/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 A projectile is fired from the t... [FREE SOLUTION] | 91Ó°ÊÓ

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A projectile is fired from the top of a conical mound of height \(h\) and base radius \(a\). What is the least projection speed that will allow the projectile to clear the mound? [Hint. Make use of the parabola of safety.] A mortar gun is placed on the summit of a conical hill of height \(60 \mathrm{~m}\) and base diameter \(160 \mathrm{~m}\). If the gun has a muzzle speed of \(25 \mathrm{~m} \mathrm{~s}^{-1}\), can it shell anywhere on the hill? [Take \(\left.g=10 \mathrm{~m} \mathrm{~s}^{-2} .\right]\)

Short Answer

Expert verified
The muzzle speed of the gun needs to be greater than the calculated speed \(v\) for the gun to shell anywhere on the hill.

Step by step solution

01

Calculating the Hill's Angular Slope

The angle \(\alpha\) of the hill can be found using trigonometric principles. The tangent of \(\alpha\) is equal to the hill's height \(h\) divided by the hill's radius \(a\). So, \(\alpha = \tan^{-1}(\frac{h}{a})\) . Substitute \(h = 60\) m and \(a = \frac{160}{2} = 80\) m and solve for \(\alpha\).
02

Determine Safe Projectile Speed

The smallest speed \(v\) necessary for the projectile to clear the hill is found by using the equation \(v = \sqrt{g*h} / \sin{(\alpha)}\), where \(g = 10\) m/s² is the gravity force and \(\alpha\) is the angle found in Step 1. Solve for \(v\).
03

Compare Speeds

Compare the calculated speed \(v\) with the muzzle speed of the gun, which is \(25\) m/s. If \(v\) is less than the muzzle speed, then the gun can shell anywhere on the hill. If not, then the gun cannot shell everywhere.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parabola of Safety
When a projectile is fired at an angle, it follows a path known as a parabolic trajectory. The term 'parabola of safety' derives from the concept that there is a particular curved path a projectile can take that will just avoid colliding with an object—like a conical hill—in its trajectory. To guarantee the projectile clears the mound, the minimum projection speed must be calculated taking this curve into account.

Imagine the conical mound as an obstacle that our projectile needs to fly over. The apex of the parabola—the highest point of the projectile's route—must sit above the summit of the mound. This ensures a 'safety' parabola where the projectile avoids the obstacle. In more mathematical terms, we consider the mound's shape and calculate the tangent angle at its peak, then use that angle to determine the minimum initial velocity required to clear the hill without contact.
Trigonometry in Projectile Motion
The use of trigonometry is crucial when analyzing projectile motion around obstructions like hills or mounds. The angle of projection, often represented by \(\alpha\), is particularly important as it influences the distance and height a projectile can travel.

The angular slope of a hill, which is a key factor in determining the parabolic trajectory needed to clear it, can be found using basic trigonometric principles. In the exercise, \(\tan\alpha\) is equal to the height (\(h\)) divided by the radius (\(a\)) of the hill. Knowing this, we can calculate the angle \(\alpha\) using the inverse tangent function: \(\alpha = \tan^{-1}(\frac{h}{a})\). This angle helps us define the minimum angle of projection required for a successful clearance of the hill.
Calculating Projectile Speed
Determining the minimum speed necessary for a projectile to clear an obstacle is pivotal for not only theoretical calculations but also in practical applications such as artillery operations. The formula for the smallest speed \(v\) that will ensure the projectile clears the mound is derived from the equation \(v = \sqrt{g*h} / \sin{(\alpha)}\), where \(g\) stands for the acceleration due to gravity. It cleverly intertwines the basic principles of kinematics and trigonometry.

In the context of the exercise, once the angle of the hill \(\alpha\) is identified, we can plug the known values into the equation to find the safe projectile speed. The muzzle speed of the projectile is then compared to this minimum speed. If the actual speed of the projectile is greater, the projectile will overcome the obstacle; if it is lesser, adjustments to the projectile's speed or angle would be needed for successful clearance.

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Most popular questions from this chapter

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