/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 (a) Verify that a \(19.0 \%\) de... [FREE SOLUTION] | 91影视

91影视

(a) Verify that a \(19.0 \%\) decrease in laminar flow through a tube is caused by a \(5.00 \%\) decrease in radius, assuming that all other factors remain constant, as stated in the text. (b) What increase in flow is obtained from a \(5.00 \%\) increase in radius, again assuming all other factors remain constant?

Short Answer

Expert verified
A 5% decrease in radius leads to approximately a 18.55% decrease in flow, which verifies the 19.0% decrease. A 5% increase in radius leads to approximately a 21.55% increase in flow.

Step by step solution

01

Understanding the Relationship

The flow of fluid through a tube in laminar flow is given by Poiseuille's Law, which states that the flow rate (Q) through a tube is directly proportional to the fourth power of the radius (r) of the tube. Mathematically, this can be expressed as: Q 鈭 r^4. This means that if the radius of the tube is decreased by a percentage, the flow rate will decrease by a percentage of the fourth power of the change in radius.
02

Calculating the Decrease in Flow Due to Radius Reduction

Let the initial radius of the tube be r. A 5.00% decrease in the radius will make the new radius equal to 0.95r (since 100% - 5.00% = 95.00%, or 0.95 in decimal form). To find the percentage decrease in flow, we calculate (0.95r)^4 and compare this to the initial flow r^4. So, the new flow rate is (0.95)^4 times the original flow rate.
03

Percentage Decrease in Flow

Compute the decrease in flow rate using the formula: Percentage Decrease = [(Original Flow - New Flow) / Original Flow] x 100. Substituting the values we get Percentage Decrease = [(1 - (0.95)^4) x 100]%. This will give the actual percentage decrease in flow due to the decrease in radius.
04

Calculating the Increase in Flow Due to Radius Increase

For a 5.00% increase in the radius, the new radius becomes 1.05r. We calculate the new flow rate as (1.05r)^4 and compare it to the initial flow rate r^4 to find the percentage increase in flow.
05

Percentage Increase in Flow

To find the increase percentage, use the formula: Percentage Increase = [(New Flow - Original Flow) / Original Flow] x 100. Substitute the values we get Percentage Increase = [((1.05)^4 - 1) x 100]%. This will give the actual percentage increase in flow resulting from the increase in radius.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Poiseuille's Law
In the world of fluid dynamics, Poiseuille's Law is a fundamental principle that describes the flow of viscous fluids in pipes. According to this law, the flow rate, typically denoted by the symbol \( Q \), is directly proportional to the fourth power of the pipe's radius \( r \), when the flow is steady and laminar. It鈥檚 important to point out that laminar flow refers to a smooth, orderly movement of fluid particles in parallel layers with no disruption between them.

Mathematically, Poiseuille's Law can be expressed as:\[ Q \propto r^4 \]. This implies that small changes in the radius of the tube can lead to significant changes in the flow rate. Understanding this law is critical because it forms the basis of many calculations in fields such as engineering, medical physiology, and meteorology, where the flow of liquids and gases through pipes or vessels is common. It's what links the tube's dimensions and the fluid's properties to how quickly the fluid can be transported through the tube.
Fluid Dynamics
Fluid dynamics is a branch of physics that deals with the movement of fluids (liquids and gases) and how forces affect them. It involves complex calculations and principles that describe the flow behavior; laminar and turbulent flow being two key concepts within this subject. Laminar flow, as mentioned earlier, is characterized by smooth, constant fluid motion in parallel layers. On the other hand, turbulent flow is chaotic, with swirling eddies and unpredictable motion.

In the context of the homework problem, we are dealing with laminar flow within a tube. This simplifies the situation as laminar flow allows for more predictable outcomes governed by Poiseuille's Law. Real-world applications of fluid dynamics range from designing water supply systems and aircraft to studying blood flow in the human body, highlighting its importance across multiple industries.
Percentage Decrease Calculation
Calculating the percentage decrease is a mathematical way to represent a reduction in a quantity relative to its original value. It鈥檚 calculated by finding the difference between the original and the new values, dividing that by the original value, and then multiplying by 100 to get a percentage.

For instance, in the exercise, the initial flow rate is affected by a change in the radius of the tube. To calculate the percentage decrease in flow rate, the formula is:\[ \text{Percentage Decrease} = \left(\frac{\text{Original Flow} - \text{New Flow}}{\text{Original Flow}}\right) \times 100 \]. This calculation is crucial as it provides a clear way to quantify changes and understand the impact of alterations in physical properties like the radius of a tube in a fluid system.
Radius Impact on Flow Rate
The radius of a tube is a critical factor that influences the flow rate of a fluid passing through it under laminar conditions. As Poiseuille's Law indicates, the flow rate is proportional to the fourth power of the radius. Hence, even small changes in the radius can lead to drastic changes in the flow rate. In the context of this exercise, a 5% change in radius doesn't result in a simple 5% change in flow rate but rather an exponential effect due to the fourth power relationship.

The relationship can be visualized as such: when the radius is decreased by 5%, the flow rate doesn鈥檛 just decrease by 5%; it decreases by approximately 19%, as calculated in the exercise steps. Conversely, a 5% increase in radius results in a flow rate that is more than 5% higher. This underlines the importance of the radius in controlling flow within systems like pipes, blood vessels, and other conduits.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Roofs are sometimes pushed off vertically during a tropical cyclone, and buildings sometimes explode outward when hit by a tornado. Use Bernoulli's principle to explain these phenomena.

A sump pump (used to drain water from the basement of houses built below the water table) is draining a flooded basement at the rate of \(0.750 \mathrm{~L} / \mathrm{s}\), with an output pressure of \(3.00 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}\). (a) The water enters a hose with a \(3.00\) \(\mathrm{cm}\) inside diameter and rises \(2.50 \mathrm{~m}\) above the pump. What is its pressure at this point? (b) The hose goes over the foundation wall, losing \(0.500 \mathrm{~m}\) in height, and widens to \(4.00 \mathrm{~cm}\) in diameter. What is the pressure now? You may neglect frictional losses in both parts of the problem.

A seagull flies at a velocity of \(9.00 \mathrm{m} / \mathrm{s}\) straight into the wind. (a) If it takes the bird 20.0 min to travel \(6.00 \mathrm{km}\) relative to the Earth, what is the velocity of the wind? (b) If the bird turns around and flies with the wind, how long will he take to return \(6.00 \mathrm{km} ?\) (c) Discuss how the wind affects the total round-trip time compared to what it would be with no wind.

Blood is pumped from the heart at a rate of \(5.0 \mathrm{~L} / \mathrm{min}\) into the aorta (of radius \(1.0 \mathrm{~cm}\) ). Determine the speed of blood through the aorta.

(a) What is the fluid speed in a fire hose with a 9.00-cm diameter carrying \(80.0\) L of water per second? (b) What is the flow rate in cubic meters per second? (c) Would your answers be different if salt water replaced the fresh water in the fire hose?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.