/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 An axially symmetric space stati... [FREE SOLUTION] | 91Ó°ÊÓ

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An axially symmetric space station (principal axis \(\mathbf{e}_{3},\) and \(\lambda_{1}=\lambda_{2}\) ) is floating in free space. It has rockets mounted symmetrically on either side that are firing and exert a constant torque \(\Gamma\) about the symmetry axis. Solve Euler's equations exactly for \(\omega\) (relative to the body axis) and describe the motion. At \(t=0\) take \(\omega=\left(\omega_{10}, 0, \omega_{30}\right)\)

Short Answer

Expert verified
\(\omega_1(t) = \omega_{10}\), \(\omega_2(t) = 0\), \(\omega_3(t) = \frac{\Gamma t}{\text{I}_3} + \omega_{30}\).

Step by step solution

01

Identify the Given Information

We have an axially symmetric space station with symmetrical axes and a constant torque around the symmetry axis. The Euler's equations for rotational motion under axial symmetry are given by:1. \( rac{d}{dt}( ext{I}_1 \omega_1) - ext{I}_2 \omega_2 \omega_3 = 0 \)2. \( rac{d}{dt}( ext{I}_2 \omega_2) - ext{I}_1 \omega_1 \omega_3 = 0 \)3. \( rac{d}{dt}( ext{I}_3 \omega_3) = \Gamma \)Where \( \text{I}_1 = \text{I}_2 \) because the body is symmetric, and \( \Gamma \) is the torque applied about the symmetry axis \( \mathbf{e}_3 \). Initial conditions are \( \omega = (\omega_{10}, 0, \omega_{30}) \) at \( t=0 \).
02

Solve for \(\omega_1(t)\) and \(\omega_2(t)\)

From the Euler equations: \[ \frac{d}{dt}( ext{I}_1 \omega_1) = \text{I}_2 \omega_2 \omega_3 \] Given \( \omega_2 \) is initially zero, and remains zero, as there is no initial angular velocity nor torque in this direction due to symmetry. Thus, \( \omega_1(t) = \omega_{10} \) remains constant because there's no component of torque or angular velocity creating a change in \( \omega_1 \) without \( \omega_2 \).
03

Solve for \(\omega_3(t)\) Using Torque

From the third Euler equation: \( \frac{d}{dt}( ext{I}_3 \omega_3) = \Gamma \)Integrating with respect to time gives:\( \text{I}_3 \omega_3(t) = \Gamma t + C \)To find \( C \), use the initial condition \( \omega_3(0) = \omega_{30} \):\( C = \text{I}_3 \omega_{30} \).Thus, \( \omega_3(t) = \frac{\Gamma t}{\text{I}_3} + \omega_{30} \).
04

Describe the Motion

The angular velocity \( \omega \) about the body axis changes over time: \( \omega_1 \) remains constant at \( \omega_{10} \), \( \omega_2 \) stays at 0, and \( \omega_3 \) increases linearly with time due to the constant torque exerted on the symmetric axis. Therefore, the space station spins faster around its symmetry axis \( \mathbf{e}_3 \) as time progresses, while maintaining a steady spin around \( \mathbf{e}_1 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rotational Motion
Rotational motion refers to the movement of an object around a central axis. For the axially symmetric space station in our problem, it is influenced by the forces applied through the rockets, causing it to spin. In rotational motion, several key parameters come into play, such as angular velocity and torque. These help in understanding how the station moves and changes its position over time.
The principal axes are crucial in rotational motion as they define how the object spins. An object is in pure rotational motion if every particle of the object has a circular path around a fixed axis. The space station, being axially symmetric, maintains this circular uniformity, keeping certain rotational attributes constant while allowing others to change under external influence.
Euler's equations are particularly helpful in analyzing rotational motion. They describe how the axes' inertias (moments of inertia) relate to the angular velocities and any external torques applied. In a nutshell, rotational motion for the space station spins around these principles, maintaining equilibrium while reacting to applied forces.
Angular Velocity
Angular velocity, denoted as \omega\, is the rate at which an object rotates around an axis. In the context of the space station, the angular velocity determines how quickly it spins about its principal axes. It is expressed in terms of its components: \( \omega_1, \omega_2, \) and \( \omega_3 \) which correspond to rotations about each of the principal axes.
Understanding angular velocity is vital because it encapsulates the rotational state of the space station. For instance, in the given exercise, \( \omega_1 \) starts at a constant value \( \omega_{10} \), and \( \omega_3 \) shows linear growth over time due to the applied torque. These behaviors of \( \omega \) align with the rules set by Euler's equations, highlighting the dynamics of angular motion.
The constancy in \( \omega_1 \) indicates that there is no net external influence causing it to change, echoing the symmetrical nature of the station. Contrastively, \( \omega_3 \)'s linear increase is directly tied to the exerted torque \( \Gamma \) about the symmetry axis, illustrating how external forces manipulate angular velocity over time.
Axial Symmetry
Axial symmetry occurs when the physical properties of a structure, like the space station, are symmetrical about a particular axis. Here, the axis of symmetry is \( \mathbf{e}_3 \). This symmetry simplifies the analysis of rotational dynamics because it implies that the moments of inertia about two of the principal axes are equal (\( \lambda_1 = \lambda_2 \)).
Due to axial symmetry, the torque applied affects only the symmetry axis in this model, maintaining uniformity about the other axes. The symmetry causes \( \omega_2 \) to remain zero, emphasizing no change or rotation occurs about the secondary axis without initial conditions or external influence in that direction.
Axial symmetry streamlines the application of Euler's equations by reducing the complexity, allowing for straightforward solutions where certain components remain unchanged, while others alter predictably. Such symmetry hence plays a crucial role in simplifying and solving problems involving rotational dynamics, as it allows external forces to have a more predictable impact on the object.

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Most popular questions from this chapter

A thin rod (of width zero, but not necessarily uniform) is pivoted freely at one end about the horizontal \(z\) axis, being free to swing in the \(x y\) plane ( \(x\) horizontal, \(y\) vertically down). Its mass is \(m,\) its \(\mathrm{CM}\) is a distance \(a\) from the pivot, and its moment of inertia (about the \(z\) axis) is \(I\). (a) Write down the equation of motion \(\dot{L}_{z}=\Gamma_{z}\) and, assuming the motion is confined to small angles (measured from the downward vertical), find the period of this compound pendulum. ("Compound pendulum" is traditionally used to mean any pendulum whose mass is distributed \(-\) as contrasted with a "simple pendulum," whose mass is concentrated at a single point on a massless arm.) (b) What is the length of the "equivalent" simple pendulum, that is, the simple pendulum with the same period?

Suppose that you have found three independent principal axes (directions \(\mathbf{e}_{1}, \mathbf{e}_{2}, \mathbf{e}_{3}\) ) and corresponding principal moments \(\lambda_{1}, \lambda_{2}, \lambda_{3}\) of a rigid body whose moment of inertia tensor \(\mathbf{I}\) (not diagonal) you had calculated. (You may assume, what is actually fairly easy to prove, that all of the quantities concerned are real.) (a) Prove that if \(\lambda_{i} \neq \lambda_{j}\) then it is automatically the case that \(\mathbf{e}_{i} \cdot \mathbf{e}_{j}=0\) (It may help to introduce a notation that distinguishes between vectors and matrices. For example, you could use an underline to indicate a matrix, so that \(\underline{\mathbf{a}}\) is the \(3 \times 1\) matrix that represents the vector a, and the vector scalar product a \(\cdot \mathbf{b}\) is the same as the matrix product \(\tilde{\mathbf{a}} \mathbf{b}\) or \(\underline{\mathbf{b}}\) a. Then consider the number \(\tilde{\mathbf{e}}_{i} \mathbf{I} \mathbf{e}_{j},\) which can be evaluated in two ways using the fact that both \(\mathbf{e}_{i}\) and \(\mathbf{e}_{j}\) are eigenvectors of I.) (b) Use the result of part (a) to show that if the three principal moments are all different, then the directions of three principal axes are uniquely determined. (c) Prove that if two of the principal moments are equal, \(\lambda_{1}=\lambda_{2}\) say, then any direction in the plane of \(\mathbf{e}_{1}\) and \(\mathbf{e}_{2}\) is also a principal axis with the same principal moment. In other words, when \(\lambda_{1}=\lambda_{2}\) the corresponding principal axes are not uniquely determined. (d) Prove that if all three principal moments are equal, then any axis is a principal axis with the same principal moment.

A triangular prism (like a box of Toblerone) of mass \(M,\) whose two ends are equilateral triangles parallel to the \(x y\) plane with side \(2 a,\) is centered on the origin with its axis along the \(z\) axis. Find its moment of inertia for rotation about the \(z\) axis. Without doing any integrals write down and explain its two products of inertia for rotation about the \(z\) axis.

A thin, flat, uniform metal triangle lies in the \(x y\) plane with its corners at \((1,0,0),(0,1,0),\) and the origin. Its surface density (mass/area) is \(\sigma=24\). (Distances and masses are measured in unspecified units, and the number 24 was chosen to make the answer come out nicely.) (a) Find the triangle's inertia tensor I. (b) What are its principal moments and the corresponding axes?

A rigid body consists of three equal masses \((m)\) fastened at the positions \((a, 0,0),(0, a, 2 a)\) and \((0,2 a, a) .\) (a) Find the inertia tensor \(\mathbf{I}\). (b) Find the principal moments and a set of orthogonal principal axes.

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