/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 A student drove to the universit... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A student drove to the university from her home and noted that the odometer reading of her car increased by 12.0 km. The trip took 18.0 min. (a) What was her average speed? (b) If the straight-line distance from her home to the university is \(10.3 \mathrm{km}\) in a direction \(25.0^{\circ}\) south of east, what was her average velocity? (c) If she returned home by the same path \(7 \mathrm{h} 30 \mathrm{min}\) after she left, what were her average speed and velocity for the entire trip?

Short Answer

Expert verified
The average speed to the university was 40.0 km/h. The average velocity to the university was approximately 34.3 km/h [25.0° S of E]. For the entire round trip, the average speed was 6.41 km/h, and the average velocity was 0 km/h (since there was no displacement).

Step by step solution

01

Calculate the average speed for the trip to the university

Average speed is defined as the total distance traveled divided by the total time taken. The distance is given as 12.0 km and the time is given as 18.0 minutes, which needs to be converted to hours for the speed in km/h. To convert minutes to hours, divide by 60. The calculation will look like this: Average speed = Distance / TimeAverage speed = 12.0 km / (18.0 min / 60 min/hour)Average speed = 12.0 km / 0.3 hourNow calculate the average speed.
02

Calculate the average velocity for the trip to the university

Average velocity is defined as the displacement divided by the total time taken. Displacement is a vector quantity, so direction matters. The straight-line distance and direction given is 10.3 km at 25.0 degrees south of east. Since average velocity includes direction and the time is the same as in Step 1, we can use it for the velocity calculation. The calculation will look like this: Average velocity = Displacement / TimeThe displacement vector can be represented as 10.3 km [25.0° S of E], and the time remains 0.3 hours.
03

Calculate the average speed for the entire trip

The total distance for the round trip is twice the distance of the one-way trip to the university. The total time for the round trip includes the time to the university and the return trip time, which is 7 hours and 30 minutes after she left. Convert 7 hours and 30 minutes into hours to be consistent with the units and then compute the total time. Finally, use the total distance and total time to calculate the average speed.
04

Calculate the average velocity for the entire trip

For the entire trip, the displacement is zero because she returned to her starting point. Since the displacement is zero, the average velocity will also be zero, regardless of the total time taken for the trip.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Displacement in Physics
Displacement is a term that often comes up in physics problems, particularly when dealing with motion. It refers to the change in position of an object and is a vector quantity, which means it has both magnitude and direction.

For instance, if a student travels from her home to the university, her displacement would be the straight-line distance between these two points, regardless of the actual path taken. Even if the car's odometer reads 12.0 km, the displacement might be different, precisely because it's the straight-line distance. In the example given, the displacement is reported as being 10.3 km in a specific direction (25.0° south of east). Understanding displacement is critical for analyzing motion correctly, as it differs from the total path length.
Vector Quantity
Physics problems often distinguish between scalar and vector quantities. A vector quantity includes both a magnitude and a direction, which makes it different from a scalar quantity that only has a magnitude. Speed is a scalar quantity, as it merely tells you how fast an object is moving, without considering its direction.

In contrast, velocity is a vector quantity as it describes the speed of the object in a particular direction. This is why when we discuss average velocity, we must account for both how fast the object has moved and in which direction. In the given scenario, while calculating the average velocity of the student's trip to the university, the direction specified was crucial to establish the velocity as a vector.
Average Velocity Calculation
The average velocity is obtained by dividing the displacement by the total time taken for the trip. Because displacement is a vector, the average velocity is also a vector, reflecting both the rate and the direction of travel.

In our problem's context, to calculate the student’s average velocity on her way to the university, you take her displacement (10.3 km at 25.0° south of east) and divide it by the total travel time converted into hours (18.0 minutes or 0.3 hours). This calculation gives a concise description of her motion that includes not just how fast she traveled, but also her travel direction.
Speed and Time Conversion
When calculating speed or velocity, ensuring consistent units is vital for an accurate result. Often, you'll need to convert time from minutes to hours, since speed is typically expressed in kilometers per hour (km/h).

To convert minutes to hours, divide the number of minutes by 60, because 1 hour equals 60 minutes. This step is critical when you work with physics problems that give you time in minutes, but ask for speed in km/h. In our example, to find the average speed, we convert 18 minutes to hours by dividing by 60, obtaining 0.3 hours, and then proceed with the speed calculation.
Physics Distance-Time Relationship
In physics, the relationship between distance, speed, and time is fundamental. The basic formula connecting these quantities is Speed = Distance / Time. This formula holds true for constant speed, but if the speed is not constant, you would have to use the average speed definition.

In our exercise, understanding this relationship enables us to calculate the student's average speed by dividing the distance her car's odometer increased (12.0 km) by the total time of the trip (0.3 hours). Similarly, the average speed for the complete round trip takes into account the total distance traveled back and forth and the total time including delays, such as the 7 hours and 30 minutes spent at the university before returning home.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Freight trains can produce only relatively small accelerations and decelerations. (a) What is the final velocity of a freight train that accelerates at a rate of \(0.0500 \mathrm{m} / \mathrm{s}^{2}\) for 8.00 min, starting with an initial velocity of \(4.00 \mathrm{m} / \mathrm{s}\) ? (b) If the train can slow down at a rate of \(0.550 \mathrm{m} / \mathrm{s}^{2}\), how long will it take to come to a stop from this velocity? (c) How far will it travel in each case?

A fireworks shell is accelerated from rest to a velocity of 65.0 m/s over a distance of 0.250 m. (a) How long did the acceleration last? (b) Calculate the acceleration.

Gauge pressure in the fluid surrounding an infant's brain may rise as high as \(85.0 \mathrm{~mm} \mathrm{Hg}\) ( 5 to \(12 \mathrm{~mm} \mathrm{Hg}\) is normal), creating an outward force large enough to make the skull grow abnormally large. (a) Calculate this outward force in newtons on each side of an infant's skull if the effective area of each side is \(70.0 \mathrm{~cm}^{2}\). (b) What is the net force acting on the skull?

During forced exhalation, such as when blowing up a balloon, the diaphragm and chest muscles create a pressure of \(60.0 \mathrm{~mm}\) \(\mathrm{Hg}\) between the lungs and chest wall. What force in newtons does this pressure create on the \(600 \mathrm{~cm}^{2}\) surface area of the diaphragm?

(a) Verify that work input equals work output for a hydraulic system assuming no losses to friction. Do this by showing that the distance the output force moves is reduced by the same factor that the output force is increased. Assume the volume of the fluid is constant. (b) What effect would friction within the fluid and between components in the system have on the output force? How would this depend on whether or not the fluid is moving?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.