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What value of inductance should be used if a \(20.0 \mathrm{k} \Omega\) reactance is needed at a frequency of \(500 \mathrm{Hz} ?\)

Short Answer

Expert verified
The inductance (L) should be approximately 6.366 henrys (H).

Step by step solution

01

Understanding Reactance in Inductors

Reactance in inductors, denoted as XL, is given by the formula XL = 2πfL, where f is the frequency and L is the inductance. The goal is to find the value of inductance L such that the reactance XL equals 20 kΩ at a frequency of 500 Hz.
02

Arranging the Formula to Solve for Inductance (L)

To solve for L, rearrange the formula for reactance (XL = 2Ï€fL) to isolate L. L = XL / (2Ï€f).
03

Calculating the Inductance (L)

Using the given values, XL = 20,000 Ω (since 20 kΩ is equivalent to 20,000 Ω), and f = 500 Hz, substitute these into the rearranged formula to find L. L = 20,000 / (2π × 500).
04

Performing the Calculation

Calculate L using the values from Step 3. L = 20,000 / (1,000π) Ω·Hz. This simplifies the arithmetic to find L = 20 / π H, or approximately L ≈ 6.366 H.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inductance Calculation
Understanding how to calculate inductance is critical for students and professionals working with electrical circuits. In simple terms, inductance is a measure of an inductor's ability to store energy in a magnetic field when electrical current flows through it. To calculate the inductance of an inductor, one can use the formula for inductive reactance, which is expressed as \( XL = 2\text{Ï€}fL \). Here, \( XL \) is the inductive reactance, \( f \) is the frequency of the AC current, and \( L \) is the inductance.

When you are given a desired reactance and frequency, as in the exercise, you can find the inductance by rearranging the formula to \( L = \frac{XL}{2\text{π}f} \). Make sure to convert all units to their base SI units before substituting them into the formula to obtain the correct value of inductance in henrys (H). For instance, a kilo-ohm (kΩ) should be converted to ohms (Ω) and kilohertz (kHz) to hertz (Hz).

  • Given reactance, \( XL \): Convert \( 20.0 \text{kΩ} \) to \( 20000 \text{Ω} \)
  • Frequency, \( f \): Use the given frequency of \( 500 \text{Hz} \) as is since it's already in the correct unit.
  • Inductance, \( L \): Apply the above conversion and calculation steps to find the value.
Reactance Formula
Reactance is a component of impedance, a broader concept that encompasses both resistance and reactance in an AC circuit. Specifically, the reactance we discuss here is inductive reactance. Reactance is not constant but varies with frequency, making it a dynamic factor in an AC circuit's total impedance. The formula for inductive reactance is \( XL = 2\text{Ï€}fL \).

Breaking it down:
  • \( XL \) represents the inductor's opposition to changes in current flow.
  • \( f \) is the frequency, providing the rate at which the AC current changes direction.
  • \( L \) is the inductance, signifying the inductor's capacity to generate electromotive force.
Understanding this relationship is vital as it shows that the reactance increases with both the frequency (\text{f}) and the inductance (\text{L}). Conversely, to achieve a specific reactance at a lower frequency, one would require a higher inductance.

In our example, for a desired reactance of \( 20 k\text{Ω} \) at a low frequency of \( 500 \text{Hz} \), one would need a relatively large inductance, thus the resultant \( 6.366 \text{H} \).
Electrical Oscillations
Electrical oscillations occur in circuits where inductors and capacitors interact, often referred to as LC circuits. They are fundamental to understanding a wide array of AC phenomena and can be analyzed to predict how a circuit's voltage and current will change over time. Oscillations are the result of energy transfer between the inductor’s magnetic field and the capacitor’s electric field.

  • The frequency of oscillation, or resonant frequency, for an LC circuit is given by \( f_0 = \frac{1}{2\text{Ï€}\text{sqrt}(LC)} \), where \( L \) is the inductance and \( C \) is the capacitance.
  • An inductor’s reactance plays a pivotal role in these oscillations. The higher the reactance, the lower the current oscillations for a given frequency.
  • Understanding the inductive reactance helps in designing circuits with desired oscillatory behaviors, important in radio transmitters, receivers, and filter circuits.
These principles are not only theoretically engaging but have practical applications in designing electronic devices, managing signal processing, and even in determining the characteristics of power systems.

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