Chapter 10: Problem 12
A particle moves vertically in a uniform gravitational field \(g\), the Lagrangian being \(L=\frac{1}{2} \dot{z}^{2}-g z\). Construct the momentum space Lagrangian \(K(p, \dot{p})\). (Hint: Add a total time derivative such as \(\frac{1}{2} d / d t\left(\lambda z^{2}\right)=\lambda z z\) to the Lagrangian.)
Short Answer
Step by step solution
Identify the Original Lagrangian
Calculate the Conjugate Momentum
Solve for Velocity in Terms of Momentum
Substitute Velocity in the Lagrangian
Modify the Lagrangian with Total Time Derivative
Construct the Momentum Space Lagrangian
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Conjugate Momentum
- The conjugate momentum \( p \) is calculated as the partial derivative of the Lagrangian \( L \) with respect to the velocity \( \dot{z} \).
- For the Lagrangian \( L = \frac{1}{2} \dot{z}^{2} - g z \), the conjugate momentum is \( p = \dot{z} \).
Legendre Transformation
- We transform the original Lagrangian \( L \) to the momentum space Lagrangian \( K \).
- The process involves using this formula: \( K = p \dot{z} - L' \), where \( L' \) is the modified Lagrangian that includes a total time derivative.
Gravitational Field
- The gravitational force is a constant downward force, affecting the potential energy represented by \( -g z \).
- The inclusion of this gravitational term directly impacts the particle's kinetic and potential energy.