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Liquid metals are attractive for high-temperature heat transfer applications owing to their characteristic high convective heat transfer coefficients. Liquid potassium flows at \(4 \mathrm{~m} / \mathrm{s}\) in a long, \(2 \mathrm{~cm}\)-I.D. tube. Calculate the Nusselt number and heat transfer coefficient (i) for a uniform wall temperature. (ii) for a uniform wall heat flux. Evaluate properties at \(900 \mathrm{~K}\). Repeat for liquid sodium.

Short Answer

Expert verified
Use the given formulas and appropriate fluid properties to calculate the Nusselt numbers and heat transfer coefficients for liquid potassium and sodium at 900 K, in both uniform wall temperature and heat flux conditions.

Step by step solution

01

Identify Known Information

We are given the following:- Flow velocity: \( u = 4\, \text{m/s} \)- Tube inner diameter: \( D = 0.02\, \text{m} \)- Temperature: \( T = 900\, \text{K} \). We need to find the Nusselt number and heat transfer coefficient for liquid potassium and later for liquid sodium at this temperature.
02

Obtain Physical Properties

Look up the properties of liquid potassium and liquid sodium at \( 900 \, \text{K} \), including:- Thermal conductivity \( k \)- Prandtl number \( \text{Pr} \)- Dynamic viscosity \( \mu \)- Density \( \rho \)
03

Define Reynolds Number Formula

The Reynolds number \( \text{Re} \) is given by the formula \( \text{Re} = \frac{\rho u D}{\mu} \). Calculate \( \text{Re} \) for both potassium and sodium using their respective properties at \( 900 \, \text{K} \).
04

Calculate Nusselt Number for Uniform Wall Temperature

For a uniform wall temperature, use the Gnielinski correlation for turbulent flow: \[ \text{Nu} = \frac{(\text{f}/8) (\text{Re} - 1000) \text{Pr}}{1 + 12.7 (\text{f}/8)^{1/2} (\text{Pr}^{2/3} - 1)} \] where \( \text{f} \) is the Darcy friction factor, which can be estimated by \( \text{f} = (0.79 \ln(\text{Re}) - 1.64)^{-2} \). Use this formula to calculate the Nusselt number for both potassium and sodium.
05

Calculate Nusselt Number for Uniform Wall Heat Flux

For a uniform heat flux, consider using the Dittus-Boelter equation: \[ \text{Nu} = 0.023 \times \text{Re}^{0.8} \times \text{Pr}^{0.3} \] for heating or \( \text{Pr}^{0.4} \) for cooling. Since we're considering high-temperature applications, use \( \text{Pr}^{0.3} \). Calculate \( \text{Nu} \) for both potassium and sodium.
06

Calculate Heat Transfer Coefficient

The heat transfer coefficient \( h \) can be found using the relation:\[ h = \frac{\text{Nu} \times k}{D} \] Use this formula to calculate \( h \) for both the uniform wall temperature and uniform wall heat flux cases, and for both potassium and sodium.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nusselt Number
In heat transfer, the Nusselt number is a dimensionless value used to characterize convective heat transfer. It is essentially the ratio of convective to conductive heat transfer across a boundary, such as the walls of a tube. The Nusselt number provides insight into how effectively a fluid, like liquid potassium or liquid sodium, can transfer heat during flow. A higher Nusselt number indicates more efficient convective heat transfer.

For a uniform wall temperature, the Gnielinski correlation is often used in calculating the Nusselt number, particularly in turbulent flow conditions. This correlation accounts for factors such as the friction factor and the Reynolds and Prandtl numbers, which are fluid property dependent.
  • The formula for the Nusselt number in this scenario is: \( \text{Nu} = \frac{(\text{f}/8) (\text{Re} - 1000) \text{Pr}}{1 + 12.7 (\text{f}/8)^{1/2} (\text{Pr}^{2/3} - 1)} \).
  • The Darcy friction factor (\( \text{f} \)) and other properties like Prandtl number also play crucial roles here.

For a scenario with uniform wall heat flux, the Dittus-Boelter equation is employed, slightly altering the exponent of the Prandtl number, tailored for heating conditions. Understanding the Nusselt number is vital for optimizing the design of heat exchangers and understanding the behavior of fluids in heat transfer applications.
Reynolds Number
The Reynolds number is a key concept in fluid dynamics and heat transfer. It is a dimensionless number used to predict flow patterns in different fluid flow situations. The Reynolds number is determined by the ratio of inertial forces to viscous forces within a fluid and is given by the formula: \( \text{Re} = \frac{\rho u D}{\mu} \), where \( \rho \) is the fluid density, \( u \) is the flow velocity, \( D \) is the characteristic length (like the diameter of a tube), and \( \mu \) is the dynamic viscosity of the fluid.

In simpler terms, the Reynolds number tells us whether a fluid is flowing in a laminar (smooth) or turbulent (chaotic) pattern. A lower Reynolds number indicates laminar flow, while a higher number signifies turbulent flow. For liquid metals like potassium and sodium flowing at high temperatures, the Reynolds number helps us understand how aggressive or smooth the flow will be inside a tube.
  • Influences the choice of formula for calculating the Nusselt number, such as using the Gnielinski correlation for turbulent flow.
  • Aids in determining the friction factor for flow calculations, a critical aspect in accurately measuring the heat transfer.

The Reynolds number is essential for designing and analyzing systems where fluid flow is a component, ensuring processes like heat transfer are efficient and effective.
Thermal Conductivity
Thermal conductivity is a physical property that measures a material's ability to conduct heat. It plays a vital role in the context of heat transfer, especially in applications involving liquid metals due to their high thermal conductivity.

Liquid metals like potassium and sodium are excellent conductors of heat compared to other fluids. This high thermal conductivity enables them to quickly and efficiently transfer heat through conduction, making them suitable for use in high-temperature applications like advanced cooling systems and heat exchangers.
  • Key for calculating the heat transfer coefficient, \( h \), in the relationship: \( h = \frac{\text{Nu} \times k}{D} \).
  • A higher thermal conductivity means that the metal can more effectively manage heat transfer in systems.

Understanding the thermal conductivity of liquid metals helps in choosing appropriate cooling or heating fluids, leading to enhanced performance in industrial applications. It's a critical factor in designing engineering systems that require precise thermal management.
Liquid Metals
Liquid metals, such as potassium and sodium, are widely used in heat transfer applications due to their unique properties. One of the primary reasons for their use is their high thermal conductivity, which allows for efficient heat transfer.

Liquid metals remain in a liquid state over a broad range of temperatures, making them suitable for high-temperature operations that are common in nuclear reactors and various industrial processes. Their ability to flow and transfer heat quickly means they can maintain system temperatures more evenly compared to other fluids.
  • High convective heat transfer coefficients make them ideal for applications where rapid heat dissipation is required.
  • Act as effective coolants in environments where conventional fluids, such as water or air, would not suffice.

Understanding the behavior of liquid metals in different thermal environments allows engineers to design advanced systems for heat management and energy conversion. Liquid metals' distinct properties make them indispensable in fields requiring reliable and efficient heat transfer solutions.

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Most popular questions from this chapter

A small submarine is to be as silent as possible. A proposed design requires the use of a thermoelectric generator rejecting heat directly to the hull, thus eliminating cooling water pumping machinery. An area \(10 \mathrm{~m}\) wide and \(10 \mathrm{~m}\) long at the bow is available for heat rejection. If the submarine cruises at \(4 \mathrm{~m} / \mathrm{s}\) and must reject \(15 \mathrm{MW}\) to \(15^{\circ} \mathrm{C}\) water, estimate the average temperature of the heat rejection surface.

To estimate the effect of surface roughness on the skin drag of a high-speed underwater vehicle, model the vehicle as a flat plate \(2.5 \mathrm{~m}\) long traveling at 70 \(\mathrm{km} / \mathrm{h}\). What is the percentage increase in skin drag over the smooth-wall value if the equivalent sand grain roughness of the surface is \(0.25 \mathrm{~mm}\) ? Assume a sea temperature of \(300 \mathrm{~K}\).

Consider flow along a flat plate. For free-stream velocities in the range \(0.1-100\) \(\mathrm{m} / \mathrm{s}\) determine the average heat transfer coefficient and drag force per unit width on a \(1 \mathrm{~m}\) length of plate for (i) air at \(1 \mathrm{~atm}\). (ii) air at \(0.01 \mathrm{~atm}\). Use a transition Reynolds number of \(10^{5}\), and evaluate properties at \(295 \mathrm{~K}\).

A \(95 \mathrm{~mm}\)-high Styrofoam cup has \(1.5 \mathrm{~mm}\)-thick walls, and its outside diameter varies from \(77 \mathrm{~mm}\) at the top to \(43 \mathrm{~mm}\) at the base. It is filled with \(200 \mathrm{ml}\) of coffee at \(80^{\circ} \mathrm{C}\), sealed with a \(0.5 \mathrm{~mm}\)-thick plastic lid, and placed on a wooden table. If the ambient air is \(24^{\circ} \mathrm{C}\) and 1000 mbar, estimate the time for coffee to cool to \(60^{\circ} \mathrm{C}\). Take \(k=0.033 \mathrm{~W} / \mathrm{m} \mathrm{K}\) and \(0.33 \mathrm{~W} / \mathrm{m} \mathrm{K}\) for the Styrofoam and plastic lid, respectively, and \(\varepsilon=0.85\) for both. Make reasonable assumptions but discuss their validity.

A thermistor is to be used to measure the temperature of a 1 atm-pressure superheated steam flow in a large pipe. Nominal conditions are a steam velocity of \(5 \mathrm{~m} / \mathrm{s}\), a thermistor bead in the form of a \(3 \mathrm{~mm}\)-diameter sphere, and a pipe wall at \(500 \mathrm{~K}\). If the thermistor reads \(526.6 \mathrm{~K}\), what is the true steam temperature? The emittance of the thermistor bead is \(0.8\), and conduction along the thermistor leads is negligible.

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