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A straightforward method of finding the density of an object is to measure its mass and then measure its volume by submerging it in a graduated cylinder. What is the density of a \(240-\mathrm{g}\) rock that displaces \(89.0 \mathrm{~cm}^{3}\) of water? (Note that the accuracy and practical applications of this technique are more limited than a variety of others that are based on Archimedes' principle.)

Short Answer

Expert verified
The density of the rock is approximately 2.70 g/cm^3.

Step by step solution

01

Understand the Concept

Density is defined as the mass of an object divided by its volume. The formula for density is: density = mass/volume.
02

Identify Given Values

Identify the mass and volume of the rock from the problem statement. Mass of the rock is 240 grams and the volume displaced is given as 89.0 cubic centimeters.
03

Insert Values into the Density Formula

Use the formula from Step 1 to calculate the density, substituting in the given mass and volume. Thus, the calculation is: density = mass/volume = 240 g / 89.0 cm^3.
04

Calculate the Density

Perform the division to find the density of the rock. The result is: density = 240 g / 89.0 cm^3 density ≈ 2.70 g/cm^3. Note that the units of grams and cubic centimeters combine to give grams per cubic centimeter (g/cm^3), which is a common unit for density.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Density Formula
Density is a fundamental concept in science that relates to the amount of matter (mass) within a specific volume. The density formula, \( \text{density} = \frac{\text{mass}}{\text{volume}}\), is straightforward but extremely powerful, serving as a cornerstone in various scientific fields from materials science to fluid dynamics.

To apply this formula accurately, comprehension of its components is key. Mass, typically measured in grams or kilograms, is a measure of how much matter an object contains, while volume, measured in cubic centimeters (cm³) or liters, indicates how much space the object occupies.

When you measure the density of a substance, you're comparing its mass to its volume to determine how tightly packed the molecules are. In the context of the textbook example, to calculate the density of a rock, we would take its mass (240 grams) and divide it by the volume it displaces in water (89.0 cm³), resulting in about \(2.70 \text{ g/cm}^3\).
Mass and Volume Measurement
Accurate measurements are the foundation of any scientific inquiry, and when it comes to mass and volume measurement, precision is key.

Mass is typically measured using a balance scale, careful to account for zero errors, which ensures the true mass of an object. Electronic scales are preferred for their precision, while traditional balance scales are valued for their ability to measure relative mass differences.

Volume measurements for solids often involve the displacement of a fluid, as done in the example problem where a rock is submerged in water in a graduated cylinder. The change in water level indicates the volume of the rock. This method effectively translates irregular shapes into a measurable volume. The cylinder's calibration is crucial; hence, using a well-calibrated and precise measuring cylinder impacts the reliability of the volume measured.

Together, accurate mass and volume measurements allow us to calculate density, which has numerous practical applications in fields such as material design, buoyancy assessment, and product quality control.
Archimedes' Principle
Beyond the simple density calculation lies a foundational principle of physics known as Archimedes' principle. This principle states that a body submerged in a fluid experiences an upward force, or buoyancy, that is equal to the weight of the fluid displaced by the body.

Essentially, when an object like our rock example is submerged, it pushes away water equal to its own volume, and the water's weight then equals the buoyant force acting upon the rock. It's this force that accounts for the 'apparent loss' of weight when objects are submerged in water.

For objects that float, Archimedes' principle is used to determine their density relative to the fluid. In practical applications, this principle allows us to design ships, determine the purity of precious metals, and even measure body composition in humans. While our textbook problem used a direct measurement of volume displacement for density calculation, understanding Archimedes' principle gives us a deeper understanding of the relationship between an object's density and its behavior in a fluid environment.

This principle not only simplifies the process of finding volume (thus density), but it's also a cornerstone concept in fluid mechanics, having extensive implications across science and engineering disciplines.

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Most popular questions from this chapter

Assume air resistance is negligible unless otherwise stated. A ball is thrown straight up. It passes a 2.00 -m-high window \(7.50 \mathrm{m}\) off the ground on its path up and takes 0.312 s to go past the window. What was the ball's initial velocity? Hint: First consider only the distance along the window, and solve for the ball's velocity at the bottom of the window. Next, consider only the distance from the ground to the bottom of the window, and solve for the initial velocity using the velocity at the bottom of the window as the final velocity.

Verify that the SI unit of \(h \rho g\) is \(\mathrm{N} / \mathrm{m}^{2}\).

Freight trains can produce only relatively small accelerations and decelerations. (a) What is the final velocity of a freight train that accelerates at a rate of \(0.0500 \mathrm{m} / \mathrm{s}^{2}\) for 8.00 min, starting with an initial velocity of \(4.00 \mathrm{m} / \mathrm{s}\) ? (b) If the train can slow down at a rate of \(0.550 \mathrm{m} / \mathrm{s}^{2}\), how long will it take to come to a stop from this velocity? (c) How far will it travel in each case?

We stated in Example that a xylem tube is of radius \(2.50 \times 10^{-5} \mathrm{~m}\). Verify that such a tube raises sap less than a meter by finding \(h\) for it, making the same assumptions that sap's density is \(1050 \mathrm{~kg} / \mathrm{m}^{3}\), its contact angle is zero, and its surface tension is the same as that of water at \(20.0^{\circ} \mathrm{C}\).

The pressure exerted by a phonograph needle on a record is surprisingly large. If the equivalent of \(1.00 \mathrm{~g}\) is supported by a needle, the tip of which is a circle \(0.200 \mathrm{~mm}\) in radius, what pressure is exerted on the record in \(\mathrm{N} / \mathrm{m}^{2} ?\)

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