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A driven oscillator satisfies the equation $$ \ddot{x}+\Omega^{2} x=F_{0} \cos [\Omega(1+\epsilon) t] $$ where \(\epsilon\) is a positive constant. Show that the solution that satisfies the initial conditions \(x=0\) and \(\dot{x}=0\) when \(t=0\) is $$ x=\frac{F_{0}}{\epsilon\left(1+\frac{1}{2} \epsilon\right) \Omega^{2}} \sin \frac{1}{2} \epsilon \Omega t \sin \Omega\left(1+\frac{1}{2} \epsilon\right) t $$ Sketch the graph of this solution for the case in which \(\epsilon\) is small.

Short Answer

Expert verified
The given function indeed satisfies the differential equation presented in the problem and fulfills the initial conditions. The graph of the solution is sinusoidal with oscillations around zero, especially when \(\epsilon\) is small.

Step by step solution

01

Verify given solution

We are given the solution to the differential equation as \(x=\frac{F_{0}}{\epsilon\left(1+\frac{1}{2} \epsilon\right) \Omega^{2}} \sin \frac{1}{2} \epsilon \Omega t \sin \Omega\left(1+\frac{1}{2} \epsilon\right) t \). Our first step is to verify this solution by substituting it back into our oscillator equation.
02

Check initial conditions

Once we have confirmed that the given solution satisfies the differential equation, we will check the initial conditions. When \(t=0\), we should have \(x=0\), and \(\dot{x}=0\). By substituting the value of \(t=0\) into \(x\) and \(\dot{x}\), we should get the required initial conditions.
03

Graph the solution

The final part of the problem involves graphing the solution. Since \(\epsilon\) is small, the best way to graph this is to look at the solution over a range of oscillator phases (\(\Omega t\)). Considering the sinewave nature of the solution, we should expect oscillations around zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equations
Differential equations are mathematical tools that involve functions and their derivatives. They describe the relationship between a function and its rates of change. Picture a car that accelerates and decelerates; its position can be described by a differential equation involving its velocity (the first derivative of position) and acceleration (the second derivative of position).

In our driven oscillator example, the movement (or position) of the oscillator is described by a second-order differential equation. The term \(\ddot{x}\) represents the acceleration, \(\Omega^{2} x\) corresponds to a restoring force proportional to the position (like the force in a spring), and \(F_{0} \cos [\Omega(1+\epsilon) t]\) is a driving force acting on the oscillator.

Understanding the different terms in the equation is essential to solving it, as each describes a distinctive aspect of the oscillator's motion. The driving force is particularly important, as it's responsible for maintaining the oscillations over time, preventing them from dying out due to resistance or damping effects.
Initial Conditions
Initial conditions are the given values of the function and its derivatives at the beginning of the period of interest; they represent where and how the system starts. To fully solve a differential equation, we need both the general form of the equation and the initial conditions.

In our oscillator problem, the initial conditions are that at time \(t=0\), the position \(x\) is 0 and the velocity \(\dot{x}\) is also 0. These conditions provide the starting point for the system and allow us to solve for constants that may be present in the general solution.

Applying initial conditions to the general solution refines it to a particular solution that pertains exactly to the scenario at hand. This step ensures that we're not just looking at any possible behavior of the system but the one that occurs under the specific circumstances given.
Oscillator Phases
The oscillator phase is a concept that helps in understanding the position of the oscillator in its cycle at a given time. It is represented mathematically by the argument of the sinusoidal function—in our case, \(\Omega t\) and \(\Omega(1+\frac{1}{2} \epsilon)t\).

The phase tells us how far along the oscillator is in its cycle, which is important when predicting its future positions or velocities. It's determined by both the angular frequency \(\Omega\) and the time \(t\), as well as any phase shift introduced by the driving force.

Small changes in the phase, due to the \(\epsilon\) in our equation, have significant effects on the behavior of the oscillator. It affects how in-phase or out-of-phase the oscillator is with its driving force, which can result in different patterns of movement such as resonance or beating.
Sinewave Solutions
Sinewave solutions are common outcomes for differential equations that model oscillatory systems, like springs, pendulums, and electrical circuits. They reflect the periodic nature of these systems. In the solution for our driven oscillator equation,\r\begin{equation*}\r x=\frac{F_{0}}{\epsilon\left(1+\frac{1}{2} \epsilon\right) \Omega^{2}} \sin\r \frac{1}{2} \epsilon \Omega t \sin \Omega\left(1+\frac{1}{2} \epsilon\right) t\r\r\rend{equation*}\, the presence of sine functions indicates that the oscillator behaves in a periodic manner.

When \(\epsilon\) is small, as stated in the exercise, the impact of the driving force's frequency on the oscillator's frequency is subtle, manifesting as a slight wobble or modulation in the otherwise smooth sinusoidal motion. The graph of this motion will have a waveform with beats—where the amplitude of the wave periodically increases and decreases, giving insights into the complex interactions between the driving force and the natural oscillations of the system.

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Most popular questions from this chapter

The oscillations of a galvanometer satisfy the equation $$ \ddot{x}+2 K \dot{x}+\Omega^{2} x=0 $$ The galvanometer is released from rest with \(x=a\) and we wish to bring the reading permanently within the interval \(-\epsilon a \leq x \leq \epsilon a\) as quickly as possible, where \(\epsilon\) is a small positive constant. What value of \(K\) should be chosen? One possibility is to choose a sub-critical value of \(K\) such that the first minimum point of \(x(t)\) occurs when \(x=-\epsilon a\). [Sketch the graph of \(x(t)\) in this case.] Show that this can be acheived by setting the value of \(K\) to be $$ K=\Omega\left[1+\left(\frac{\pi}{\ln (1 / \epsilon)}\right)^{2}\right]^{-1 / 2} $$ If \(K\) has this value, show that the time taken for \(x\) to reach its first minimum is approximately \(\Omega^{-1} \ln (1 / \epsilon)\) when \(\epsilon\) is small.

Find the general solution of the damped SHM equation (5.9) for the special case of critical damping, that is, when \(K=\Omega\). Show that, if the particle is initially released from rest at \(x=a\), then the subsequent motion is given by $$ x=a e^{-\Omega t}(1+\Omega t) $$ Sketch the graph of \(x\) against \(t\).

A particle of mass \(m\) is connected to a fixed point \(O\) on a smooth horizontal table by a linear elastic string of natural length \(2 a\) and strength \(m \Omega^{2}\). Initially the particle is released from rest at a point on the table whose distance from \(O\) is \(3 a\). Find the period of the resulting oscillations.

A particle \(P\) of mass \(3 m\) is suspended fron a fixed point \(O\) by a light linear spring with strength \(\alpha .\) A second particle \(Q\) of mass \(2 m\) is in turn suspended from \(P\) by a second spring of the same strength. The system moves in the vertical straight line through \(O\). Find the normal frequencies and the form of the normal modes for this system. Write down the form of the general motion.

A particle of mass \(m\) moves along the \(x\)-axis and is acted upon by the restoring force \(-m\left(n^{2}+k^{2}\right) x\) and the resistance force \(-2 m k \dot{x}\), where \(n, k\) are positive constants. If the particle is released from rest at \(x=a\), show that, in the subsequent motion, $$ x=\frac{a}{n} e^{-k t}(n \cos n t+k \sin n t) $$ Find how far the particle travels before it next comes to rest.

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