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How does the energy contained in a charged capacitor change when a dielectric is inserted, assuming the capacitor is isolated and its charge is constant? Does this imply that work was done?

Short Answer

Expert verified
The energy stored in the isolated charged capacitor increases when a dielectric is inserted, since the capacitance increases while the charge remains constant. This increase implies that work was done to insert the dielectric.

Step by step solution

01

Understand the effect of inserting a dielectric

When a dielectric material is inserted into an isolated charged capacitor with constant charge, the capacitance increases. The dielectric reduces the electric field between the plates which, according to the formula for capacitance, C = \(\frac{Q}{V}\), results in an increased capacitance due to decreased voltage V.
02

Calculate the change in energy

The energy stored in a capacitor is given by \(U = \frac{1}{2}CV^2\). Since the capacitance (C) increases and the charge (Q) remains the same, the voltage (V) must decrease. The new energy stored, assuming the charge is constant, can be calculated by \(U’ = \frac{1}{2}C’V’^2\), where C' is the new capacitance with the dielectric. As C has increased and V has decreased, the new energy U’ is larger than the original energy U.
03

Determine if work was done

Since energy is conserved, the increase in stored energy within the capacitor must come from the work done to insert the dielectric. Work is done against the attractive forces between the charges on the plates and the induced charges on the dielectric surface. Thus, work is indeed done when the dielectric is inserted into the capacitor.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Capacitance and Dielectrics
The concept of a capacitor is foundational in understanding various aspects of electromagnetism and electronics. A capacitor essentially consists of two conductive plates separated by an insulating material known as a dielectric. Capacitance, denoted as 'C', is the capacity of a capacitor to store charge per unit voltage, which is expressed by the formula:

\[\begin{equation}C = \frac{Q}{V}\end{equation}\]
where 'Q' is the electric charge and 'V' is the voltage across the plates. When a dielectric is inserted between the plates of an isolated capacitor (with a constant charge), the capacitance increases. This occurs because the dielectric material reduces the electric field within the capacitor, leading to a decreased voltage across the plates and hence a higher capacitance value. Dielectric materials possess an electric permittivity greater than the vacuum permittivity, which enhances the charge-holding capacity.

Moreover, the type of dielectric material and its properties such as permittivity directly influence the extent to which the capacitance will increase. This transformative ability of dielectrics has far-reaching applications, enabling capacitors to store more energy without changing their size. Exploring the interaction between a capacitor's geometry, the dielectric material, and the resultant capacitance is a critical part of developing an intuitive understanding of how capacitors work and are applied in various electronic devices.
Electric Potential Energy
The electric potential energy in the context of capacitors is the energy stored due to the separation of charges. It is a form of potential energy that arises from the electric field generated by the charges on the capacitor's plates. The potential energy, denoted by 'U', can be seen as the work required to establish the charge separation under a certain voltage, and for a capacitor is given by the formula:

\[\begin{equation}U = \frac{1}{2}CV^2\end{equation}\]
The inserted dielectric alters the capacitor's ability to hold energy without changing the amount of charge stored. As the dielectric is inserted and the capacitance increases, the voltage across the capacitor's plates decreases while the stored charge remains the same. This effect leads to a consequent increase in the electric potential energy stored within the capacitor. This concept points to the power of electrical fields in doing work and storing energy. Understanding this relationship teaches us how energy can be stored in an electric field, captured succinctly by the capacitor—an essential device in electronics that taps into the physics of storage and retrieval of electric potential energy.
Work Done on Capacitor
When discussing work in the context of physics, it refers to the process of energy transfer that occurs when a force is applied over a distance. In the scenario of a dielectric being inserted into a capacitor, work is done on the system. This process can be complex to visualize, but essentially, work is done against the existing electric field between the capacitor plates. Adding the dielectric involves overcoming the attractive forces between the charges on the plates and those induced charges on the dielectric surface.

The work done is directly related to the change in energy of the capacitor system. As the capacitance increases with the addition of the dielectric, so too does the stored energy within the capacitor. This implies that the work had to be done to insert the dielectric, accounting for the increased energy stored in the capacitor. The work, in this case, is the energy required to move the dielectric into the space between the plates while counteracting the internal electric field. It is essential for students to understand that energy conservation principles apply: The work done on the capacitor manifests as an increased electric potential energy in the system, providing a practical demonstration of how work translates into stored energy within a capacitor.

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