/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 What capacitance do you need to ... [FREE SOLUTION] | 91影视

91影视

What capacitance do you need to produce a resonant frequency of 1.00 GHz, when using an 8.00 nH inductor?

Short Answer

Expert verified
To produce a resonant frequency of 1.00 GHz with an 8.00 nH inductor, a capacitance of approximately 2.53 pF is required.

Step by step solution

01

Identifying the Formula for Resonant Frequency

To find the required capacitance for a resonant frequency, use the formula for the resonant frequency of an LC circuit, which is given by \(f = \frac{1}{2\pi\sqrt{LC}}\). Here, \(f\) is the resonant frequency, \(L\) is the inductance, and \(C\) is the capacitance that we need to find.
02

Isolating the Capacitance

We need to solve the equation for \(C\) to find the capacitance. This is done by rearranging the formula: \[C = \frac{1}{{(2\pi f)^2 L}}\]
03

Plugging in the Values

Insert the values for \(f\) and \(L\) into the equation. With \(f = 1.00 \times 10^9 Hz\) (1.00 GHz) and \(L = 8.00 \times 10^{-9} H\) (8.00 nH), we have \(C = \frac{1}{{(2\pi \cdot 1.00 \times 10^9)^2 \cdot 8.00 \times 10^{-9}}}\).
04

Calculating the Capacitance

Carry out the calculation to find the capacitance: \[C = \frac{1}{{(2\pi \cdot 1.00 \times 10^9)^2 \cdot 8.00 \times 10^{-9}}} \approx 2.53 \times 10^{-15} F\], which can also be expressed as 2.53 pF (picoFarads).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

LC Circuit
An LC circuit, also known as a resonant circuit, tank circuit, or tuned circuit, is a fundamental electrical circuit that consists of an inductor, denoted as 'L', and a capacitor, denoted as 'C'. These two components are connected together either in series or in parallel. The LC circuit is key in various electronic devices where it can be used to filter signals, tune radios, or even generate oscillations in transmitters and receivers.

The behavior of an LC circuit is governed by the inductance and the capacitance. Inductors resist changes in current and store energy in a magnetic field, whereas capacitors resist changes in voltage and store energy in an electric field. When an LC circuit is powered, the energy oscillates back and forth between the inductor and the capacitor. This energy exchange occurs at a specific frequency known as the resonant frequency, which is precisely the focus of the exercise provided.
Capacitance
Capacitance is the ability of a system to store an electric charge and is measured in Farads (F). A capacitor consists of two conductors separated by an insulator or dielectric material. The insulator prevents direct current from flowing through the capacitor but allows alternating current to pass as it periodically charges and discharges.

Capacitance is determined by the area of the conductors, the distance between them, and the type of dielectric material. The capacitance value plays a crucial role in determining the behavior of an LC circuit, as it affects the circuit's resonant frequency. A higher capacitance typically leads to a lower resonant frequency and vice versa, which is critical to understand when solving the exercise we have at hand.
Inductance
Inductance is the property of an electrical conductor that opposes the change of current flowing through it. It is measured in Henrys (H). An inductor is a coil of wire that generates a magnetic field when current flows through it. The magnetic field can store energy, which can be later released and do work in the circuit.

The value of inductance depends on factors such as the number of turns in the coil, the cross-section of the coil, the core material, and its magnetic permeability. Just as capacitance influences the resonant frequency of an LC circuit, so does inductance. The interaction between the inductors and capacitors in an LC circuit is what makes tuning to specific frequencies possible.
Electrical Resonance
Electrical resonance occurs in an LC circuit when the inductive and capacitive reactances are equal in magnitude but opposite in phase, causing them to cancel each other out. At this point, the impedance of the circuit reaches a minimum, and the circuit naturally oscillates at a particular resonant frequency, which is governed by the formula given in the exercise: \(f = \frac{1}{2\pi\sqrt{LC}}\).

The concept of electrical resonance is critical in designing filters and oscillators in electronic devices. The frequency at which this phenomenon occurs is where the circuit can store and transfer the maximum amount of energy between the capacitor and inductor. Understanding how to manipulate the resonant frequency by altering the capacitance and inductance allows engineers to create circuits tailored for specific applications. In the context of the exercise, this principle allows us to calculate the desired capacitance necessary to reach the target resonant frequency.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) A car generator turns at 400 rpm when the engine is idling. Its 300-turn, 5.00 by 8.00 cm rectangular coil rotates in an adjustable magnetic field so that it can produce sufficient voltage even at low rpms. What is the field strength needed to produce a 24.0 V peak emf? (b) Discuss how this required field strength compares to those available in permanent and electromagnets.

A large power plant generates electricity at 12.0 kV. Its old transformer once converted the voltage to 335 kV. The secondary of this transformer is being replaced so that its output can be 750 kV for more efficient cross-country transmission on upgraded transmission lines. (a) What is the ratio of turns in the new secondary compared with the old secondary? (b) What is the ratio of new current output to old output (at 335 kV) for the same power? (c) If the upgraded transmission lines have the same resistance, what is the ratio of new line power loss to old?

Integrated Concepts A very large, superconducting solenoid such as one used in MRI scans, stores 1.00 MJ of energy in its magnetic field when 100 A flows. (a) Find its self- inductance. (b) If the coils 鈥済o normal,鈥 they gain resistance and start to dissipate thermal energy. What temperature increase is produced if all the stored energy goes into heating the 1000 kg magnet, given its average specific heat is 200 J/kg?潞C?

A powerful induction cannon can be made by placing a metal cylinder inside a solenoid coil. The cylinder is forcefully expelled when solenoid current is turned on rapidly. Use Faraday鈥檚 and Lenz鈥檚 laws to explain how this works. Why might the cylinder get live/hot when the cannon is fired?

(a) Verify that a \(19.0 \%\) decrease in laminar flow through a tube is caused by a \(5.00 \%\) decrease in radius, assuming that all other factors remain constant, as stated in the text. (b) What increase in flow is obtained from a \(5.00 \%\) increase in radius, again assuming all other factors remain constant?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.