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Note: Data taken from figures can be assumed to be accurate to three significant digits. What are the largest and smallest resistances you can obtain by connecting a \(36.0-\Omega,\) a \(50.0-\Omega,\) and a \(700-\Omega\) resistor together?

Short Answer

Expert verified
The smallest total resistance is approximately \(20.3\,\Omega\) and the largest total resistance is \(786.0\,\Omega\).

Step by step solution

01

Determine Smallest Resistance

To get the smallest total resistance, connect all resistors in parallel. Use the formula \(\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}\), where \(R_1 = 36.0\,\Omega\), \(R_2 = 50.0\,\Omega\), and \(R_3 = 700\,\Omega\). Calculate the reciprocal of the total resistance (\(R_{total}\)).
02

Calculate Smallest Resistance

Plugging the values into the formula gives \(\frac{1}{R_{total}} = \frac{1}{36.0} + \frac{1}{50.0} + \frac{1}{700} = 0.0278 + 0.0200 + 0.00143 = 0.0492\) (rounded to three significant digits). Taking the reciprocal of that sum gives the smallest total resistance: \(R_{total} = \frac{1}{0.0492} \approx 20.3\,\Omega\).
03

Determine Largest Resistance

To find the largest total resistance, connect all resistors in series. The total resistance is the sum of individual resistances: \(R_{total} = R_1 + R_2 + R_3\).
04

Calculate Largest Resistance

Add the values of the individual resistances: \(R_{total} = 36.0\,\Omega + 50.0\,\Omega + 700\,\Omega = 786.0\,\Omega\). This is the largest total resistance you can obtain.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Series and Parallel Circuits
Understanding how resistors can be connected in circuits is crucial for mastering electronics. There are two primary ways resistors can be linked: series and parallel.

In series circuits, resistors are connected end-to-end, creating a single path for the current to follow. The total resistance in a series circuit is simply the sum of all resistors' resistances. This means that if you keep adding resistors in series, the total resistance will continue to grow. When resistors are connected in series, the current flowing through each resistor is the same, but the voltage across each can be different.

In parallel circuits, resistors are connected across the same two points, creating multiple paths for the current. The voltage across each resistor in a parallel circuit is the same, but the current can vary. To calculate the total resistance in a parallel circuit, one must consider that the reciprocal of the total resistance is the sum of the reciprocals of each individual resistance. This means adding more resistors in parallel actually decreases the total resistance since more paths are available for the current to travel.

The exercise provided illustrates how altering the configuration of the same set of resistors can give the highest and lowest possible resistances, showing the practical relevance of understanding series and parallel connections.
Resistance Calculation
The ability to calculate resistance in a circuit with multiple resistors is a fundamental skill in electrical engineering and physics. The total resistance depends on the circuit configuration: series or parallel.

In a series arrangement, calculating total resistance (\(R_{total}\)) is straightforward: it's the sum of individual resistors (\(R_{total} = R_1 + R_2 + R_3 + \text{...}\) for resistors \(R_1, R_2, R_3, \text{...}\)). In contrast, for a parallel arrangement, you need to sum up the reciprocals of each resistor's resistance and then take the reciprocal of that sum to find the total resistance (\( \frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \text{...}\) and then \(R_{total} = \frac{1}{(1/R_1 + 1/R_2 + 1/R_3 + \text{...})}\)).

It's important to note that when resistors are combined in series and parallel within the same circuit, the calculation may involve several steps: first calculating the combined resistance of parallel or series sections, and then adding these results. The step-by-step solution in the exercise illustrates this process for the simplest cases, but real-world scenarios can be much more complex.
Electrical Resistors
Electrical resistors are components used to control the flow of current in a circuit. Their main purpose is to reduce or limit the current but they also serve other functions such as dividing voltages, biasing active elements, and terminating transmission lines.

Resistors come in various shapes and sizes, but their functionality is defined by one main characteristic: their resistance, measured in ohms (\( \text{Ω} \)). This value dictates how much opposition the resistor will provide against the current flow.

There are fixed and variable resistors. Fixed resistors have a pre-determined resistance value, whereas variable ones can be adjusted, like a volume knob. The resistors described in the exercise (\(36.0\text{-Ω}, 50.0\text{-Ω}, \text{ and } 700\text{-Ω}\)) are examples of fixed resistors. When planning circuits or interpreting circuit diagrams, understanding the role and properties of resistors, as well as how they may be combined, is essential for effective design and problem-solving.

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Most popular questions from this chapter

To what value must you adjust \(R_{3}\) to balance a Wheatstone bridge, if the unknown resistance \(R_{\mathrm{x}}\) is \(100 \Omega, R_{1}\) is \(50.0 \Omega,\) and \(R_{2}\) is \(175 \Omega ?\)

(a) Find the terminal voltage of a 12.0 -V motorcycle battery having a \(0.600-\Omega\) internal resistance, if it is being charged by a current of \(10.0 \mathrm{A}\). (b) What is the output voltage of the battery charger?

A person with body resistance between his hands of \(10.0 \mathrm{k} \Omega\) accidentally grasps the terminals of a \(20.0-\mathrm{kV}\) power supply. (Do NOT do this!) (a) Draw a circuit diagram to represent the situation. (b) If the internal resistance of the power supply is \(2000 \Omega\), what is the current through his body? (c) What is the power dissipated in his body? (d) If the power supply is to be made safe by increasing its internal resistance, what should the internal resistance be for the maximum current in this situation to be 1.00 mA or less? (e) Will this modification compromise the effectiveness of the power supply for driving low-resistance devices? Explain your reasoning.

The electrical power output of a large nuclear reactor facility is \(900 \mathrm{MW}\). It has a \(35.0 \%\) efficiency in converting nuclear power to electrical. (a) What is the thermal nuclear power output in megawatts? (b) How many \({ }^{235} \mathrm{U}\) nuclei fission each second, assuming the average fission produces \(200 \mathrm{MeV?}\) (c) What mass of \({ }^{235} \mathrm{U}\) is fissioned in one year of full-power operation?

(a) What is the internal resistance of a voltage source if its terminal voltage drops by 2.00 V when the current supplied increases by \(5.00 \mathrm{A} ?\) (b) Can the emf of the voltage source be found with the information supplied?

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