Chapter 6: Problem 67
On a hot sunny day the corrugated iron roof of a work shed is measured to be \(50^{\circ} \mathrm{C}\) when the ambient air is at \(30^{\circ} \mathrm{C}\) and \(80 \%\) relative humidity. Calculate the heat flux into the shed if \(h_{c}\) for the roof is estimated to be \(20 \mathrm{~W} / \mathrm{m}^{2} \mathrm{~K}\). Take \(\varepsilon=0.6, \alpha_{3}=0.8\) for the iron, a shape factor from the roof to the sky of unity, and a solar irradiation of \(900 \mathrm{~W} / \mathrm{m}^{2}\).
Short Answer
Step by step solution
Heat Transfer due to Convection
Radiative Heat Transfer
Solar Heat Gain
Total Heat Flux
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Convection
- \( Q_{c} = h_{c} \times (T_{roof} - T_{air}) \)
Radiation
- \( Q_{r} = \varepsilon \sigma (T_{roof}^4 - T_{sky}^4) \)
- \(\varepsilon\) is the emissivity of the surface, a measure of how effectively the surface emits energy as thermal radiation. For the iron roof, \(\varepsilon = 0.6\).
- \(\sigma\) is the Stefan–Boltzmann constant \(5.67 \times 10^{-8} \, \text{W/m}^{2}\text{K}^{4}\).
- \(T_{roof}\) and \(T_{sky}\) are the absolute temperatures (in Kelvin) of the roof and the sky, respectively.
Heat Flux
- Convective heat transfer, \(Q_{c}\), calculated based on the temperature difference between the roof and the surrounding air.
- Radiative heat transfer, \(Q_{r}\), determined by the emissive properties of the roof and its temperature difference with the sky.
- Solar heat gain, \(Q_{solar}\), acknowledged from direct solar irradiation absorption.
Solar Irradiation
- \( Q_{solar} = \alpha_{3}\times G \)
- \(\alpha_{3}\) is the absorptivity of the roof, with a given value of \(0.8\). This indicates the proportion of solar energy absorbed by the roof surface.
- \(G\) represents the solar irradiation strength, at \(900 \, \text{W/m}^2\).