Consider the soap film problem for which it is required to minimise
$$
J[y]=\int_{-a}^{a} y\left(1+\dot{y}^{2}\right)^{\frac{1}{2}} d x
$$
with \(y(-a)=y(a)=b\). Show that the extremals of \(J\) have the form
$$
y=c \cosh \left(\frac{x}{c}+d\right)
$$
where \(c, d\) are constants, and that the end conditions are satisfied if (and
only if) \(d=0\) and
$$
\cosh \lambda=\left(\frac{b}{a}\right) \lambda
$$
where \(\lambda=a / c\). Show that there are two admissible extremals provided
that the aspect ratio \(b / a\) exceeds a certain critical value and none if \(b
/ a\) is less than this crirical value. Sketch a graph showing how this
critical value is determined.
The remainder of this question requires computer assistance. Show that the
critical value of the aspect ratio \(b / a\) is about \(1.51\). Choose a value of
\(b / a\) larger than the critical value (b \(/ a=2\) is suitable) and find the
two values of \(\lambda\). Plot the two admissible extremals on the same graph.
Which one looks like the actual shape of the soap film? Check your guess by
perturbing each extremal by small admissible variations and finding the change
in the value of the functional \(J[y]\).