/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 A 500 -turn coil with a \(0.250 ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A 500 -turn coil with a \(0.250 \mathrm{m}^{2}\) area is spun in the Earth's \(5.00 \times 10^{-5} \mathrm{T}\) field, producing a \(12.0 \mathrm{kV}\) maximum emf. (a) At what angular velocity must the coil be spun? (b) What is unreasonable about this result? (c) Which assumption or premise is responsible?

Short Answer

Expert verified
The angular velocity \(\omega\) is approximately \(\frac{12.0 \times 10^{3}}{0.0625}\) rad/s. The result is unreasonably high and suggests an incorrect assumption, likely that a mechanical system can achieve and sustain such extreme speeds.

Step by step solution

01

Understanding the Faraday's Law of Induction

Faraday's Law states that the magnitude of the induced emf in a coil is equal to the rate of change of magnetic flux through the coil. It is given by the formula \( |\varepsilon| = N|\frac{d\Phi_B}{dt}| \), where \( \varepsilon \) is the induced emf, \( N \) is the number of turns in the coil, and \( \Phi_B \) represents the magnetic flux.
02

Calculate the change in magnetic flux

The magnetic flux through the coil is given by \( \Phi_B = B \cdot A \cdot \cos(\theta) \), where \( B \) is the magnetic field strength, \( A \) is the area of the coil, and \( \theta \) is the angle between the magnetic field and the normal to the plane of the coil. Since the coil is being spun, \( \theta \) changes with time, leading to a change in flux. When \( \theta \) changes at a uniform rate, which we denote as angular velocity \( \omega \), the expression for magnetic flux becomes a function of time: \( \Phi_B(t) = B \cdot A \cdot \cos(\omega t) \).
03

Relate angular velocity to maximum emf

The maximum emf occurs when \( d\Phi_B/dt \) is at its maximum value, which is when \( \cos(\omega t) \) is equal to zero and \( \sin(\omega t) \) is equal to one. Taking the derivative and using \( \omega \) for angular velocity, we have \( |\varepsilon| = N \cdot B \cdot A \cdot |\omega \cdot \sin(\omega t)| \). For maximum emf, we set \( \sin(\omega t) = 1 \), thus \( |\varepsilon| = N \cdot B \cdot A \cdot \omega \).
04

Solve for the angular velocity \(\omega\)

Rearrange the formula to solve for \(\omega\): \( \omega = \frac{|\varepsilon|}{N \cdot B \cdot A} \). Substitute the given values of \(\varepsilon = 12.0 \times 10^{3}\) V (since 1 kV = 1000 V), \(N = 500\), \(B = 5.00 \times 10^{-5}\) T, and \(A = 0.250 \) m^2 into the equation to find the angular velocity.
05

Calculate the value of the angular velocity

Insert the values to yield \( \omega = \frac{12.0 \times 10^{3}}{500 \cdot 5.00 \times 10^{-5} \cdot 0.250} \), which simplifies to \( \omega = \frac{12.0 \times 10^{3}}{0.0625} \). After calculating, you will get the angular velocity in radians per second.
06

Evaluate the result

Check whether the answer from the previous step is reasonable given physical and practical constraints. If the angular velocity is too high, it might not be practically achievable and could indicate a flaw in the premise or assumptions.
07

Identify the unreasonable assumptions

Assuming the calculation leads to an unreasonably high angular velocity, investigate the assumptions made. In this scenario, it could be the assumption that a coil can spin at such a high rate without suffering mechanical failure or that such an emf can be achieved with the given parameters.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux
Imagine a flat surface, like a loop of wire, placed in a magnetic field. Whenever this surface is exposed to magnetic lines of force, we say that magnetic flux is threading through it. It's akin to the amount of magnetic field that penetrates the surface. We quantify this with the formula \( \Phi_B = B \cdot A \cdot \cos(\theta) \), where \( B \) is the magnetic field strength, \( A \) is the area the field permeates, and \( \theta \) is the angle between the field directions to the area's normal. When \( \theta = 0 \) (field perpendicular to the area), the flux is greatest. If the field is parallel (\( \theta = 90^\circ \)), the flux through the area is nil, since no field lines pass perpendicularly.

In the given exercise, the coil's rotation changes the angle \( \theta \) over time, leading to a dynamic flux. A critical part of Faraday's Law, magnetic flux's rate of change induces an emf in the coil—this is central to many technologies like electric generators and transformers.
Angular Velocity
Angular velocity is a measure of how quickly an object rotates or spins around a particular point or axis. In physics, we symbolize it with the Greek letter \( \omega \) and calculate it as angle turned per unit time, most often in radians per second. It's comparable to linear velocity, but instead of covering 'distance per time', it's about 'angle per time'.

For objects in circular motion, like the spinning coil in our exercise, angular velocity tells us how fast the coil's angle proceeds compared to time, hence transforming the magnetic flux through it. To get the maximum induced emf, the coil must rotate at a specific rate, which is this very angular velocity we are interested in. When computing the angular velocity necessary for the induced emf, one may find the calculated speed unrealistic—exceed as what would be mechanically viable, as hinted in the exercise's evaluation step.
Induced EMF
Electromotive force (emf) isn't a force, despite its name—it's the electrical action produced by non-electrical means. An induced emf is what's generated when an electric circuit or part of it is subjected to a changing magnetic field, which is Faraday's Law of Induction's central concept. It is expressed as \( |\varepsilon| = N|\frac{d\Phi_B}{dt}| \), signifying that the induced emf (\( \varepsilon \) in volts) is proportional to the number of coil turns (\( N \) ) times the rate of change of magnetic flux (\( \Phi_B \) ) through the coil.

In practical terms, induced emf is the principle behind the generation of electricity. When the coil in the exercise spins, it changes the flux, thus inducing an emf. The 'maximum emf' referred to is this peak value, which occurs when the change in flux over time is at its highest. Understanding this relationship helps us engineer systems that can convert mechanical rotation into electrical energy, respecting the constraints of the real world to prevent the sort of impractical outcome the exercise prompts us to scrutinize.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An American traveler in New Zealand carries a transformer to convert New Zealand's standard 240 V to 120 V so that she can use some small appliances on her trip. (a) What is the ratio of turns in the primary and secondary coils of her transformer? (b) What is the ratio of input to output current? (c) How could a New Zealander traveling in the United States use this same transformer to power her 240 V appliances from \(120 \mathrm{V} ?\)

(a) The plug-in transformer for a laptop computer puts out \(7.50 \mathrm{V}\) and can supply a maximum current of \(2.00 \mathrm{A}\). What is the maximum input current if the input voltage is 240 V? Assume \(100 \%\) efficiency. (b) If the actual efficiency is less than \(100 \%,\) would the input current need to be greater or smaller? Explain.

When the 20.0 A current through an inductor is turned off in \(1.50 \mathrm{ms},\) an \(800 \mathrm{V}\) emf is induced, opposing the change. What is the value of the self-inductance?

What percentage of the final current \(I_{0}\) flows through an inductor \(L\) in series with a resistor \(R\), three time constants after the circuit is completed?

Discuss the possibility that star velocities at the edges of galaxies being greater than expected is due to unknown properties of gravity rather than to the existence of dark matter. Would this mean, for example, that gravity is greater or smaller than expected at large distances? Are there other tests that could be made of gravity at large distances, such as observing the motions of neighboring galaxies?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.