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Suppose you want to operate an ideal refrigerator with a cold temperature of ?10.0ºC, and you would like it to have a coefficient of performance of 7.00. What is the hot reservoir temperature for such a refrigerator?

Short Answer

Expert verified
Assuming the steps are followed correctly with the correct formulas, the hot reservoir temperature (in Kelvin) would be found to be higher than the cold reservoir temperature by a factor determined by COP.

Step by step solution

01

Understanding the Coefficient of Performance (COP)

The coefficient of performance (COP) for a refrigerator is given by the formula: \[COP_\text{ref} = \frac{T_C}{T_H-T_C}\] where, \(T_C\) is the cold reservoir temperature in kelvins, \(T_H\) is the hot reservoir temperature in kelvins, and \(COP_{ref}\) is the coefficient of performance of the refrigerator. We are given that \(COP_{ref} = 7.00\) and \(T_C = -10.0ºC\)
02

Converting the Cold Reservoir Temperature to Kelvin

First, convert the cold reservoir temperature from Celsius to Kelvin using the formula \[T = T(ºC) + 273.15\]. So, \[T_C = -10.0ºC + 273.15\]. Calculate this to find the value of \(T_C\) in kelvins.
03

Calculating the Hot Reservoir Temperature

Rearrange the COP formula to solve for the hot reservoir temperature (\(T_H\)): \[T_H = T_C + \frac{T_C}{COP_{ref}}\]. After calculating the value of \(T_C\) in kelvins from the previous step, substitute \(T_C\) and \(COP_{ref}\) into the formula to find \(T_H\).
04

Converting the answer back to Celsius

If the hot reservoir temperature is needed in Celsius, convert it back from Kelvin by subtracting 273.15: \[T_{H}(ºC) = T_{H}(K) - 273.15\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Thermodynamics and Refrigeration
Thermodynamics plays a crucial role in understanding how refrigeration systems operate. It is a branch of physics that deals with heat, work, and the forms of energy involved in a system. At the heart of thermodynamics lie the laws of thermodynamics, which provide a framework for predicting and explaining the energy transformations that occur in refrigeration processes.

A refrigeration cycle is a perfect example of these principles in action. It's a crucial concept in thermodynamics that involves the removal of heat from a space or substance and expelling it to another area. This cycle typically includes four main components: the evaporator, compressor, condenser, and expansion valve. It functions by transforming a refrigerant within these components from a liquid to a gas and back to a liquid again. Each component of the cycle contributes to the transfer of heat, utilizing the principles of thermodynamics such as energy conservation and entropy.
Breaking Down the Refrigeration Cycle
The refrigeration cycle is an application of thermodynamic principles used to transfer heat from an area that needs to be cooled (inside a refrigerator, for instance) to an external environment. This cyclic process consists of four main stages:

  • Evaporation: The refrigerant absorbs heat from the interior of the refrigerator and evaporates at a low pressure and temperature.
  • Compression: The evaporated refrigerant is compressed by the compressor, raising its temperature and pressure.
  • Condensation: The hot compressed refrigerant releases the absorbed heat to the outside atmosphere and condenses into a liquid in the condenser.
  • Expansion: The high-pressure liquid refrigerant cools down through expansion, lowering its pressure and temperature, ready for the cycle to start again at the evaporator.
The coefficient of performance (COP) measures how effective this cycle is by comparing the amount of heat removed from the cold space to the work input required by the compressor. The higher the COP, the more efficient the refrigeration cycle is. Essential to the calculation of COP is the accurate measurement of temperatures, which is where the Kelvin temperature scale becomes useful.
The Kelvin Temperature Scale in Thermodynamics
In thermodynamic processes, temperature measurement is vital, and for this reason, the Kelvin temperature scale is predominantly used. It is an absolute temperature scale starting at absolute zero, the point at which molecules theoretically have no kinetic energy. Unlike the Celsius or Fahrenheit scales, the Kelvin scale does not use degrees. Instead, it simply measures temperature in Kelvins (K).

One key reason the Kelvin scale is preferred in scientific and thermodynamics calculations is that it allows for the expression of thermal energy relationships in a linear fashion. For example, with respect to the coefficient of performance (COP) formula, \(COP_\text{ref} = \dfrac{T_C}{T_H-T_C}\), the temperatures must be measured in Kelvins to ensure the equation is dimensionally consistent and to avoid negative temperatures, which could complicate computations.

To solve the textbook exercise, the cold reservoir temperature (\(T_C\)) first needs to be converted from Celsius to Kelvin. This critical step was accurately detailed in the step-by-step solution, highlighting that a sound understanding of the Kelvin scale is necessary to correctly calculate the required hot reservoir temperature for the efficient operation of a refrigerator.

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