \text{cm})\).
Vector addition helps in understanding how different forces combine to generate a single net force, an essential concept in physics.
Vector Subtraction
Vector subtraction is conceptually similar to addition but involves subtracting one vector's components from the corresponding components of another vector.
This operation reflects the difference between two possible routes or forces.

Here's how to do it:
  • For vectors \( \overrightarrow{B} = (B_x, B_y) \)
  • and \( \overrightarrow{A} = (A_x, A_y) \)

The resulting vector from the subtraction \( \overrightarrow{B} - \overrightarrow{A} \) will be:
  • X-component: \( B_x - A_x \)
  • Y-component: \( B_y - A_y \)

Using our components:
  • X-component: \( 4.10 - 1.30 = 2.80 \, \text{cm} \)
  • Y-component: \( -3.75 - 2.25 = -6.00 \, \text{cm} \)
This gives the vector difference as \((2.80 \, \text{cm}, -6.00 \, \text{cm})\).
Grasping vector subtraction is vital in applications like determining relative velocity or displacement in different contexts.
Magnitude and Direction of Vectors
The magnitude and direction of a vector provide a complete description of its size and which way it points.
This is crucial for translating the vector into a physical quantity like force, velocity, or displacement.

For the magnitude, use the Pythagorean theorem:
  • Magnitude\(|\overrightarrow{V}|\) is given by \(|\overrightarrow{V}| = \sqrt{V_x^2 + V_y^2} \)

In our example:
  • The magnitude of \(\overrightarrow{A} + \overrightarrow{B} \) is \( \sqrt{5.40^2 + (-1.50)^2} \approx 5.60 \, \text{cm} \)

To find the direction, calculate the angle \( \theta \) with the x-axis using:
  • \( \theta = \arctan\left( \frac{V_y}{V_x} \right) \)

For the vector sum:
  • Direction \(\theta \) is \( \arctan\left(\frac{-1.50}{5.40}\right) \approx -15.5^\circ \)
This reveals that the vector's direction is slightly downwards relative to the horizontal.
Knowing both magnitude and direction is essential for accurately modeling real-life situations in scientific and engineering fields.
Component Method
The component method involves breaking a vector into its x and y components, which simplifies complex vector operations.
By resolving vectors into components, vector addition and subtraction become straightforward algebraic problems.

Think of it as translating a full vector into manageable horizontal and vertical parts.
  • The x-component determines how much of the vector affects horizontal motion.
  • The y-component, similarly, affects vertical motion.

This method is useful in:
  • Finding the net effect of combined vectors.
  • Making calculations easier in physics problems.

Within this framework, vectors can be manipulated algebraically, allowing us to evaluate scenarios like projectile motion or force equilibrium smoothly.

For the exercise:
  • Vector \(\overrightarrow{A}\) transformed into components \( (1.30, 2.25) \)
  • Vector \(\overrightarrow{B}\) transformed into components \( (4.10, -3.75) \)

This method enables a coherent approach to dissecting vectors and solving for different outcomes effectively.
Understanding components is imperative for assessing how each constituent directs the overall behavior of the vector.

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