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(a) What is the work output of a cyclical heat engine having a 22.0% efficiency and 6.00×109J of heat transfer into the engine? (b) How much heat transfer occurs to the environment?

Short Answer

Expert verified
The work output of the engine is 1.32×10^9 J, and the heat transfer to the environment is 4.68×10^9 J.

Step by step solution

01

Understand Work Output

To calculate the work output of a heat engine with a given efficiency, use the formula: Work output = Efficiency × Heat Input. The efficiency should be in decimal form.
02

Convert Efficiency to Decimal

Convert the given efficiency from a percentage to a decimal by dividing by 100. For a 22.0% efficiency, the conversion is: 22.0% / 100 = 0.22.
03

Calculate Work Output

Using the converted efficiency and the given amount of heat input, calculate the work output: Work output = 0.22 × 6.00×10^9 J.
04

Solving for Work Output

Multiply the efficiency in decimal form by the heat transfer into the engine to find the work output: 0.22 × 6.00×10^9 J = 1.32×10^9 J.
05

Understand Heat Transfer to Environment

The heat transfer to the environment is the difference between the heat input and the work output, since the energy not used for work is released as heat to the surroundings.
06

Calculate Heat Transfer to Environment

Subtract the work output from the total heat input to find the heat transfer to the environment: 6.00×10^9 J - 1.32×10^9 J.
07

Solving for Heat Transfer to Environment

Calculate the heat transfer to the environment using the values obtained in step 6: 6.00×10^9 J - 1.32×10^9 J = 4.68×10^9 J.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Thermodynamics
Thermodynamics is the branch of physics that deals with the relationships between heat and other forms of energy. In essence, it explores the principles governing the conversion of heat into mechanical work and vice versa. It operates under four fundamental laws that lay the foundations of energy transformations and helps us understand the behavior of systems in response to changes in temperature, volume, and pressure.

For the case of heat engines, which are thermodynamic systems that convert heat energy into mechanical work, these laws prescribe how energy can be efficiently transformed from one form to another. The efficiency of a heat engine, as explored in the textbook exercise, is a critical aspect determined by thermodynamics. It measures the ratio of the useful work output to the heat input into the system. Efficiency is intrinsic to thermodynamic cycles and is a key factor in evaluating the performance of real-world systems such as car engines and power plants.
Calculating Work Output
Work output is a term frequently used in engineering and physics that refers to the energy transferred by a system during a process where force is applied. To calculate the work output of a heat engine, it is crucial to know both the amount of heat energy that enters the system and the efficiency of the engine in converting that heat into work.

In the textbook exercise, the formula to find the work output is given by multiplying the efficiency (in decimal form) with the heat input. This mathematical approach translates the conceptual understanding of energy conversion into a quantifiable measure. It's vital to apply the correct units for energy—joules (J) in the International System of Units—and to ensure that efficiency is converted from a percentage to a decimal before calculations.

Tip for Calculation:

Always double-check the units and conversion of efficiency to avoid common mistakes. Remember, the more accurate your input values, the more reliable your calculated work output will be.
Heat Transfer Dynamics
Heat transfer is another fundamental concept in thermodynamics, defining how thermal energy moves from one body or system to another with a different temperature. In a heat engine, some of the energy is always lost to the environment because no engine can be 100% efficient due to the second law of thermodynamics. Thus, any energy that is not converted into work is ultimately released as heat.

The textbook exercise demonstrates calculating the amount of heat transferred to the environment by subtracting the work output from the total heat input. This ensures the principle of conservation of energy is respected, where the total energy remains constant in an isolated system, merely transitioning from one form to another or from one part of the system to another.

Note on Energy Conservation:

Determining the heat transfer to the environment is not just a measure of energy 'wasted' but is a critical part in calculating thermal efficiency and designing systems to minimize energy loss for environmental and economic benefits.

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Most popular questions from this chapter

(a) The Sun orbits the Milky Way galaxy once each \(2.60 \times 10^{8} \mathrm{y},\) with a roughly circular orbit averaging \(3.00 \times 10^{4}\) light years in radius. (A light year is the distance traveled by light in 1 y.) Calculate the centripetal acceleration of the Sun in its galactic orbit. Does your result support the contention that a nearly inertial frame of reference can be located at the Sun? (b) Calculate the average speed of the Sun in its galactic orbit. Does the answer surprise you?

A 4-ton air conditioner removes 5.06×107J (48,000 British thermal units) from a cold environment in 1.00 h. (a) What energy input in joules is necessary to do this if the air conditioner has an energy efficiency rating (EER) of 12.0? (b) What is the cost of doing this if the work costs 10.0 cents per 3.60×106J (one kilowatt-hour)? (c) Discuss whether this cost seems realistic. Note that the energy efficiency rating (EER) of an air conditioner or refrigerator is defined to be the number of British thermal units of heat transfer from a cold environment per hour divided by the watts of power input.

Astrology, that unlikely and vague pseudoscience, makes much of the position of the planets at the moment of one's birth. The only known force a planet exerts on Earth is gravitational. (a) Calculate the magnitude of the gravitational force exerted on a \(4.20 \mathrm{kg}\) baby by a \(100 \mathrm{kg}\) father \(0.200 \mathrm{m}\) away at birth (he is assisting, so he is close to the child). (b) Calculate the magnitude of the force on the baby due to Jupiter if it is at its closest distance to Earth, some \(6.29 \times 10^{11} \mathrm{m}\) away. How does the force of Jupiter on the baby compare to the force of the father on the baby? Other objects in the room and the hospital building also exert similar gravitational forces. (Of course, there could be an unknown force acting, but scientists first need to be convinced that there is even an effect, much less that an unknown force causes it.)

This problem compares the energy output and heat transfer to the environment by two different types of nuclear power stations—one with the normal efficiency of 34.0%, and another with an improved efficiency of 40.0%. Suppose both have the same heat transfer into the engine in one day, 2.50×1014J. (a) How much more electrical energy is produced by the more efficient power station? (b) How much less heat transfer occurs to the environment by the more efficient power station? (One type of more efficient nuclear power station, the gas-cooled reactor, has not been reliable enough to be economically feasible in spite of its greater efficiency.)

(a) What is the radius of a bobsled turn banked at \(75.0^{\circ}\) and taken at \(30.0 \mathrm{m} / \mathrm{s},\) assuming it is ideally banked? (b) Calculate the centripetal acceleration. (c) Does this acceleration seem large to you?

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