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A very large, superconducting solenoid such as one used in MRI scans, stores \(1.00 \mathrm{M} \mathrm{J}\) of energy in its magnetic field when 100 A flows. (a) Find its self-inductance. (b) If the coils "go normal," they gain resistance and start to dissipate thermal energy. What temperature increase is produced if all the stored energy goes into heating the 1000 kg magnet, given its average specific heat is \(200 \mathrm{J} / \mathrm{kg} \cdot^{\circ} \mathrm{C} ?\)

Short Answer

Expert verified
The self-inductance of the solenoid is 200 H, and the temperature increase is 5°C.

Step by step solution

01

Determine self-inductance

To find the self-inductance (L) of the solenoid, we use the energy stored in a solenoid, given by the formula: \[\begin{equation}E = \frac{1}{2}LI^2\end{equation}\]where E is the energy stored, and I is the current. Rearranging this formula to solve for L, we get: \[\begin{equation}L = \frac{2E}{I^2}\end{equation}\]
02

Calculate self-inductance

Now, using the provided values for E (energy stored) and I (current), we can calculate L. \[\begin{equation}L = \frac{2 \times 1.00 \times 10^6 \mathrm{J}}{(100 \mathrm{A})^2} = \frac{2 \times 10^6 \mathrm{J}}{10^4 \mathrm{A^2}} = 200 \mathrm{H}\end{equation}\]
03

Determine the temperature increase

We use the formula relating the heat Q absorbed or released by a substance to the change in temperature (\(\Delta T\)), its mass (m), and its specific heat capacity (c): \[\begin{equation}Q = mc\Delta T\end{equation}\]We implement the known values of Q (the stored energy), m (mass), and c (specific heat) to find \(\Delta T\).
04

Calculate temperature increase

Rearranging the formula to solve for \(\Delta T\), we get:\[\begin{equation}\Delta T = \frac{Q}{mc}\end{equation}\]Substituting the given values, we find:\[\begin{equation}\Delta T = \frac{1.00 \times 10^6 \mathrm{J}}{1000 \mathrm{kg} \times 200 \mathrm{J/kg^\circ C}} = \frac{10^6 \mathrm{J}}{2 \times 10^5 \mathrm{J/^\circ C}} = 5^\circ\mathrm{C}\end{equation}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Energy Storage
Understanding how energy is stored in magnetic fields is critical for the operation of devices such as MRI scanners and electric transformers. Magnetic energy storage refers to the conservation of energy within the magnetic field of a solenoid or inductor. The key relationship is captured by the formula \[E = \frac{1}{2}LI^2\], where \(E\) is the energy stored in the solenoid, \(L\) is the self-inductance, and \(I\) is the current flowing through the solenoid.

Self-inductance is a property of the solenoid that quantifies its ability to induce voltage as a result of a change in current, which in turn affects energy storage. For a given solenoid, the higher the self-inductance, the more energy it can store. This is essential in many applications where energy needs to be stored temporarily, such as in superconducting magnetic energy storage systems used to stabilize power grids.

The example of the MRI scanner's solenoid illustrates these principles. By using the given values, it shows how to apply the formula to determine the amount of energy that can be stored. With 100 A of current, the solenoid stores 1.00 MJ (mega joules), demonstrating a high self-inductance that enables substantial energy storage. This capacity is critical for medical imaging technology.
Specific Heat and Temperature Change
Specific heat capacity is the amount of heat required to change the temperature of a mass unit of a substance by one degree Celsius. It's a key factor in understanding how different materials react to energy transfer, particularly in the context of thermal energy.

The formula \[Q = mc\Delta T\] links thermal energy (Q), mass (m), specific heat capacity (c), and temperature change (\(\Delta T\)). When heat is added to or removed from a substance, specific heat capacity determines how much the temperature will change.

In the solenoid exercise, if the coils 'go normal' and lose their superconductivity, they gain resistance, which causes the stored energy to convert into thermal energy and increase the temperature. Substituting the known values into the formula results in a calculated temperature increase. This concept demonstrates how energy conservation plays a role in different contexts, such as the heat dissipated by an electromagnet when it transitions from a superconducting state to a normal state, and the implications of specific heat in such scenarios.
Superconducting Solenoids
Superconducting solenoids are a type of electromagnet made from coils of superconducting wire. They become superconducting—that is, they conduct electricity without resistance—when cooled below a specific temperature. This property is especially useful in applications requiring strong and stable magnetic fields, such as MRI scanners.

When a solenoid becomes superconducting, it can store a large amount of energy in its magnetic field without any loss, as there's no resistance to dissipate the energy as heat. If, however, the solenoid's temperature rises above the critical temperature (i.e., it 'goes normal'), it loses its superconducting properties, and resistance within the coils increases. Consequently, the stored magnetic energy is released in the form of thermal energy, leading to a rise in temperature – a core aspect illustrated in the step-by-step solution to the exercise.

Superconducting solenoids are essential in various technological and medical fields due to their ability to generate large magnetic fields with high efficiency. The absence of resistive losses and the strong, stable magnetic fields make them invaluable in precision equipment such as MRI machines, which require consistent and powerful magnetic fields to operate effectively.

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