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What is the Fahrenheit temperature of a person with a \(39.0^{\circ} \mathrm{C}\) fever?

Short Answer

Expert verified
The Fahrenheit temperature of a person with a \(39.0^{\rc}\text{C}\) fever is \(102.2^{\rc}\text{F}\).

Step by step solution

01

Understand the Conversion Formula

Recall the Celsius to Fahrenheit conversion formula, which is given by: \(F = \frac{9}{5}C + 32\). This is the formula we will use to convert \(39.0^{\rc}\text{C}\) to Fahrenheit.
02

Plug in the Celsius Temperature

Insert the Celsius temperature (\(C = 39.0\text{C}\)) into the conversion formula: \(F = \frac{9}{5} \cdot 39.0 + 32\).
03

Perform the Multiplication

First, multiply 39.0 by \(\frac{9}{5}\): \(\frac{9}{5} \cdot 39.0 = 70.2\).
04

Add 32 to the Result

Next, add 32 to this result to get the Fahrenheit temperature: \(70.2 + 32 = 102.2\). Therefore, the temperature in Fahrenheit is \(102.2^{\rc}\text{F}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Temperature Conversion
Temperature conversion is a fundamental process in various scientific fields and day-to-day life, enabling us to relate temperature values from one unit system to another. Fahrenheit and Celsius are two temperature scales that are commonly used for this purpose.

Converting temperature from Celsius to Fahrenheit can often seem complex, but it becomes clear and straightforward when we understand the conversion formula. The basic formula for converting Celsius to Fahrenheit is: \( F = \frac{9}{5}C + 32 \). This formula shows that to get from Celsius to Fahrenheit, one multiplies the Celsius value by \(\frac{9}{5}\) (or 1.8) and then adds 32 to the result.

To ensure that students fully comprehend this formula's application, let's revisit the exercise provided. A fever of \(39.0^{\rc}\text{C}\) is converted to Fahrenheit by plugging the value into the formula resulting in \(70.2\), and then by adding 32, we arrive at \(102.2^{\rc}\text{F}\). This example provides a vivid illustration of how temperature conversion is efficiently accomplished using this formula.
Physics Temperature
In physics, temperature is a measure of the average kinetic energy of the particles in a substance. It's an essential concept because it affects various physical properties, such as density, state of matter, and energy transfer. The Celsius (\(^{\rc}\text{C}\)) and Fahrenheit (\(^{\rc}\text{F}\)) scales are both used to express temperature, but they have different starting points (the freezing point of water) and scale increments.

The Celsius scale is part of the metric system and is used worldwide, especially in scientific contexts. It sets the freezing point of water at \(0^{\rc}\text{C}\) and the boiling point at \(100^{\rc}\text{C}\) at standard atmospheric pressure. In contrast, the Fahrenheit scale, primarily used in the United States, sets the freezing point of water at \(32^{\rc}\text{F}\) and the boiling point at \(212^{\rc}\text{F}\).

Understanding the concept of physics temperature is vital for students because it not only helps them comprehend the behavior of matter under different conditions but also enables them to convert temperatures between different unit systems effectively, facilitating communication and collaboration in science.
Unit Conversion
Unit conversion is a critical skill in various educational fields, especially in science and mathematics. It allows for the translation of measurements from one system of units to another, ensuring consistency and comparability of data. Unit conversions require a clear understanding of the relationship between different units and the proper use of conversion factors to make accurate and meaningful translations of quantities.

When converting temperature or any other unit, one must identify the correct conversion formula or factor. For instance, converting Celsius to Fahrenheit involves a specific formula, while converting inches to centimeters involves a different fixed conversion rate (1 inch = 2.54 cm).

Students are advised to focus on learning the basic conversion formulas and factors by heart, ensure that they use the correct units in calculations, and practice with a variety of exercises. Consistent practice provides familiarity and ultimately helps students feel confident in executing unit conversions without hesitation, which is key to success in many problem-solving scenarios.

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Most popular questions from this chapter

What net external force is exerted on a 1100 -kg artillery shell fired from a battleship if the shell is accelerated at \(2.40 \times 10^{4} \mathrm{m} / \mathrm{s}^{2} ?\) What is the magnitude of the force exerted on the ship by the artillery shell?

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A bicycle tire has a pressure of \(7.00 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}\) at a temperature of \(18.0^{\circ} \mathrm{C}\) and contains \(2.00 \mathrm{~L}\) of gas. What will its pressure be if you let out an amount of air that has a volume of \(100 \mathrm{~cm}^{3}\) at atmospheric pressure? Assume tire temperature and volume remain constant.

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A 75.0-kg man stands on a bathroom scale in an elevator that accelerates from rest to \(30.0 \mathrm{m} / \mathrm{s}\) in \(2.00 \mathrm{s}\). (a) Calculate the scale reading in newtons and compare it with his weight. (The scale exerts an upward force on him equal to its reading.) (b) What is unreasonable about the result? (c) Which premise is unreasonable, or which premises are inconsistent?

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