/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 A gymnast doing a forward flip l... [FREE SOLUTION] | 91Ó°ÊÓ

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A gymnast doing a forward flip lands on the mat and exerts a \(500-\mathrm{N} \cdot \mathrm{m}\) torque to slow her angular velocity to zero. Her initial angular velocity is \(10.0 \mathrm{rad} / \mathrm{s},\) and her moment of inertia is \(0.050 \mathrm{kg} \cdot \mathrm{m}^{2}\). (a) What time is required for her to exactly stop her spin? (b) What is unreasonable about the result? (c) Which premises are unreasonable or inconsistent?

Short Answer

Expert verified
The time required for the gymnast to exactly stop her spin is found in step 3. Steps 4 and 5 involve evaluating the plausibility of the result and the consistency of the premises, respectively.

Step by step solution

01

Recall the relationship between torque, moment of inertia and angular acceleration

The torque (\tau) exerted on an object is related to the moment of inertia (I) and angular acceleration (\alpha) by the equation \( \tau = I \cdot \alpha \). We will use this formula to find the angular acceleration.
02

Determine the angular acceleration

Since torque and moment of inertia are given, we can rearrange the formula from step 1 to find angular acceleration: \( \alpha = \frac{\tau}{I} \). Substituting the given values, \( \alpha = \frac{500\, \mathrm{N} \cdot \mathrm{m}}{0.050\, \mathrm{kg} \cdot \mathrm{m}^{2}} \). Calculate the value to obtain angular acceleration in \( \mathrm{rad}/\mathrm{s}^2 \).
03

Calculate the angular deceleration time

We can use the following kinematic equation to find the time (t) required to stop: \( \omega_f = \omega_0 + \alpha t \), where \( \omega_f \) is the final angular velocity (0 \( \mathrm{rad}/\mathrm{s} \)), \( \omega_0 \) is the initial angular velocity (10 \( \mathrm{rad}/\mathrm{s} \)), and \( \alpha \) is the angular acceleration. Solve for t to find the time it takes to stop.
04

Evaluate the reasonableness of the result

After calculating the time, assess the reasonableness by considering whether the time value seems physically possible for a gymnast to stop spinning.
05

Identify any unreasonable or inconsistent premises

If the time result from step 3 is found to be unreasonable, scrutinize the given premises (torque, moment of inertia, initial angular velocity) for any values that may be unrealistic or inconsistent with real-world scenarios.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Imagine you're watching a figure skater spin on ice. Angular velocity is a measure of how fast she's rotating, which in physics, we define as the rate of change of angular position over time, typically measured in radians per second (rad/s). It's akin to the linear concept of velocity but adapted for rotational motion. In our gymnast's case, she is initially spinning at an angular velocity of 10.0 rad/s.

Angular velocity doesn't just apply to gymnasts and skaters; it's also crucial in the study of the rotating parts of machinery, the Earth's rotation, and many other natural and man-made phenomena.
Moment of Inertia
The moment of inertia is a bit like 'rotational mass'. Just as mass determines how much force it takes to accelerate an object in linear motion, moment of inertia is a measure of how much torque it takes to change an object's rotational speed. It depends not only on the object's mass but also on how that mass is distributed relative to the axis of rotation. Our gymnast has a moment of inertia of 0.050 kg⋅m², which is quite small, reflecting both her mass and the tight tuck position she's presumably holding to spin.

A large moment of inertia means it's harder to change an object's spinning speed. This concept is why ice skaters pull in their arms to spin faster and extend them to slow down.
Torque
Torque is the rotational equivalent of force. It's a twist or turn that can cause an object to rotate, and its magnitude depends on how much force is applied, as well as the distance from the point of rotation to where the force is applied (the lever arm). Our gymnast exerts a torque of 500 Nâ‹…m to slow down her spin. This forceful action interacts with her moment of inertia, causing her to decelerate.

In many ways, torque is to angular motion as force is to linear motion. It can set objects spinning, stop them, speed them up, or slow them down, depending on how it's applied.
Angular Acceleration
When you push down on the pedals of a bike, you cause it to speed up rotationally; this is because of angular acceleration, the rate at which the angular velocity changes over time, akin to linear acceleration but for rotating systems. In our gymnast's scenario, we talk about angular acceleration in terms of slowing down, or 'angular deceleration'. By exerting torque, the gymnast produces an angular deceleration opposite to her initial rotation direction, effectively reducing her angular velocity until it reaches zero and she comes to a stop.

Knowing her initial angular velocity and the torque applied, we can calculate the angular acceleration necessary to bring her rotation to a halt.
Kinematic Equations
The kinematic equations describe the motion of objects and are divided into those for linear motion and those for rotational motion. Our attention is on the latter, as we use these equations to connect angular velocity, angular acceleration, and time. When the gymnast applies torque to come to a stop, we can use kinematic equations to determine exactly how much time it will take her to halt her spin.

In linear motion, we might relate velocity, acceleration, and time to describe how a car slows down to a stop. Similarly, we can do this with rotational concepts to predict the time it takes for an object to reach a certain angular velocity, given its acceleration or deceleration and the time involved in the motion.

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